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8.1.3 Ratios, units and rates on the road

Ratios and proportion

Definition

Ratio

A comparison of two quantities that shows how many times larger one is than the other.

Definition

Directly proportional

A relationship between two quantities in which multiplying one by a factor multiplies the other by the same factor.

  1. A ratio compares two quantities by dividing one by the other, so it tells you how many times larger one quantity is than the other.
  2. A coach that travels 90 km90\ \text{km}90 km while a cyclist travels 30 km30\ \text{km}30 km has covered 333 times the distance, a ratio of 3:13:13:1.
  3. Two quantities are directly proportional when doubling one doubles the other, tripling one triples the other, and so on.
  4. For a vehicle moving at a constant speed, the distance travelled is directly proportional to the time taken.
  5. Proportional reasoning uses this pattern to scale a known value up or down without starting the calculation again.
  6. One method is to find the value for one unit first and then multiply by the number of units needed.
  7. A second method is to find the scale factor between the two situations and multiply the known value by it.
Example

Scaling a journey

  • A lorry travelling at a constant speed covers 36 km36\ \text{km}36 km in 303030 minutes.
  • To find the distance it covers in 505050 minutes at the same speed, first work out the distance per minute:
36 km30 min=1.2 km per minute \frac{36\ \text{km}}{30\ \text{min}} = 1.2\ \text{km per minute} 30 min36 km​=1.2 km per minute distance in 50 min=1.2 km per minute×50 min=60 km \text{distance in } 50\ \text{min} = 1.2\ \text{km per minute} \times 50\ \text{min} = 60\ \text{km} distance in 50 min=1.2 km per minute×50 min=60 km
  • The scale factor method gives the same answer, because 5030×36 km=60 km\dfrac{50}{30} \times 36\ \text{km} = 60\ \text{km}3050​×36 km=60 km.

Converting to SI units

Definition

SI unit

A unit from the international system of standard units used in science, such as the metre, the kilogram and the second.

  1. Physics equations such as distance=speed×time\text{distance} = \text{speed} \times \text{time}distance=speed×time and F=maF = maF=ma only give correct answers when every quantity is in SI units.
  2. The SI unit of distance is the metre, m\text{m}m, the SI unit of time is the second, s\text{s}s, and the SI unit of mass is the kilogram, kg\text{kg}kg.
  3. Road information is often given in non-SI units, such as kilometres, miles, hours, minutes and tonnes, so it must be converted before it is used.
  4. A conversion multiplies by a ratio equal to one, such as 1000 m1 km\dfrac{1000\ \text{m}}{1\ \text{km}}1 km1000 m​, so the size of the quantity stays the same and only the unit changes.
  5. The conversions you need most often on the road are these:
    1. 1 km=1000 m1\ \text{km} = 1000\ \text{m}1 km=1000 m
    2. 1 mile≈1600 m1\ \text{mile} \approx 1600\ \text{m}1 mile≈1600 m
    3. 1 minute=60 s1\ \text{minute} = 60\ \text{s}1 minute=60 s and 1 hour=3600 s1\ \text{hour} = 3600\ \text{s}1 hour=3600 s
    4. 1 tonne=1000 kg1\ \text{tonne} = 1000\ \text{kg}1 tonne=1000 kg and 1 g=0.001 kg1\ \text{g} = 0.001\ \text{kg}1 g=0.001 kg
  6. Converting to a smaller unit gives a larger number, so 2.5 km2.5\ \text{km}2.5 km becomes 2500 m2500\ \text{m}2500 m.

Converting road speeds

  1. To change km/h\text{km/h}km/h into m/s\text{m/s}m/s, convert the kilometres into metres and the hours into seconds, which means multiplying by 100010001000 and dividing by 360036003600.
  2. Multiplying by 10003600\dfrac{1000}{3600}36001000​ is the same as dividing by 3.63.63.6, so speed in m/s=speed in km/h3.6\text{speed in m/s} = \dfrac{\text{speed in km/h}}{3.6}speed in m/s=3.6speed in km/h​.
  3. To change m/s\text{m/s}m/s back into km/h\text{km/h}km/h, multiply by 3.63.63.6.
  4. To change miles per hour into m/s\text{m/s}m/s, multiply by 160016001600 and divide by 360036003600, which is close to multiplying by 0.450.450.45.
  5. Useful results to remember are 303030 mph ≈13 m/s\approx 13\ \text{m/s}≈13 m/s and 707070 mph ≈31 m/s\approx 31\ \text{m/s}≈31 m/s.
  6. A speed in m/s\text{m/s}m/s is always a smaller number than the same speed in km/h\text{km/h}km/h or mph, which gives a fast way to spot a conversion done the wrong way round.
Example

