Heating a gas at constant volume raises its pressure
- Start with a fixed mass of gas sealed in a rigid container, such as a steel can, so no particles get in or out and the volume cannot change.
- Heating the gas raises the average kinetic energy of its particles, so on average they move faster.
- Faster particles cross the container in less time, so they strike the walls more often.
- Each collision is also harder, because a faster particle rebounds with a bigger change of velocity and pushes the wall more strongly.
- More frequent and harder collisions mean a greater total force on the same area of wall, so the pressure rises.
- Cooling the same sealed can reverses every step, so the pressure falls, which is why an aerosol left in a cold shed sprays weakly.
Squeezing a gas at constant temperature also raises its pressure
- Now take the same fixed mass of gas in a syringe with the nozzle blocked, and push the plunger in slowly so the temperature stays constant.
- Because the temperature has not changed, the particles are moving at the same average speed as before, so each individual collision is just as hard as it was.
- The smaller volume gives each particle a shorter distance to travel before it meets a wall again.
- The same number of particles therefore makes more collisions per second on each square metre of wall, and the pressure rises.
- Pulling the plunger back out increases the volume, spreads the collisions thinner, and the pressure falls again.
- Notice the difference between the two cases: heating changes both how often and how hard, while squeezing changes only how often.
At constant temperature, pressure times volume stays the same
Definition
Boyle's law
For a fixed mass of gas at constant temperature, the pressure multiplied by the volume always gives the same value.
pV=constant pV = \text{constant} pV=constantso for two sets of conditions
p1V1=p2V2 p_1V_1 = p_2V_2 p1V1=p2V2- Halving the volume doubles the pressure, and trebling the volume cuts the pressure to a third, so pressure and volume are inversely proportional.
- Two conditions must hold for the equation to work: the mass of gas is fixed and the temperature is constant.
- Any consistent units work, because the same units appear on both sides, so pressure in kPa\text{kPa}kPa with volume in cm3\text{cm}^3cm3 is fine as long as you do not switch part-way through.
- A graph of ppp against VVV is a smooth curve falling steeply at first and then flattening, never touching either axis.
- A graph of ppp against 1/V1/V1/V is a straight line through the origin, and that straight line is the usual way of showing that the relationship really is inverse proportion.
Common Mistake
- Do not say that squeezing a gas makes its particles move faster, because at constant temperature their average speed is unchanged and only the collision rate rises.
- Do not use pV=constantpV = \text{constant}pV=constant when the temperature changes, because the equation only holds at constant temperature.
- Do not describe ppp and VVV as proportional, because they are inversely proportional and one goes up as the other comes down.
- Do not mix units within one calculation, so if V1V_1V1 is in cm3\text{cm}^3cm3 then V2V_2V2 must be in cm3\text{cm}^3cm3 too.
Exam technique
- Read the stem for which quantity is being held constant before you write anything, because that decides whether the answer is about speed or about spacing.
- For a qualitative explanation, give the chain in order: what the particles do, how the collisions change, then what happens to the pressure.
- Quote p1V1=p2V2p_1V_1 = p_2V_2p1V1=p2V2 from memory and substitute before rearranging, so a slip in the algebra still leaves the substitution mark standing.
- Check the answer makes sense: a smaller volume must give a bigger pressure, so an answer that has dropped means the fraction was the wrong way up.
Self review
- Explain, in terms of particles, why heating a gas in a sealed rigid can raises its pressure.
- Why does the pressure rise when a gas is squeezed into a smaller volume at constant temperature?
- State the two conditions needed for pV=constantpV = \text{constant}pV=constant to apply.
- A gas at 200 kPa200\ \text{kPa}200 kPa occupies 30 cm330\ \text{cm}^330 cm3. Find its volume at 120 kPa120\ \text{kPa}120 kPa and the same temperature.
- Sketch the shape of a graph of ppp against 1/V1/V1/V for a fixed mass of gas at constant temperature.