The first three terms of a geometric series are (3k+3)(3k+3)(3k+3), (k+3)(k+3)(k+3), and k k\,k respectively, where k k\,k is a positive constant.
Show that 2k2−3k−9=02k^2 - 3k - 9 = 02k2−3k−9=0.
Hence show that k=3k = 3k=3.
Find the common ratio.
Find the sum to infinity of the series.
Practise AQA A Level Maths 1.7 D: Sequences and series with exam-style questions for A Level Maths. 267 questions covering 1.7.1 Binomial expansion, 1.7.2 Types of sequence (A-level only), 1.7.3 Sigma notation (A-level only), 1.7.4 Arithmetic sequences and series (A-level only), 1.7.5 Geometric sequences and series (A-level only), and 1.7.6 Sequences and series in modelling (A-level only), matched to the AQA A Level Maths (7357) specification and written in Paper 1, Paper 2 and Paper 3 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.