An electric motorcycle accelerates uniformly in a straight line from rest at time t=0t = 0t=0. At t=2.5 st = 2.5\text{ s}t=2.5 s, the speed of the motorcycle is 15.0 m/s15.0\text{ m/s}15.0 m/s.
(i) Calculate the acceleration of the motorcycle. (ii) Explain in words what is meant by the term acceleration.
The motorcycle travels at a constant speed of 15.0 m/s15.0\text{ m/s}15.0 m/s from t=2.5 st = 2.5\text{ s}t=2.5 s to t=10.5 st = 10.5\text{ s}t=10.5 s. (i) Determine the distance travelled by the motorcycle between t=0t = 0t=0 and t=2.5 st = 2.5\text{ s}t=2.5 s. (ii) Calculate the total distance travelled by the motorcycle from t=0t = 0t=0 to t=10.5 st = 10.5\text{ s}t=10.5 s.
At t=10.5 st = 10.5\text{ s}t=10.5 s, the brakes are applied. The motorcycle and its rider have a combined mass of 240 kg240\text{ kg}240 kg. The motorcycle decelerates uniformly from 15.0 m/s15.0\text{ m/s}15.0 m/s to rest in 3.0 s3.0\text{ s}3.0 s, travelling a distance of 22.5 m22.5\text{ m}22.5 m during this deceleration. (i) Show that the work done by the braking force to bring the motorcycle to a stop is approximately 2.7×104 J2.7 \times 10^4\text{ J}2.7×104 J. (ii) Calculate the average braking force acting on the motorcycle during this deceleration.
On a different day, the motorcycle travels a longer distance than 22.5 m22.5\text{ m}22.5 m while it decelerates from 15.0 m/s15.0\text{ m/s}15.0 m/s to rest. Suggest and explain mechanical or environmental factors that cause this braking distance to increase.
204 exam-style questions on CIE IGCSE Physics Motion, covering Motion. Each one has a worked solution and a mark scheme showing where the marks go.