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2.1.3b Pressure, volume and temperature of a gas

Heating a gas at constant volume raises its pressure

  1. Start with a fixed mass of gas sealed in a rigid container, such as a steel can, so no particles get in or out and the volume cannot change.
  2. Heating the gas raises the average kinetic energy of its particles, so on average they move faster.
  3. Faster particles cross the container in less time, so they strike the walls more often.
  4. Each collision is also harder, because a faster particle rebounds with a bigger change of velocity and pushes the wall more strongly.
  5. More frequent and harder collisions mean a greater total force on the same area of wall, so the pressure rises.
  6. Cooling the same sealed can reverses every step, so the pressure falls, which is why an aerosol left in a cold shed sprays weakly.

Squeezing a gas at constant temperature also raises its pressure

  1. Now take the same fixed mass of gas in a syringe with the nozzle blocked, and push the plunger in slowly so the temperature stays constant.
  2. Because the temperature has not changed, the particles are moving at the same average speed as before, so each individual collision is just as hard as it was.
  3. The smaller volume gives each particle a shorter distance to travel before it meets a wall again.
  4. The same number of particles therefore makes more collisions per second on each square metre of wall, and the pressure rises.
  5. Pulling the plunger back out increases the volume, spreads the collisions thinner, and the pressure falls again.
  6. Notice the difference between the two cases: heating changes both how often and how hard, while squeezing changes only how often.

At constant temperature, pressure times volume stays the same

Definition

Boyle's law

For a fixed mass of gas at constant temperature, the pressure multiplied by the volume always gives the same value.

pV=constant pV = \text{constant} pV=constant

so for two sets of conditions

p1V1=p2V2 p_1V_1 = p_2V_2 p1​V1​=p2​V2​
  1. Halving the volume doubles the pressure, and trebling the volume cuts the pressure to a third, so pressure and volume are inversely proportional.
  2. Two conditions must hold for the equation to work: the mass of gas is fixed and the temperature is constant.
  3. Any consistent units work, because the same units appear on both sides, so pressure in kPa\text{kPa}kPa with volume in cm3\text{cm}^3cm3 is fine as long as you do not switch part-way through.
  4. A graph of ppp against VVV is a smooth curve falling steeply at first and then flattening, never touching either axis.
  5. A graph of ppp against 1/V1/V1/V is a straight line through the origin, and that straight line is the usual way of showing that the relationship really is inverse proportion.
Common Mistake
  • Do not say that squeezing a gas makes its particles move faster, because at constant temperature their average speed is unchanged and only the collision rate rises.
  • Do not use pV=constantpV = \text{constant}pV=constant when the temperature changes, because the equation only holds at constant temperature.
  • Do not describe ppp and VVV as proportional, because they are inversely proportional and one goes up as the other comes down.
  • Do not mix units within one calculation, so if V1V_1V1​ is in cm3\text{cm}^3cm3 then V2V_2V2​ must be in cm3\text{cm}^3cm3 too.
Exam technique
  • Read the stem for which quantity is being held constant before you write anything, because that decides whether the answer is about speed or about spacing.
  • For a qualitative explanation, give the chain in order: what the particles do, how the collisions change, then what happens to the pressure.
  • Quote p1V1=p2V2p_1V_1 = p_2V_2p1​V1​=p2​V2​ from memory and substitute before rearranging, so a slip in the algebra still leaves the substitution mark standing.
  • Check the answer makes sense: a smaller volume must give a bigger pressure, so an answer that has dropped means the fraction was the wrong way up.
Self review
  • Explain, in terms of particles, why heating a gas in a sealed rigid can raises its pressure.
  • Why does the pressure rise when a gas is squeezed into a smaller volume at constant temperature?
  • State the two conditions needed for pV=constantpV = \text{constant}pV=constant to apply.
  • A gas at 200 kPa200\ \text{kPa}200 kPa occupies 30 cm330\ \text{cm}^330 cm3. Find its volume at 120 kPa120\ \text{kPa}120 kPa and the same temperature.
  • Sketch the shape of a graph of ppp against 1/V1/V1/V for a fixed mass of gas at constant temperature.
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2.1.3b Pressure, volume and temperature of a gas Revision Guide

  1. IGCSE
  2. /Physics
  3. /2.1.3b Pressure, volume and temperature of a gas

Revision notes for CIE IGCSE Physics 2.1.3b Pressure, volume and temperature of a gas: explanations and worked examples.

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