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bg-background","children":["$","$L3a",null,{"backHref":"/igcse/maths/oxford-aqa/questions","basePath":"/igcse/maths/oxford-aqa/grade-5-5-6-solving-quadratics/questions","formulaUrl":"https://www.oxfordaqa.com/oaqaresources/maths/assessment/9260-oxfordaqa-international-gcse-mathematics-formulae-sheet-ext-e3.pdf","initialIndex":8,"initialQuestionWindow":[{"id":"c71b8017-c256-4d93-ad27-580a5b58d5b9","revisionId":"a667948f-fdb0-47da-96e6-8b466410033f","questionNumber":"8","questionType":"LA","specification":"","difficulty":2,"difficultyBand":"medium","totalMarks":3,"sourceTitle":"Solving Quadratics","calculatorUse":null,"isCalculation":true,"parts":[{"id":"dea24b92-62a2-46bd-aa60-677cc1315d5e","label":"0","content":"Solve $x^2 + 5x - 6 = 0$","markscheme":"- Factorises the quadratic: $(x - 1)(x + 6) = 0$ M2\n- Correct solutions: $x = 1$ or $x = -6$ A1","marks":3,"order":0,"markingRubric":{"totalMarks":3,"points":[{"id":"p1","marks":1,"description":"Identifies factors of -6 that sum to 5 (-1 and 6).","code":"M"},{"id":"p2","marks":1,"description":"Writes the quadratic in factorised form $(x-1)(x+6) = 0$.","code":"M"},{"id":"p3","marks":1,"description":"Final answers $x = 1$ and $x = -6$.","code":"A"}],"finalAnswers":["x = 1, x = -6"],"generatedAt":"2026-05-07T01:58:33.588Z","modelVersion":"gemini-3-flash-preview"},"tableImages":[],"explanation":{"methods":[{"id":"factorising","label":"Factorising","steps":[{"type":"text","order":0,"title":"Find two numbers","content":"To factorise, find two numbers whose **product** is $-6$ and whose **sum** is $5$. They are $-1$ and $6$.\n\nThese give the brackets $(x-1)$ and $(x+6)$.","highlights":[{"text":"Solve $x^2 + 5x - 6 = 0$","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"\\htmlData{anchor=original}{x^2+5x-6=0}"},{"latex":"\\htmlData{anchor=factorised}{\\color{@sky}{(x-1)(x+6)}=0}"}],"highlights":[{"color":"sky","style":"text-color-with-background","anchor":"factorised"}],"connections":[{"to":"factorised","from":"original","color":"sky","label":"factorise"}]},"order":1,"title":"Factorise the quadratic","description":"The first terms multiply to x squared, the last terms multiply to negative six, and the middle terms add to five x. This correct factorisation earns the M2 marks."},{"type":"text","order":2,"title":"Use the zero-product rule","content":"If two factors multiply to zero, at least one factor must equal zero. Therefore set each bracket equal to zero:\n\n$$x-1=0 \\quad \\text{or} \\quad x+6=0.$$"},{"type":"hyper_latex","block":{"nodes":[{"latex":"\\htmlData{anchor=first_equation}{x-1=0}"},{"latex":"\\htmlData{anchor=first_solution}{\\color{@green}{x=1}}"},{"latex":"\\htmlData{anchor=second_equation}{x+6=0}"},{"latex":"\\htmlData{anchor=second_solution}{\\color{@green}{x=-6}}"}],"highlights":[{"color":"green","style":"text-color-with-background","anchor":"first_solution"},{"color":"green","style":"text-color-with-background","anchor":"second_solution"}],"connections":[{"to":"first_solution","from":"first_equation","color":"green","label":"add 1"},{"to":"second_solution","from":"second_equation","color":"green","label":"subtract 6"}]},"order":3,"title":"Solve each bracket","description":"Make x the subject in each of the two one-step equations. Writing x equals 1 or x equals negative 6 earns the A1 mark."