A particle P P\,P moves with constant acceleration (2i−3j)(2\mathbf{i} - 3\mathbf{j})(2i−3j) m s−2^{-2}−2. At time t=0t = 0t=0, P P\,P is at the origin O O\,O and is moving with velocity (2i−2j)(2\mathbf{i} - 2\mathbf{j})(2i−2j) m s−1^{-1}−1.
Find the speed of P P\,P at time t=2t = 2t=2 s.
Show that the position vector of P P\,P at time t=2t = 2t=2 s is (8i−10j)(8\mathbf{i} - 10\mathbf{j})(8i−10j) m.
265 exam-style questions on AQA A Level Maths 3.2 Q: Kinematics, covering 3.2.1 Language of kinematics, 3.2.2 Graphs in kinematics, 3.2.3 Constant acceleration formulae, 3.2.4 Calculus in kinematics (A-level only), and 3.2.5 Motion under gravity and projectiles (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.