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Organic synthesis and analysis

What you'll learn

  • How to plan organic syntheses as sequences of reactions, not isolated facts.
  • How to choose practical techniques for separation, purification and purity testing.
  • How addition polymers, polyesters and polyamides are formed.
  • How to combine chemical tests, high-resolution 1H^{1}\text{H}1H NMR and chromatography to identify unknowns.

1. Organic synthesis: building a route

Organic synthesis is the preparation of an organic compound from simpler starting materials. At A level, the key skill is recognising which functional group you have and which one you need.

Definition

Functional group

A functional group is the atom or group of atoms responsible for the characteristic reactions of an organic compound, such as –OH in alcohols, –COOH in carboxylic acids or –NH₂ in amines.

Definition

Synthetic sequence

A synthetic sequence is a planned series of reactions where the product of one step becomes the reactant for the next step.

Organic synthesis route map showing common functional group interconversions

Useful reaction choices include:

  • Haloalkane → alcohol: warm with aqueous OH⁻, usually under reflux.
  • Haloalkane → nitrile: warm with ethanolic CN⁻; this extends the carbon chain by one carbon.
  • Primary alcohol → aldehyde: acidified dichromate(VI), distil off the aldehyde.
  • Primary alcohol → carboxylic acid: acidified dichromate(VI), reflux.
  • Carboxylic acid + alcohol → ester: concentrated H₂SO₄ catalyst, reflux.
  • Carboxylic acid → acyl chloride: SOCl₂.
  • Acyl chloride + amine → amide: room temperature, often producing HCl.
Key Idea

Think backwards

A good synthesis often starts by working backwards from the target molecule: identify the target functional group, then choose a known reaction that makes it.

Example

Planning a two-step ester synthesis

You need to make butyl ethanoate from 1-bromobutane.

  1. Compare the target with the starting material: butyl ethanoate contains a butyl group attached through oxygen, so you first need butan-1-ol from 1-bromobutane.
  2. Choose the first reaction: heat 1-bromobutane with aqueous OH⁻ under reflux to give butan-1-ol by nucleophilic substitution.
  3. Choose the second reaction: react butan-1-ol with ethanoic acid using concentrated H₂SO₄ and reflux to form butyl ethanoate and water.
  4. Write the overall route in order: 1-bromobutane → butan-1-ol → butyl ethanoate.

Curly-arrow thinking in synthesis

Definition

Curly arrow

A curly arrow shows the movement of a pair of electrons. It must start at a lone pair or bond and point to where the electron pair moves.

For example, in the reaction of bromoethane with cyanide ions:

CH₃CH₂Br + CN⁻ → CH₃CH₂CN + Br⁻

The mechanism is nucleophilic substitution. The cyanide ion attacks using the lone pair on the carbon atom of CN⁻. A curly arrow goes from that lone pair to the carbon bonded to bromine. At the same time, a curly arrow goes from the C–Br bond to Br, forming Br⁻.

Common Mistake

Wrong end of cyanide

In A-level mechanisms, CN⁻ usually attacks through its carbon atom, giving a nitrile and increasing the carbon chain length by one.

2. Manipulation, separation and purification

Organic products are rarely obtained pure straight from the reaction mixture. You must be able to explain how to handle them.

Key practical techniques

  • Reflux heats a reaction mixture without losing volatile reactants or products; vapour condenses and returns to the flask.
  • Distillation separates liquids using different boiling temperatures.
  • A separating funnel separates immiscible liquid layers, often an organic layer and an aqueous layer.
  • A drying agent, such as anhydrous MgSO₄, removes traces of water from an organic liquid.
  • Recrystallisation purifies a solid by dissolving it in minimum hot solvent, then allowing pure crystals to form on cooling.
  • Melting temperature helps assess the purity of a solid.

For a liquid organic product, a typical method is: reflux the reaction mixture, transfer it to a separating funnel, wash with suitable aqueous solutions, run off the layers carefully, dry the organic layer, then distil the product.

For a solid organic product, a typical method is: collect the crude solid by filtration, recrystallise from a suitable solvent, filter the crystals under reduced pressure, wash with cold solvent, dry, then measure the melting temperature.

Common Mistake

Separating funnel safety

Always vent a separating funnel regularly when shaking, especially if gas may be produced during washing.

Melting temperature and purity

A pure solid has a sharp melting range, usually within about 1–2 °C, close to the data-book value. Impurities usually make the melting range lower and broader because they disrupt the regular crystal lattice.

Example

Judging purity from melting temperature

A compound has a literature melting temperature of 122 °C. Your product melts from 115 °C to 120 °C.

  1. Compare the sample range with the literature value: the sample starts melting well below 122 °C.
  2. Judge the sharpness: a 5 °C range is broad, not sharp.
  3. Conclude that the sample is impure and should be recrystallised again before relying on its identity or yield.
Tip

Two-step practicals

In a two-step synthesis, purify or at least isolate the intermediate before the second step. Impurities carried forward can reduce yield and complicate melting temperature or spectra.

3. Addition and condensation polymerisation

Definition

Polymer

A polymer is a large molecule made from many smaller molecules called monomers joined together.

In addition polymerisation, monomers with C=C bonds join without losing any atoms. The double bond opens and forms a saturated polymer chain.

In condensation polymerisation, monomers join together while eliminating a small molecule, usually water or HCl.

Comparison of addition polymerisation and condensation polymerisation forming polyesters and polyamides

Polyesters

A polyester contains ester links, –COO–. It can form from:

  • a diol and a dicarboxylic acid, eliminating water
  • a diol and a diacyl chloride, eliminating HCl

General idea:

HO–R–OH + HOOC–R′–COOH → polyester + water

Polyamides

A polyamide contains amide links, –CONH–. It can form from:

  • a diamine and a dicarboxylic acid, eliminating water
  • a diamine and a diacyl chloride, eliminating HCl

Nylon is an important example. Condensation polymers are industrially useful in fibres, packaging and engineering materials, but their persistence in the environment raises recycling and disposal issues.

