An arithmetic series is given by
∑n=1150(bn+c)\sum_{n=11}^{50} (bn + c)∑n=1150(bn+c)
where b b\,b and c c\,c are constants. The sum of the series is 2680.
Show that 61b+2c=13461b + 2c = 13461b+2c=134.
Given that the 21st term of the sequence un=bn+cu_n = bn + cun=bn+c is 4 times its 3rd term, find the value of b b\,b and the value of ccc.
308 exam-style questions on AQA A Level Maths 1.7 D: Sequences and series, covering 1.7.1 Binomial expansion, 1.7.2 Types of sequence (A-level only), 1.7.3 Sigma notation (A-level only), 1.7.4 Arithmetic sequences and series (A-level only), 1.7.5 Geometric sequences and series (A-level only), and 1.7.6 Sequences and series in modelling (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.