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5.1.4 Wave speed problems

Using the wave equation

Definition

Wave speed

The distance travelled by a wave each second.

  1. Every wave speed calculation uses the wave equation, v=fλv = f\lambdav=fλ, which you must be able to recall.
  2. Before you start, pick out the two quantities you have been given and the one you need to find.
  3. To find the speed, multiply the frequency by the wavelength: v=fλv = f\lambdav=fλ.
  4. To find the frequency, divide the speed by the wavelength: f=vλf = \dfrac{v}{\lambda}f=λv​.
  5. To find the wavelength, divide the speed by the frequency: λ=vf\lambda = \dfrac{v}{f}λ=fv​.
  6. You can check a rearrangement with simple numbers, such as v=10v = 10v=10, f=2f = 2f=2 and λ=5\lambda = 5λ=5, which fit all three forms.

Units and prefixes

  1. The equation only gives the right answer when every quantity is in its standard unit: m/s\text{m/s}m/s for speed, Hz\text{Hz}Hz for frequency and m\text{m}m for wavelength.
  2. Convert centimetres to metres by dividing by 100100100, so 45 cm=0.45 m45\ \text{cm} = 0.45\ \text{m}45 cm=0.45 m.
  3. Convert millimetres to metres by dividing by 100010001000, so 8 mm=0.008 m8\ \text{mm} = 0.008\ \text{m}8 mm=0.008 m.
  4. Convert kilohertz to hertz by multiplying by 100010001000, so 2.5 kHz=2500 Hz2.5\ \text{kHz} = 2500\ \text{Hz}2.5 kHz=2500 Hz.
  5. Convert megahertz to hertz by multiplying by 1 000 0001\,000\,0001000000, so 3.0 MHz=3.0×106 Hz3.0\ \text{MHz} = 3.0 \times 10^{6}\ \text{Hz}3.0 MHz=3.0×106 Hz.
  6. Very large or very small answers are clearest in standard form, so 0.0015 m0.0015\ \text{m}0.0015 m is written as 1.5×10−3 m1.5 \times 10^{-3}\ \text{m}1.5×10−3 m.
  7. Give the final answer to a sensible number of significant figures, usually the same as the least precise value in the question.

Multi-step problems

  1. Harder questions do not give you fff and λ\lambdaλ directly, so you must work them out from other information first.
  2. If the period is given, find the frequency first using f=1Tf = \dfrac{1}{T}f=T1​.
  3. If a distance covering several waves is given, divide it by the number of waves to get one wavelength.
  4. If you are asked how long a wave takes to travel a distance, find its speed and then use time=distancespeed\text{time} = \dfrac{\text{distance}}{\text{speed}}time=speeddistance​.
  5. Writing down each intermediate value with its unit stops you losing track, and lets the examiner award marks for each correct step.
Example

Speed of a sound wave

  • A sound wave has a frequency of 2.0 kHz2.0\ \text{kHz}2.0 kHz and a wavelength of 17 cm17\ \text{cm}17 cm.
  • Both values are converted to standard units first, giving f=2000 Hzf = 2000\ \text{Hz}f=2000 Hz and λ=0.17 m\lambda = 0.17\ \text{m}λ=0.17 m.
v=fλ v = f\lambda v=fλ v=2000×0.17 v = 2000 \times 0.17 v=2000×0.17 v=340 m/s v = 340\ \text{m/s} v=340 m/s
Example

Wavelength from a period

  • Waves on a lake have a period of 0.50 s0.50\ \text{s}0.50 s and travel at 1.2 m/s1.2\ \text{m/s}1.2 m/s.
  • The frequency is found from the period first.
f=1T=10.50=2.0 Hz f = \frac{1}{T} = \frac{1}{0.50} = 2.0\ \text{Hz} f=T1​=0.501​=2.0 Hz
  • The wave equation is then rearranged to make wavelength the subject.
λ=vf=1.22.0=0.60 m \lambda = \frac{v}{f} = \frac{1.2}{2.0} = 0.60\ \text{m} λ=fv​=2.01.2​=0.60 m
Example

Frequency and travel time on a spring

  • A wave on a long spring travels at 4.5 m/s4.5\ \text{m/s}4.5 m/s, and six complete waves fit along 3.0 m3.0\ \text{m}3.0 m of the spring.
  • One wavelength is 3.0 m÷6=0.50 m3.0\ \text{m} \div 6 = 0.50\ \text{m}3.0 m÷6=0.50 m.
f=vλ=4.50.50=9.0 Hz f = \frac{v}{\lambda} = \frac{4.5}{0.50} = 9.0\ \text{Hz} f=λv​=0.504.5​=9.0 Hz
  • The time for a wave to travel the full 3.0 m3.0\ \text{m}3.0 m of spring comes from the distance and the speed.
t=dv=3.04.5=0.67 s t = \frac{d}{v} = \frac{3.0}{4.5} = 0.67\ \text{s} t=vd​=4.53.0​=0.67 s
Common Mistake
  • Do not substitute a wavelength in centimetres or a frequency in kilohertz without converting it, because the answer will be wrong by a factor of 100100100 or 100010001000.
  • Do not multiply when you should divide, and check that a higher frequency gives a shorter wavelength in your answer.
  • Do not round intermediate values too early, because rounding errors build up in multi-step questions.
Exam technique

Setting out a calculation

  • Write the equation first, either as v=fλv = f\lambdav=fλ or already rearranged, because this alone often earns a mark.
  • Show the substitution with the numbers in standard units, so that a slip on the calculator still leaves you credit for your method.
  • Write the final answer on the answer line with its unit, such as m/s\text{m/s}m/s, Hz\text{Hz}Hz or m\text{m}m.
  • Higher tier questions expect you to rearrange the equation yourself, so practise all three forms until they are automatic.
Self review
  • What are the three rearranged forms of the wave equation?
  • What is 750 mm750\ \text{mm}750 mm in metres?
  • What is the frequency of a wave with a period of 0.20 s0.20\ \text{s}0.20 s?
  • What is the wavelength of a 500 Hz500\ \text{Hz}500 Hz sound wave travelling at 340 m/s340\ \text{m/s}340 m/s?
  • Why should you write down the equation before substituting any numbers?
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Revision notes for OCR GCSE Physics 5.1.4 Wave speed problems: explanations and worked examples.

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