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5.2.3a Radioactive decay

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Question 52

Bismuth, Bi\text{Bi}Bi, has a proton number equal to 83 and a nucleon number equal to 210.

Bismuth changes into polonium, Po\text{Po}Po, by emitting a β−\beta^-β−-particle.

Which equation correctly represents this decay?

A

21083Bi→21084Po+0−1β{}_{210}^{83}\text{Bi} \rightarrow {}_{210}^{84}\text{Po} + {}_{0}^{-1}\beta21083​Bi→21084​Po+0−1​β

B

21083Bi+0−1β→21084Po{}_{210}^{83}\text{Bi} + {}_{0}^{-1}\beta \rightarrow {}_{210}^{84}\text{Po}21083​Bi+0−1​β→21084​Po

C

83210Bi→84210Po+−10β{}_{83}^{210}\text{Bi} \rightarrow {}_{84}^{210}\text{Po} + {}_{-1}^{0}\beta83210​Bi→84210​Po+−10​β

D

83210Bi+−10β→84210Po{}_{83}^{210}\text{Bi} + {}_{-1}^{0}\beta \rightarrow {}_{84}^{210}\text{Po}83210​Bi+−10​β→84210​Po

Markscheme

5.2.3a Radioactive decay Questions

  1. IGCSE
  2. /Physics
  3. /5.2.3a Radioactive decay

120 exam-style questions on CIE IGCSE Physics 5.2.3a Radioactive decay. Each one has a worked solution and a mark scheme showing where the marks go.

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