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Acids, alkalis and titrations

Acids, alkalis and titrations

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Question 1

An industrial chemist wants to determine the percentage by mass of anhydrous ethanedioic acid (H2C2O4\text{H}_2\text{C}_2\text{O}_4H2​C2​O4​) in a commercial brand of solid rust-remover.

She uses the following method:

  • Weighs a sample of the solid rust-remover.
  • Dissolves the sample in deionised water.
  • Titrates the resulting solution with standardized sodium hydroxide solution, NaOH\text{NaOH}NaOH.

The table below shows her experimental results:

MeasurementValue
Mass of rust-remover sample0.450 g0.450\text{ g}0.450 g
Concentration of NaOH\text{NaOH}NaOH solution0.125 mol/dm30.125\text{ mol/dm}^30.125 mol/dm3
Volume of NaOH\text{NaOH}NaOH solution added24.80 cm324.80\text{ cm}^324.80 cm3
a.

Calculate the amount, in moles, of NaOH\text{NaOH}NaOH in 24.80 cm324.80\text{ cm}^324.80 cm3 of 0.125 mol/dm30.125\text{ mol/dm}^30.125 mol/dm3 sodium hydroxide solution.

[2]
b.

In the titration, 2 mol2\text{ mol}2 mol of NaOH\text{NaOH}NaOH reacts with 1 mol1\text{ mol}1 mol of H2C2O4\text{H}_2\text{C}_2\text{O}_4H2​C2​O4​. Calculate the amount, in moles, of H2C2O4\text{H}_2\text{C}_2\text{O}_4H2​C2​O4​ in the rust-remover sample.

[2]
c.

Calculate the mass, in grams, of H2C2O4\text{H}_2\text{C}_2\text{O}_4H2​C2​O4​ in the rust-remover sample. [Mr of H2C2O4=90.0M_{\text{r}}\text{ of H}_2\text{C}_2\text{O}_4 = 90.0Mr​ of H2​C2​O4​=90.0]

[2]
d.

Calculate the percentage by mass of H2C2O4\text{H}_2\text{C}_2\text{O}_4H2​C2​O4​ in the rust-remover sample.

[2]
Markscheme

Acids, alkalis and titrations Questions

  1. IGCSE
  2. /Chemistry
  3. /Acids, alkalis and titrations

39 exam-style questions on Edexcel IGCSE Chemistry Acids, alkalis and titrations. Each one has a worked solution and a mark scheme showing where the marks go.

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