The curve $C\,$ has the equation

$2\tan 2y$ , where $−π4<y<π4\displaystyle -\frac{\pi}{4} < y < \frac{\pi}{4}$

You may use the result $ddu(tan⁡ku)=ksec⁡2ku\dfrac{d}{du}(\tan ku) = k\sec^2 ku$ .

Show that, for all points $(x, y)$ lying on $C$ ,

$dydx=ax2+b\displaystyle \frac{dy}{dx} = \frac{a}{x^2 + b}$

where $a\,$ and $b\,$ are constants to be found.

The curve $C\,$ has the equation

$2\tan 2y$ , where $−π4<y<π4\displaystyle -\frac{\pi}{4} < y < \frac{\pi}{4}$

You may use the result $ddu(tan⁡ku)=ksec⁡2ku\dfrac{d}{du}(\tan ku) = k\sec^2 ku$ .

Show that, for all points $(x, y)$ lying on $C$ ,

$dydx=ax2+b\displaystyle \frac{dy}{dx} = \frac{a}{x^2 + b}$

where $a\,$ and $b\,$ are constants to be found.

1 Pure Mathematics

1 Pure Mathematics Questions