It is given that
f(x)=ln(2x+1)+x2−5f(x) = \ln(2x + 1) + x^2 - 5f(x)=ln(2x+1)+x2−5, x>−0.5x > -0.5x>−0.5
Show that f(x)=0f(x) = 0f(x)=0 has a root in the interval [1.8,1.9][1.8, 1.9][1.8,1.9].
Find f′(x)f'(x)f′(x).