Revision notes for Oxford AQA IGCSE Maths Indices. Open the guide for explanations and worked examples. Written against the Oxford AQA IGCSE Maths (9260) specification, so the content matches what's examinable rather than general Maths background.
Revision notes for Oxford AQA IGCSE Maths Indices. Open the guide for explanations and worked examples. Written against the Oxford AQA IGCSE Maths (9260) specification, so the content matches what's examinable rather than general Maths background.
A power is a shorter way of writing repeated multiplication. For example, 434^343 means:
43=4×4×44^3 = 4 \times 4 \times 443=4×4×4It does not mean 4 times 3.
Base and index
In an expression such as ana^nan, the base is aaa and the index is nnn. The plural of index is indices. The index tells you how many times the base is multiplied by itself.
Evaluating a simple power
Expand 252^525 as five factors of 2.
25=2×2×2×2×22^5 = 2 \times 2 \times 2 \times 2 \times 225=2×2×2×2×2Multiply carefully from left to right.
25=322^5 = 3225=32Index does not mean multiply
252^525 means 2 multiplied by itself five times. It is not the same as 2 times 5.
When you multiply powers with the same base, you add the indices.
Multiplication law
For the same base, am×an=am+na^m \times a^n = a^{m+n}am×an=am+n. The base stays the same; the indices add.
The diagram below shows the idea behind the three main laws: multiplying joins factors, dividing cancels factors, and a power outside brackets repeats the whole power.

Simplifying a product of powers
Simplify r7×r2r^7 \times r^2r7×r2.
The base is the same in both terms: rrr.
Add the indices.
r7×r2=r7+2r^7 \times r^2 = r^{7+2}r7×r2=r7+2Write the answer as one power: r9r^9r9.
Hidden index of 1
A letter on its own has index 1. So xxx means x1x^1x1.
When you divide powers with the same base, you subtract the indices.
Division law
For the same non-zero base, am÷an=am−na^m \div a^n = a^{m-n}am÷an=am−n. In fraction form, aman=am−n\frac{a^m}{a^n} = a^{m-n}anam=am−n.
Simplifying a quotient of powers
Simplify y8y3\frac{y^8}{y^3}y3y8.
The base is the same: yyy.
Subtract the bottom index from the top index.
y8y3=y8−3\frac{y^8}{y^3} = y^{8-3}y3y8=y8−3Write the answer: y5y^5y5.
Do not divide by zero
The division law assumes the base is not zero, because division by zero is not allowed.
Sometimes a power is raised to another power, such as (x3)4(x^3)^4(x3)4.
This means the power x3x^3x3 is being repeated four times:
(x3)4=x3×x3×x3×x3(x^3)^4 = x^3 \times x^3 \times x^3 \times x^3(x3)4=x3×x3×x3×x3So the indices multiply.
Power of a power
When a power is raised to another power, multiply the indices: (am)n=amn(a^m)^n = a^{mn}(am)n=amn.
Simplifying a power of a power
Simplify (t4)3(t^4)^3(t4)3.
Multiply the indices 4 and 3.
(t4)3=t4×3(t^4)^3 = t^{4 \times 3}(t4)3=t4×3Write the final answer: t12t^{12}t12.
Do not add here
For (x5)2(x^5)^2(x5)2, multiply the indices to get x10x^{10}x10. Do not add them to get x7x^7x7.
A bracketed expression may include a number as well as letters, such as (2a3b)4(2a^3b)^4(2a3b)4.
Coefficient
A coefficient is the number multiplying a letter. In 6x6x6x, the coefficient of xxx is 6.
When a bracket is raised to a power, the outside index applies to everything inside the bracket.
Simplifying brackets with a coefficient
Simplify (3m2n)3(3m^2n)^3(3m2n)3.
Cube the coefficient 3.
33=273^3 = 2733=27Multiply each letter’s index by 3.
(m2)3=m6(m^2)^3 = m^6(m2)3=m6Remember that nnn has a hidden index of 1, so n3n^3n3 stays as n3n^3n3.
Combine the parts: 27m6n327m^6n^327m6n3.
Forgetting to power the number
In (4x)2(4x)^2(4x)2, the answer is 16x216x^216x2, not 4x24x^24x2, because the coefficient 4 is squared as well.
For expressions with coefficients and letters, deal with the numbers and each letter separately.
Multiply term by term
Multiply the coefficients, then add indices for matching letters.
Multiplying terms with different letters
Simplify 4p2q3×5pq24p^2q^3 \times 5pq^24p2q3×5pq2.
Multiply the coefficients.
4×5=204 \times 5 = 204×5=20Add the powers of ppp, remembering p=p1p=p^1p=p1.
p2×p=p2+1=p3p^2 \times p = p^{2+1} = p^3p2×p=p2+1=p3Add the powers of qqq.
q3×q2=q3+2=q5q^3 \times q^2 = q^{3+2} = q^5q3×q2=q3+2=q5Combine everything: 20p3q520p^3q^520p3q5.
When dividing algebraic terms, divide the coefficients and subtract indices for matching letters.
Dividing algebraic terms
Simplify 18a6b46a2b\frac{18a^6b^4}{6a^2b}6a2b18a6b4.
Divide the coefficients.
