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Question 5
Hard

A constant force F=(6i−2j) N\mathbf{F} = (6\mathbf{i} - 2\mathbf{j})\text{ N}F=(6i−2j) N acts on a particle as it moves from a point A A\,A with position vector (i+j) m(\mathbf{i} + \mathbf{j})\text{ m}(i+j) m to a point B B\,B with position vector (5i−4j) m(5\mathbf{i} - 4\mathbf{j})\text{ m}(5i−4j) m.

Calculate the work done by this force.

14 J14\text{ J}14 J

34 J34\text{ J}34 J

38 J38\text{ J}38 J

42 J42\text{ J}42 J

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  1. GCSE
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