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1.4.1 Structure and methods of proof

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Question 71

A reliability engineer is modeling the probability p p\,p of a component failing under extreme stress, where the probability is constrained by the open interval 0.2<p<0.30.2 < p < 0.30.2<p<0.3.

a.

The engineer suggests that 0.3 is the maximum possible value for p p\,p within this range. Explain the error in this claim.

[1]
bi.

To demonstrate that no maximum value exists in this interval, the engineer proposes the following proof by contradiction:

Step 1: Assume there exists a maximum value M M\,M within the interval 0.2<p<0.30.2 < p < 0.30.2<p<0.3.

Step 2: Let q=M+0.32\displaystyle q = \frac{M + 0.3}{2}q=2M+0.3​.

Step 3: M<q<0.3M < q < 0.3M<q<0.3, which is a contradiction.

Step 4: Therefore, no maximum value exists in the interval 0.2<p<0.30.2 < p < 0.30.2<p<0.3.

Explain the contradiction stated in Step 3.

[1]
bii.

Use a similar proof by contradiction to prove that no minimum value exists in the interval 0.2<p<0.30.2 < p < 0.30.2<p<0.3.

[3]

1.4.1 Structure and methods of proof Questions

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