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Electrolysis

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Question 11

The ionic half-equation for the formation of oxygen at the positive electrode during the electrolysis of dilute sulfuric acid is: 2H2O→O2+4H++4e−2\text{H}_2\text{O} \rightarrow \text{O}_2 + 4\text{H}^+ + 4\text{e}^-2H2​O→O2​+4H++4e−. In one experiment, a charge of 0.0600 faraday0.0600\text{ faraday}0.0600 faraday is passed through the solution.

a.

Calculate the amount, in moles, of oxygen formed.

[3]
b.

Calculate the volume of oxygen formed at room temperature and pressure (rtp). [The molar volume of a gas is 24 dm3 at rtp.] Give the unit in your answer.

[2]

Electrolysis Questions

  1. IGCSE
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  3. /Electrolysis