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Group 2

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Question 1

An analytical chemist in a metallurgy laboratory is tasked with verifying the identity of an unknown Group 2 metal, M\text{M}M, which has been recovered from a scrap alloy sample.

To determine the identity, the chemist performs a 'back-titration' analysis:

  • A known mass of the metal is reacted with a measured excess of hydrochloric acid.
  • The resulting mixture is diluted, and the remaining unreacted acid is determined by titration with standard sodium hydroxide solution.

Stage 1 The chemist reacts a 1.28 g1.28\text{ g}1.28 g sample of the metal M\text{M}M with 100.0 cm3100.0\text{ cm}^3100.0 cm3 of 1.20 mol dm−3 HCl(aq)1.20\text{ mol dm}^{-3}\ \text{HCl(aq)}1.20 mol dm−3 HCl(aq). An excess of acid is used to ensure all of metal M\text{M}M reacts completely. A redox reaction occurs, forming hydrogen gas and a solution containing M2+\text{M}^{2+}M2+ ions.

Stage 2 The entire mixture from Stage 1 is quantitatively transferred to a volumetric flask and diluted with deionised water to a total volume of 250.0 cm3250.0\text{ cm}^3250.0 cm3.

Stage 3 A 25.00 cm325.00\text{ cm}^325.00 cm3 sample of the diluted solution is titrated against 0.250 mol dm−3 NaOH(aq)0.250\text{ mol dm}^{-3}\ \text{NaOH(aq)}0.250 mol dm−3 NaOH(aq) to neutralise the excess hydrochloric acid:

HCl(aq)+NaOH(aq)→NaCl(aq)+H2O(l) \text{HCl(aq)} + \text{NaOH(aq)} \rightarrow \text{NaCl(aq)} + \text{H}_2\text{O(l)} HCl(aq)+NaOH(aq)→NaCl(aq)+H2​O(l)

The titration is repeated to obtain concordant results.

Titration results

The burette readings have been recorded to the nearest 0.05 cm30.05\text{ cm}^30.05 cm3.

123
Final reading / cm3\text{cm}^3cm323.1523.9527.55
Initial reading / cm3\text{cm}^3cm30.001.505.20

Analyse these results to identify metal M\text{M}M. Show all your working.

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Group 2 Questions

  1. A Level
  2. /Chemistry
  3. /Group 2