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Question 26
35%

Use the substitution u=1+2cos⁡xu = 1 + 2\cos xu=1+2cosx to find ∫0π2sin⁡x1+2cos⁡xdx\displaystyle \int_0^{\frac{\pi}{2}} \frac{\sin x}{1 + 2\cos x} dx∫02π​​1+2cosxsinx​dx

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Integration Questions

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