This question is about some reactions of d-block elements and their ions.
Table 1 shows standard electrode potentials which will be needed within this question.
Half-reactionEθ/VMg2+(aq)+2e−⇌Mg(s)−2.37V3+(aq)+e−⇌V2+(aq)−0.26Co2+(aq)+2e−⇌Co(s)−0.28VO2+(aq)+2H+(aq)+e−⇌V3+(aq)+H2O(l)+0.34Br2(aq)+2e−⇌2Br−(aq)+1.09Fe3+(aq)+e−⇌Fe2+(aq)+0.77S2O82−(aq)+2e−⇌2SO42−(aq)+2.01\begin{array}{|l|c|} \hline \text{Half-reaction} & E^\theta / \text{V} \\ \hline \text{Mg}^{2+}(\text{aq}) + 2\text{e}^- \rightleftharpoons \text{Mg}(\text{s}) & -2.37 \\ \text{V}^{3+}(\text{aq}) + \text{e}^- \rightleftharpoons \text{V}^{2+}(\text{aq}) & -0.26 \\ \text{Co}^{2+}(\text{aq}) + 2\text{e}^- \rightleftharpoons \text{Co}(\text{s}) & -0.28 \\ \text{VO}^{2+}(\text{aq}) + 2\text{H}^+(\text{aq}) + \text{e}^- \rightleftharpoons \text{V}^{3+}(\text{aq}) + \text{H}_2\text{O}(\text{l}) & +0.34 \\ \text{Br}_2(\text{aq}) + 2\text{e}^- \rightleftharpoons 2\text{Br}^-(\text{aq}) & +1.09 \\ \text{Fe}^{3+}(\text{aq}) + \text{e}^- \rightleftharpoons \text{Fe}^{2+}(\text{aq}) & +0.77 \\ \text{S}_2\text{O}_8^{2-}(\text{aq}) + 2\text{e}^- \rightleftharpoons 2\text{SO}_4^{2-}(\text{aq}) & +2.01 \\ \hline \end{array}Half-reactionMg2+(aq)+2e−⇌Mg(s)V3+(aq)+e−⇌V2+(aq)Co2+(aq)+2e−⇌Co(s)VO2+(aq)+2H+(aq)+e−⇌V3+(aq)+H2O(l)Br2(aq)+2e−⇌2Br−(aq)Fe3+(aq)+e−⇌Fe2+(aq)S2O82−(aq)+2e−⇌2SO42−(aq)Eθ/V−2.37−0.26−0.28+0.34+1.09+0.77+2.01Complete the electron configuration of:
A standard cell is set up in the laboratory with the cell reaction shown below:
Co(s)+Br2(aq)→Co2+(aq)+2Br−(aq) \text{Co}(\text{s}) + \text{Br}_2(\text{aq}) \rightarrow \text{Co}^{2+}(\text{aq}) + 2\text{Br}^-(\text{aq}) Co(s)+Br2(aq)→Co2+(aq)+2Br−(aq)Describe how this cell could be set up to measure its standard cell potential. Include details of the electrodes, solutions, salt bridge, and standard conditions required.
Predict the standard cell potential of this cell.
Use the information in Table 1 to help answer both parts of this question.
Write the overall equation for the oxidation of Fe2+\text{Fe}^{2+}Fe2+ by S2O82−\text{S}_2\text{O}_8^{2-}S2O82−.
Magnesium reacts with acidified VO2+\text{VO}^{2+}VO2+ ions to form V2+\text{V}^{2+}V2+ ions in two stages. Explain why this happens in terms of electrode potentials and equilibria. Include overall equations for the reactions which occur.
Three different reactions of transition metal compounds are described below.
Identify C–F by formulae or structures, as appropriate. Include equations, any changes in oxidation number, and working.