Acceleration
Definition
Acceleration
The rate of change of velocity.
Definition
Deceleration
A negative acceleration, in which the velocity of an object decreases.
Definition
Magnitude
The size of a quantity, given as a number and a unit.
- Acceleration is how quickly the velocity of an object changes, so an object accelerates when it speeds up, slows down or changes direction.
- You recall acceleration from acceleration=change in velocitytime\text{acceleration} = \dfrac{\text{change in velocity}}{\text{time}}acceleration=timechange in velocity, written in symbols as a=v−uta = \dfrac{v-u}{t}a=tv−u.
- Acceleration is measured in metres per second squared, m/s2\text{m/s}^2m/s2, and an acceleration of 2 m/s22\ \text{m/s}^22 m/s2 means the velocity changes by 2 m/s2\ \text{m/s}2 m/s every second.
- When an object slows down, vvv is smaller than uuu, so the acceleration is negative and is called a deceleration.
- The magnitude of an acceleration is its size without its direction, so a car slowing at −4 m/s2-4\ \text{m/s}^2−4 m/s2 has an acceleration of magnitude 4 m/s24\ \text{m/s}^24 m/s2.
- A large acceleration needs a large change in velocity, a short time, or both.
- A fast object does not have to be accelerating, because a car moving at a steady 30 m/s30\ \text{m/s}30 m/s in a straight line has zero acceleration.
Estimating an acceleration
Definition
Estimate
An approximate value of a quantity worked out from sensible, rounded values rather than from exact measurements.
Definition
Free fall
The motion of an object when the only force acting on it is its weight.
- To estimate an acceleration, you choose sensible rounded values for the change in velocity and the time taken, then divide one by the other.
- Typical speeds give the change in velocity, so a car pulling away from traffic lights and reaching town speed changes its velocity by about 13 m/s13\ \text{m/s}13 m/s.
- The time comes from everyday experience, such as how many seconds a car takes to reach that speed.
- The answer is rounded to one significant figure, because the starting values are only estimates.
- A useful benchmark is the acceleration of an object in free fall near the Earth's surface, which is about 10 m/s210\ \text{m/s}^210 m/s2.
- Comparing an estimate with 10 m/s210\ \text{m/s}^210 m/s2 quickly shows whether it is sensible, because most everyday accelerations are smaller than this.
Typical everyday accelerations
- Starting to walk: a person reaches 1.5 m/s1.5\ \text{m/s}1.5 m/s in about 1 s1\ \text{s}1 s, so the acceleration is roughly 1.5 m/s21.5\ \text{m/s}^21.5 m/s2.
- Sprint start: an athlete leaving the blocks reaches about 10 m/s10\ \text{m/s}10 m/s in about 2 s2\ \text{s}2 s, giving roughly 5 m/s25\ \text{m/s}^25 m/s2.
- Cycling: a cyclist pulling away reaches about 6 m/s6\ \text{m/s}6 m/s in about 4 s4\ \text{s}4 s, giving about 1.5 m/s21.5\ \text{m/s}^21.5 m/s2.
- Family car: a car pulling away normally reaches about 13 m/s13\ \text{m/s}13 m/s in around 5 s5\ \text{s}5 s, giving about 3 m/s23\ \text{m/s}^23 m/s2.
- Bus or train: these speed up more gently, at about 1 m/s21\ \text{m/s}^21 m/s2 or less, so that standing passengers keep their balance.
- Lift: a lift starting or stopping accelerates at about 1 m/s21\ \text{m/s}^21 m/s2, which is why you feel slightly heavier or lighter for a moment.
- Car braking: a car braking normally slows at about 3 m/s23\ \text{m/s}^23 m/s2, and in an emergency stop on a dry road its deceleration can reach about 7 m/s27\ \text{m/s}^27 m/s2.
- Falling object: an object in free fall accelerates at about 10 m/s210\ \text{m/s}^210 m/s2, which is larger than almost every acceleration you experience in normal travel.
Example
Acceleration of a car pulling away
- A car waiting at traffic lights pulls away and reaches about 13 m/s13\ \text{m/s}13 m/s in about 5 s5\ \text{s}5 s.
- The values are estimates, so the acceleration is about 3 m/s23\ \text{m/s}^23 m/s2.
Example
Deceleration of a train
- A train approaching a station slows from 40 m/s40\ \text{m/s}40 m/s to rest over about 60 s60\ \text{s}60 s.
- The negative sign shows that the train is slowing down, so the magnitude of its deceleration is about 0.7 m/s20.7\ \text{m/s}^20.7 m/s2.
Common Mistake
- Do not confuse a high speed with a large acceleration, because acceleration depends on how quickly the velocity changes, not on how fast the object is moving.
- Do not use only the final velocity in a=v−uta = \dfrac{v-u}{t}a=tv−u, because the initial velocity must be subtracted first.
- Do not give an acceleration in m/s\text{m/s}m/s, because its unit is m/s2\text{m/s}^2m/s2.
Exam technique
Estimating accelerations
- Write down the values you have chosen for the change in velocity and the time before you calculate, so that your reasoning can be followed.
- Choose values from typical speeds you know, such as 13 m/s13\ \text{m/s}13 m/s for a car in town, rather than guessing at random.
- Round your final answer, because an estimate given to four significant figures suggests a false precision.
- Check your answer against 10 m/s210\ \text{m/s}^210 m/s2, and look again if an everyday acceleration comes out much larger than this.
Self review
- Recall the equation that links acceleration, change in velocity and time.
- State the unit of acceleration.
- Estimate the acceleration of a cyclist who reaches 6 m/s6\ \text{m/s}6 m/s from rest in 3 s3\ \text{s}3 s.
- State the acceleration of an object in free fall near the Earth's surface.
- Explain why a car moving at a steady 30 m/s30\ \text{m/s}30 m/s in a straight line has zero acceleration.