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3.2 Q: Kinematics

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Question 18

At time t t\,t seconds a particle has velocity v=4ti−3j\mathbf{v} = 4t\mathbf{i} - 3\mathbf{j}v=4ti−3j m s−1^{-1}−1.

Find the acceleration of the particle when t=2t = 2t=2.

Circle your answer.

A

4i4\mathbf{i}4i m s−2^{-2}−2

B

8i8\mathbf{i}8i m s−2^{-2}−2

C

4i−3j4\mathbf{i} - 3\mathbf{j}4i−3j m s−2^{-2}−2

D

8i−3j8\mathbf{i} - 3\mathbf{j}8i−3j m s−2^{-2}−2

Markscheme

3.2 Q: Kinematics Questions

  1. A Level
  2. /Maths
  3. /3.2 Q: Kinematics

265 exam-style questions on AQA A Level Maths 3.2 Q: Kinematics, covering 3.2.1 Language of kinematics, 3.2.2 Graphs in kinematics, 3.2.3 Constant acceleration formulae, 3.2.4 Calculus in kinematics (A-level only), and 3.2.5 Motion under gravity and projectiles (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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