Show that the first three terms, in descending powers of xxx, of the expansion of
(3x−2)8 (3x - 2)^8 (3x−2)8are given by
6561x8+ax7+bx6 6561x^8 + ax^7 + bx^6 6561x8+ax7+bx6where aaa and bbb are integers to be found.
Find the constant term in the expansion of
(3x−2x)8 \left(3x - \frac{2}{x}\right)^8 (3x−x2)8