18÷6=318 \div 6 = 318÷6=3Subtract the powers of aaa.
a6÷a2=a6−2=a4a^6 \div a^2 = a^{6-2} = a^4a6÷a2=a6−2=a4Subtract the powers of bbb, remembering b=b1b=b^1b=b1.
b4÷b=b4−1=b3b^4 \div b = b^{4-1} = b^3b4÷b=b4−1=b3Combine everything: 3a4b33a^4b^33a4b3.
Cancel first if it helps
In a fraction, you can cancel common factors before using index laws. This is often useful when the coefficients are not simple multiples.
Any non-zero number or letter to the power of 0 is equal to 1.
Why? Because dividing a power by itself gives 1:
x4x4=1\frac{x^4}{x^4}=1x4x4=1Using index laws:
x4x4=x4−4=x0\frac{x^4}{x^4}=x^{4-4}=x^0x4x4=x4−4=x0So x0=1x^0=1x0=1 when x≠0x \neq 0x=0.
Zero index
For any non-zero base, a0=1a^0=1a0=1.
Using a zero index
Find the value of 909^090.
The base 9 is not zero.
Use the zero index rule.
90=19^0 = 190=1A negative index means “take the reciprocal”.
Reciprocal
The reciprocal of a number is 1 divided by that number. For example, the reciprocal of 5 is 15\frac{1}{5}51, and the reciprocal of 14\frac{1}{4}41 is 4.
Negative index
For a non-zero base, a−n=1ana^{-n}=\frac{1}{a^n}a−n=an1.
Evaluating a negative power
Work out 3−23^{-2}3−2.
A negative index means write the reciprocal.
3−2=1323^{-2} = \frac{1}{3^2}3−2=321Evaluate the positive power in the denominator.
3−2=193^{-2} = \frac{1}{9}3−2=91Simplifying with a negative index
Simplify 7x5×2x−37x^5 \times 2x^{-3}7x5×2x−3.
Multiply the coefficients.
7×2=147 \times 2 = 147×2=14Add the indices of xxx.
x5×x−3=x5+(−3)=x2x^5 \times x^{-3} = x^{5+(-3)} = x^2x5×x−3=x5+(−3)=x2Combine the parts: 14x214x^214x2.
Sometimes you need to rewrite a number using the same base as the rest of the expression.
For example, 25 can be written as 525^252, and 1000 can be written as 10310^3103.
Writing as a power of the same base
Write 25×5425 \times 5^425×54 as a power of 5.
Rewrite 25 as a power of 5.
25=5225 = 5^225=52Substitute this into the expression.
25×54=52×5425 \times 5^4 = 5^2 \times 5^425×54=52×54Add the indices.
52×54=565^2 \times 5^4 = 5^652×54=56Changing a power of 1000 into a power of 10
Write 100031000^310003 as a power of 10.
Rewrite 1000 as 10310^3103.
Put this into the expression.
10003=(103)31000^3 = (10^3)^310003=(103)3Multiply the indices.
(103)3=109(10^3)^3 = 10^9(103)3=109If an index is unknown, use the index law first, then solve the simple equation.
Finding missing powers
Find kkk if z4×zk=z11z^4 \times z^k = z^{11}z4×zk=z11.
Multiplying same bases means add the indices.
z4+k=z11z^{4+k}=z^{11}z4+k=z11Equate the indices.
4+k=114+k=114+k=11Solve to get k=7k=7k=7.
A missing power in brackets
Find bbb if (h3)b=h15(h^3)^b=h^{15}(h3)b=h15.
A power of a power means multiply the indices.
(h3)b=h3b(h^3)^b = h^{3b}(h3)b=h3bEquate the indices.
3b=153b=153b=15Solve to get b=5b=5b=5.
A missing power in a division
Find aaa if x5xa=x8\frac{x^5}{x^a}=x^8xax5=x8.
Dividing same bases means subtract the indices.
x5xa=x5−a\frac{x^5}{x^a}=x^{5-a}xax5=x5−aEquate the indices.
5−a=85-a=85−a=8Solve to get a=−3a=-3a=−3.
In numerical questions, it is often quicker to simplify the powers first, then work out the final value.
Working out a value using index laws
Work out 27×2−223\frac{2^7 \times 2^{-2}}{2^3}2327×2−2.
Combine the powers of 2 by adding the top indices and subtracting the bottom index.
27×2−223=27+(−2)−3\frac{2^7 \times 2^{-2}}{2^3}=2^{7+(-2)-3}2327×2−2=27+(−2)−3Simplify the index.
27+(−2)−3=222^{7+(-2)-3}=2^227+(−2)−3=22Evaluate the final power.
22=42^2=422=4In the exam
Check the bases are the same before adding or subtracting indices.
When there are brackets, apply the outside index to the coefficient and every letter inside.
Remember the special rules: a0=1a^0=1a0=1 and a−n=1ana^{-n}=\frac{1}{a^n}a−n=an1 for non-zero aaa.
Check yourself
Can you explain the difference between 535^353 and 5 times 3?
Can you simplify an expression with coefficients, such as 6x4y2÷3x2y6x^4y^2 \div 3x^2y6x4y2÷3x2y?
Can you rewrite a negative index as a reciprocal?
Test yourself with 5 quick questions on this guide. Answer them all correctly to complete it.
Test yourself on this topic, or move on to the next guide.
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