The redox equilibria for a direct methanol fuel cell under standard acidic conditions are shown below.
CO2(g)+6H+(aq)+6e−⇌CH3OH(aq)+H2O(l)Eθ=+0.02 V \text{CO}_2(\text{g}) + 6\text{H}^+(\text{aq}) + 6\text{e}^- \rightleftharpoons \text{CH}_3\text{OH}(\text{aq}) + \text{H}_2\text{O}(\text{l}) \quad E^\theta = +0.02\text{ V} CO2(g)+6H+(aq)+6e−⇌CH3OH(aq)+H2O(l)Eθ=+0.02 V O2(g)+4H+(aq)+4e−⇌2H2O(l)Eθ=+1.23 V \text{O}_2(\text{g}) + 4\text{H}^+(\text{aq}) + 4\text{e}^- \rightleftharpoons 2\text{H}_2\text{O}(\text{l}) \quad E^\theta = +1.23\text{ V} O2(g)+4H+(aq)+4e−⇌2H2O(l)Eθ=+1.23 VWhat is the equation for the overall cell reaction when the cell is discharging?