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1.7 D: Sequences and series

1.7 D: Sequences and series

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Question 56

The first three terms of a geometric series are (3k+3)(3k+3)(3k+3), (k+3)(k+3)(k+3), and k k\,k respectively, where k k\,k is a positive constant.

a.

Show that 2k2−3k−9=02k^2 - 3k - 9 = 02k2−3k−9=0.

[4]
b.

Hence show that k=3k = 3k=3.

[2]
c.

Find the common ratio.

[2]
d.

Find the sum to infinity of the series.

[2]
Markscheme

1.7 D: Sequences and series Questions

  1. A Level
  2. /Maths
  3. /1.7 D: Sequences and series

308 exam-style questions on AQA A Level Maths 1.7 D: Sequences and series, covering 1.7.1 Binomial expansion, 1.7.2 Types of sequence (A-level only), 1.7.3 Sigma notation (A-level only), 1.7.4 Arithmetic sequences and series (A-level only), 1.7.5 Geometric sequences and series (A-level only), and 1.7.6 Sequences and series in modelling (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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