}]}],"generatedAt":"2026-07-21T04:15:48.684Z","modelVersion":"gpt-5.6-terra","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":null,"firstAttemptFullMarks":null,"walkthroughVideo":null},{"id":"7face5c3-4ccc-4d2e-ae9f-d3e8e9df86ce","revisionId":"33adc4a4-9770-40e4-8dd9-24bcf20f8bde","questionNumber":"9","questionType":"LA","specification":"","difficulty":2,"difficultyBand":"medium","totalMarks":3,"sourceTitle":"Solving Quadratics","calculatorUse":null,"isCalculation":true,"parts":[{"id":"331fd46a-ca72-4c7c-9c06-b1dd3d2478ef","label":"0","content":"Solve $x^2 + 5x + 6 = 0$","markscheme":"- Factorises the quadratic: $(x + 2)(x + 3) = 0$ M2\n- Correct solutions: $x = -2$ or $x = -3$ A1","marks":3,"order":0,"markingRubric":{"totalMarks":3,"points":[{"id":"p1","marks":1,"description":"Identifies factors of 6 that sum to 5 (2 and 3).","code":"M"},{"id":"p2","marks":1,"description":"Writes the quadratic in factorised form $(x+2)(x+3) = 0$.","code":"M"},{"id":"p3","marks":1,"description":"Final answers $x = -2$ and $x = -3$.","code":"A"}],"finalAnswers":["x = -2, x = -3"],"generatedAt":"2026-05-07T01:58:33.588Z","modelVersion":"gemini-3-flash-preview"},"tableImages":[],"explanation":{"methods":[{"id":"factorising","label":"Factorising","steps":[{"type":"text","order":0,"title":"Choose the factor pair","content":"Find two numbers that multiply to give $6$ and add to give $5$. They are $2$ and $3$.\n\nThese numbers become the constants in the two brackets.","highlights":[{"text":"Solve $x^2 + 5x + 6 = 0$","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"\\htmlData{anchor=original}{x^2+5x+6=0}"},{"latex":"\\htmlData{anchor=factorised}{(x+2)(x+3)=0}"}],"connections":[{"to":"factorised","from":"original","color":"sky","label":"factor pair: 2 + 3 = 5, 2 × 3 = 6","style":"solid"}]},"order":1,"title":"Factorise the quadratic","description":"Use 2 and 3 because 2 + 3 = 5 and 2 × 3 = 6. M2: correct factorisation."},{"type":"text","order":2,"title":"Apply zero-product rule","content":"If two factors multiply to make $0$, at least one factor must equal $0$. So solve $x+2=0$ and $x+3=0$ separately."},{"type":"hyper_latex","block":{"nodes":[{"latex":"\\htmlData{anchor=two_from}{x+2=0}"},{"latex":"\\htmlData{anchor=two_to}{x=-2}"},{"latex":"\\htmlData{anchor=three_from}{x+3=0}"},{"latex":"\\htmlData{anchor=three_to}{x=-3}"}],"highlights":[{"color":"orange","style":"text-color-with-background","anchor":"two_to"},{"color":"green","style":"text-color-with-background","anchor":"three_to"}],"connections":[{"to":"two_to","from":"two_from","color":"orange","label":"subtract 2","style":"solid"},{"to":"three_to","from":"three_from","color":"green","label":"subtract 3","style":"solid"}]},"order":3,"title":"Solve each factor","description":"Subtract 2 from the first equation and 3 from the second. A1: both resulting solutions correct."}]}],"generatedAt":"2026-07-21T04:11:56.831Z","modelVersion":"gpt-5.6-terra","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":null,"firstAttemptFullMarks":null,"walkthroughVideo":null},{"id":"b2cf389a-05e6-4dcf-ad80-4867651ec01c","revisionId":"5733bd6a-89fe-4d30-a8f4-56b434c3344f","questionNumber":"10","questionType":"LA","specification":"","difficulty":2,"difficultyBand":"medium","totalMarks":3,"sourceTitle":"Solving Quadratics","calculatorUse":null,"isCalculation":true,"parts":[{"id":"14e53afd-09e0-4da3-badf-bad984b1f9db","label":"0","content":"Solve $x^2 - 12x + 32 = 0$","markscheme":"- Factorises the quadratic: $(x - 4)(x - 8) = 0$ M2\n- Correct solutions: $x = 4$ or $x = 8$ A1","marks":3,"order":0,"markingRubric":{"totalMarks":3,"points":[{"id":"p1","marks":1,"description":"Identifies factors of 32 that sum to -12 (-4 and -8).","code":"M"},{"id":"p2","marks":1,"description":"Writes the quadratic in factorised form $(x-4)(x-8) = 0$.","code":"M"},{"id":"p3","marks":1,"description":"Final answers $x = 4$ and $x = 8$.","code":"A"}],"finalAnswers":["x = 4, x = 