An atmospheric chemist investigating the degradation of a volatile organic compound (VOC) determined the initial rates for the reaction between two gaseous species, P\text{P}P and Q\text{Q}Q, at 298 K:
ExperimentInitial [P]/mol dm−3Initial [Q]/mol dm−3Initial rate/mol dm−3 s−110.1500.2504.50×10−420.300To be calculated2.70×10−3 \begin{array}{|c|c|c|c|} \hline \text{Experiment} & \text{Initial } [\text{P}] / \text{mol dm}^{-3} & \text{Initial } [\text{Q}] / \text{mol dm}^{-3} & \text{Initial rate} / \text{mol dm}^{-3} \text{ s}^{-1} \\ \hline 1 & 0.150 & 0.250 & 4.50 \times 10^{-4} \\ \hline 2 & 0.300 & \text{To be calculated} & 2.70 \times 10^{-3} \\ \hline \end{array} Experiment12Initial [P]/mol dm−30.1500.300Initial [Q]/mol dm−30.250To be calculatedInitial rate/mol dm−3 s−14.50×10−42.70×10−3The rate equation for the reaction is:
rate=k[P][Q]2 \text{rate} = k [\text{P}] [\text{Q}]^2 rate=k[P][Q]2What is the initial concentration of Q\text{Q}Q in experiment 2?
0.1880.1880.188
0.3750.3750.375
0.4330.4330.433
0.7500.7500.750
