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6.1.1b Average orbital speed

Average orbital speed: one lap round, divided by the time it took

Definition

Average orbital speed

The distance travelled in one complete orbit divided by the time taken for that orbit.

v=2πrT v = \frac{2\pi r}{T} v=T2πr​

where rrr is the average radius of the orbit and TTT is the orbital period.

  1. Speed is always distance divided by time, so the only real work in this topic is writing down the distance an orbiting object covers.

  2. An orbit is treated as a circle of radius rrr, measured from the centre of the orbit out to the orbiting object.

  3. The distance covered in one complete orbit is therefore the circumference of that circle.

    distance in one orbit=2πr \text{distance in one orbit} = 2\pi r distance in one orbit=2πr
  4. The time for that one orbit is the orbital period TTT, so dividing the circumference by TTT gives the average speed.

    v=2πrT v = \frac{2\pi r}{T} v=T2πr​
  5. The word average matters, because a real orbit is slightly squashed and the object speeds up and slows down as it goes round; this equation gives the speed averaged over the whole lap.

  6. You must be able to write the equation down from memory, since no equation list is handed out with the paper.

Units first: metres and seconds, or the answer is wrong by thousands

Definition

Orbital period

The time taken for an orbiting object to complete one full circuit of its orbit, given the symbol TTT and measured in seconds.

  1. For a speed in m/s\text{m/s}m/s, put rrr in metres and TTT in seconds before substituting anything.

  2. Orbital periods are almost always quoted in days, hours or years, so a conversion is nearly always the first step.

    1 hour=3600 s 1\ \text{hour} = 3600\ \text{s} 1 hour=3600 s 1 day=24×3600=86 400 s 1\ \text{day} = 24 \times 3600 = 86\,400\ \text{s} 1 day=24×3600=86400 s
  3. Radii in space physics are enormous, so work in standard form throughout rather than typing long strings of zeros into the calculator.

  4. The equation rearranges in the usual way if the question gives you the speed and asks for the period or the radius.

    T=2πrvr=vT2π T = \frac{2\pi r}{v} \qquad r = \frac{vT}{2\pi} T=v2πr​r=2πvT​
Common Mistake
  • Do not put the diameter of the orbit into the equation, because rrr is the radius, measured from the centre of the orbit outwards.
  • Do not confuse the radius of the orbit with the radius of the planet, which questions often list in the same data table to catch you out.
  • Do not forget the factor 2π2\pi2π; using r/Tr/Tr/T alone is one of the most common ways to lose the whole calculation.

Reading the equation: what makes an orbiting object fast or slow

  1. For the same orbital radius, a shorter period means a higher speed, because the same distance is covered in less time.
  2. For the same period, a larger radius means a higher speed, because a bigger circle has to be covered in the same time.
  3. In a real planetary system both quantities change together, so you cannot judge which planet is fastest by looking at radius alone: put the numbers into the equation and compare.
  4. The equation works for anything that goes round anything else, so the same three symbols handle a planet round the Sun, the Moon round the Earth or a satellite round the Earth.
Exam technique
  • Write v=2πrTv = \frac{2\pi r}{T}v=T2πr​ on the page before you touch the calculator, because the equation itself usually carries a mark even if the arithmetic then goes wrong.
  • Show the unit conversion as a separate line, so a converted period in seconds is visible to the marker rather than buried inside one long calculation.
  • The mark most often dropped here is the unit on the final answer, so write m/s\text{m/s}m/s every time.
  • When a data table gives several planets, underline the two columns you actually need before starting, because these tables deliberately carry extra columns such as density and surface temperature.
Self review
  • Define average orbital speed and write its equation.
  • Why does the term 2πr2\pi r2πr appear in the equation?
  • What must rrr and TTT be measured in to give a speed in m/s\text{m/s}m/s?
  • A satellite orbits at a radius of 7.0×106 m7.0 \times 10^{6}\ \text{m}7.0×106 m with a period of 6000 s6000\ \text{s}6000 s. Find its average orbital speed.
  • Two moons have the same orbital period, but one orbits twice as far out. Which moves faster, and why?
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6.1.1b Average orbital speed Revision Guide

  1. IGCSE
  2. /Physics
  3. /6.1.1b Average orbital speed

Revision notes for CIE IGCSE Physics 6.1.1b Average orbital speed: explanations and worked examples.

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