8"],"generatedAt":"2026-05-07T01:58:33.588Z","modelVersion":"gemini-3-flash-preview"},"tableImages":[],"explanation":{"methods":[{"id":"factorising","label":"Factorise then solve","steps":[{"type":"text","order":0,"title":"Choose the factor pair","content":"Find two numbers which multiply to $32$ and add to $12$: they are $4$ and $8$. Both signs are negative because the middle term is $-12x$, while the constant is positive.","highlights":[{"text":"$$x^2 - 12x + 32 = 0$","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"\\htmlData{anchor=original}{x^2-12x+32=0}"},{"latex":"\\htmlData{anchor=factorised}{(x-4)(x-8)=0}"}],"highlights":[{"color":"sky","style":"text-color-with-background","anchor":"factorised"}]},"order":1,"title":"Factorise the quadratic","description":"Find two numbers which multiply to 32 and add to 12. The correct factorisation earns the M2 marks."},{"type":"hyper_latex","block":{"nodes":[{"latex":"\\htmlData{anchor=first_factor}{x-4=0}"},{"latex":"\\htmlData{anchor=first_root}{x=4}"},{"latex":"\\htmlData{anchor=second_factor}{x-8=0}"},{"latex":"\\htmlData{anchor=second_root}{x=8}"}],"connections":[{"to":"first_root","from":"first_factor","color":"orange","label":"add 4","style":"solid"},{"to":"second_root","from":"second_factor","color":"orange","label":"add 8","style":"solid"}]},"order":2,"title":"Set each factor zero","description":"A product is zero only when at least one factor is zero, so set each factor equal to zero. These roots earn the A1 mark."}]}],"generatedAt":"2026-07-21T04:12:34.905Z","modelVersion":"gpt-5.6-terra","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":null,"firstAttemptFullMarks":null,"walkthroughVideo":null}],"subjectCode":"igcse_maths__oxford_aqa","summaries":[{"id":"8c4a3814-07f4-423e-961b-9108b4e4f481","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"2fe541d6-a67a-44eb-9ce4-d6b00ec581ec","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"6aeabf1c-53f7-46c3-8e3a-21c54867b5a5","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"d076615f-be28-4fd1-b260-315b540ba51b","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"aa9ac8b7-21c2-49c0-96bf-6a92f17abe01","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"d296e581-2509-4b68-8c33-935b5c6c36ac","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"1c0b7c87-d951-4125-819e-b7cb826593be","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"c71b8017-c256-4d93-ad27-580a5b58d5b9","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"7face5c3-4ccc-4d2e-ae9f-d3e8e9df86ce","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"b2cf389a-05e6-4dcf-ad80-4867651ec01c","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"2ada5dd1-ffd8-4c4a-a7cc-c334dd668bd1","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"5f32ba50-332a-42a7-996d-1965f7e48ce8","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"30878799-3a3a-4c2d-984d-545b84d7778b","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"b3935209-66d6-4aa0-8493-f378abbca4d6","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"d600099b-0ecf-46f9-a730-89d28e2f26b4","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"df27fdcc-0236-4e33-b25f-ed879ca090fa","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"62eb9144-cf1d-4dde-9d57-dfc5f0eacd47","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"7ffc1c73-47e1-4b79-a48f-69185e7cde87","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true}],"title":"Solving Quadratics","topicId":"0fc9a4da-ed2b-45f7-ae31-aa3798b15b98","topicSidebar":"$L3b","topicSlug":"grade-5-5-6-solving-quadratics","topicTitle":"Solving Quadratics"}]}],"$L3c","$L3d"]}]

Solving Quadratics

Question 3

Solving Quadratics Questions

Solving Quadratics

Question 3

Solving Quadratics Questions