Example

Identifying the polymer type

A polymer is made from HOOC–(CH₂)₄–COOH and H₂N–(CH₂)₆–NH₂.

  1. Identify the functional groups: the first monomer is a dicarboxylic acid and the second is a diamine.
  2. Decide the link formed: –COOH and –NH₂ combine to form an amide link, –CONH–.
  3. State the polymer type: it is a condensation polymer, specifically a polyamide, with water eliminated.

4. Identifying unknown organic compounds

When identifying an unknown, do not rely on one test alone. Build evidence from chemical tests and spectra.

Planning chemical tests

A sensible test sequence uses small samples and separates possibilities logically:

  • Bromine water decolourises with many alkenes.
  • Sodium carbonate gives effervescence with carboxylic acids due to CO₂.
  • 2,4-dinitrophenylhydrazine gives an orange precipitate with aldehydes and ketones.
  • Tollens’ reagent or Fehling’s solution distinguishes aldehydes from ketones.
  • Iodoform testing can identify CH₃CO– groups or CH₃CH(OH)– groups.
  • Iron(III) chloride can give a coloured complex with phenols.
Key Idea

Use evidence together

A positive chemical test suggests a functional group, but spectra help confirm the whole structure.

High-resolution 1H^{1}\text{H}1H NMR

High-resolution proton NMR gives four main types of information:

  • Chemical shift, measured in ppm, suggests the proton environment.
  • Integration gives the relative number of protons in each environment.
  • Splitting shows neighbouring equivalent protons, using the n+1n + 1n+1 rule.
  • Number of peaks shows the number of different proton environments.

You should combine this with other data, such as IR absorptions, mass spectrometry molecular ion peaks, and carbon-13 NMR environments.

Annotated proton NMR spectrum, TLC plate and gas chromatography trace

Example

Using proton NMR to identify ethyl ethanoate

A compound has three proton environments with integrations 3H, 2H and 3H. The 2H signal is a quartet at about 4.1 ppm, one 3H signal is a triplet at about 1.2 ppm, and the other 3H signal is a singlet at about 2.0 ppm.

  1. Use the quartet and triplet together: a 2H quartet next to a 3H triplet suggests an ethyl group, –CH₂CH₃.
  2. Use the chemical shift of the quartet: about 4.1 ppm suggests –O–CH₂– rather than a simple alkyl CH₂.
  3. Use the singlet at about 2.0 ppm: a 3H singlet near a carbonyl suggests CH₃CO– with no neighbouring hydrogens across the carbonyl.
  4. Combine the fragments: CH₃COOCH₂CH₃ is ethyl ethanoate.
Common Mistake

Splitting across the wrong atoms

In simple A-level NMR interpretation, do not count neighbouring protons through oxygen or across a carbonyl carbon for splitting.

5. Chromatography and mixture composition

Definition

Chromatography

Chromatography separates substances because they distribute differently between a stationary phase and a mobile phase.

In paper chromatography and TLC, the stationary phase is the paper or coated plate, and the mobile phase is the solvent. The RfR_fRf​ value is:

Rf=distance moved by spotdistance moved by solvent frontR_f = \frac{\text{distance moved by spot}}{\text{distance moved by solvent front}}Rf​=distance moved by solvent frontdistance moved by spot​

In two-way paper chromatography, the chromatogram is run in one solvent, dried, rotated by 90°, then run in a second solvent. This improves separation when spots overlap.

In GC and HPLC, each component has a retention time. Comparing retention times with standards helps identify compounds. Peak area is proportional to amount, so composition can be found using peak areas or calibration data.

Example

Calculating an Rf value

A spot moves 3.6 cm from the baseline. The solvent front moves 6.0 cm.

  1. Substitute into the expression: Rf=3.66.0R_f = \frac{3.6}{6.0}Rf​=6.03.6​.
  2. Calculate the value: Rf=0.60R_f = 0.60Rf​=0.60.
  3. Compare with standards run under the same conditions, because RfR_fRf​ values depend on the solvent, stationary phase and temperature.
Exam technique

In the exam

  1. For synthesis routes, state the reagent and conditions for every arrow, not just the product.
  2. For practical questions, link each technique to its purpose: separating layers, removing water, purifying crystals or checking purity.
  3. For structure determination, combine evidence: molecular formula, IR, NMR integration/splitting and chromatography should all agree.
Self review

Check yourself

  • Why does a broad, low melting range suggest an impure solid?
  • What monomers would you need to make a polyester rather than a polyamide?
  • How do retention time and peak area give different information in GC or HPLC?
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Synthesis route map from 1-bromobutane to butan-1-ol to butyl ethanoate, with a side branch to a nitrile showing chain length plus one

Organic synthesis is the preparation of a target molecule from simpler starting materials through a planned sequence of reactions. The key question in each step is which functional group you have now and which one you need next.

A haloalkane can become an alcohol with aqueous OH−OH^-OH− under reflux, or a nitrile with ethanolic CN−CN^-CN− on warming. A primary alcohol can then be oxidised to an aldehyde by distilling it off as it forms, or further to a carboxylic acid under reflux.

Good planning often starts backwards from the target functional group. Once the route is clear, label every arrow with both reagent and conditions to ensure every transition in the sequence is clearly defined.

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In a synthetic sequence, the [     ] of one step becomes the [     ] for the next.

Organic synthesis and analysis Revision Guide

  1. A Level
  2. /Chemistry
  3. /Organic synthesis and analysis