Motorway speed in m/s

  • A car travels at 707070 mph on a motorway.
  • Convert the miles into metres and the hours into seconds:
70 mph=70×1600 m3600 s=112 000 m3600 s=31 m/s 70\ \text{mph} = \frac{70 \times 1600\ \text{m}}{3600\ \text{s}} = \frac{112\,000\ \text{m}}{3600\ \text{s}} = 31\ \text{m/s} 70 mph=3600 s70×1600 m​=3600 s112000 m​=31 m/s
  • The car travels about 313131 metres in every second.
Example

A speed limit in km/h

  • A speed limit abroad is shown as 90 km/h90\ \text{km/h}90 km/h.
speed in m/s=903.6=25 m/s \text{speed in m/s} = \frac{90}{3.6} = 25\ \text{m/s} speed in m/s=3.690​=25 m/s
  • The limit is 25 m/s25\ \text{m/s}25 m/s, a little below the typical speed of a car on a UK motorway.

Computing rates

Definition

Rate

The change in a quantity per unit of time.

  1. A rate tells you how much a quantity changes in each unit of time, so speed is the rate of change of distance and acceleration is the rate of change of velocity.
  2. A rate is found by dividing the change in a quantity by the time taken for that change.
  3. The unit of a rate is the unit of the quantity divided by the unit of time, so a distance in m\text{m}m divided by a time in s\text{s}s gives m/s\text{m/s}m/s.
  4. The average speed for a whole journey is the total distance divided by the total time, including any time spent stopped.
  5. Every quantity in a rate calculation must be in matching units, so a speed in km/h\text{km/h}km/h must be converted to m/s\text{m/s}m/s before it is divided by a time in seconds.
Example

Acceleration from a speed in km/h

  • A car speeds up from rest to 54 km/h54\ \text{km/h}54 km/h in 6.0 s6.0\ \text{s}6.0 s.
  • Convert the final speed into m/s\text{m/s}m/s first:
v=543.6=15 m/s v = \frac{54}{3.6} = 15\ \text{m/s} v=3.654​=15 m/s a=v−ut=15 m/s−0 m/s6.0 s=2.5 m/s2 a = \frac{v-u}{t} = \frac{15\ \text{m/s} - 0\ \text{m/s}}{6.0\ \text{s}} = 2.5\ \text{m/s}^2 a=tv−u​=6.0 s15 m/s−0 m/s​=2.5 m/s2
  • Leaving the speed in km/h\text{km/h}km/h would have given 999, which is the wrong value with no meaningful unit.
Example

Average speed of a bus journey

  • A bus travels 12 km12\ \text{km}12 km in 404040 minutes, including its stops.
12 km=12 000 m40 min=40×60 s=2400 s 12\ \text{km} = 12\,000\ \text{m} \qquad 40\ \text{min} = 40 \times 60\ \text{s} = 2400\ \text{s} 12 km=12000 m40 min=40×60 s=2400 s average speed=12 000 m2400 s=5.0 m/s \text{average speed} = \frac{12\,000\ \text{m}}{2400\ \text{s}} = 5.0\ \text{m/s} average speed=2400 s12000 m​=5.0 m/s
  • This is about half the typical speed of a moving bus, because of the time spent at stops.
Common Mistake
  • Do not multiply by 3.63.63.6 when converting from km/h\text{km/h}km/h to m/s\text{m/s}m/s, because the answer in m/s\text{m/s}m/s must be the smaller number.
  • Do not write 1.51.51.5 hours as 111 hour 505050 minutes, because half an hour is 303030 minutes.
  • Do not substitute a time in minutes or a mass in tonnes into a physics equation without converting it into SI units first.
Exam technique

Showing unit conversions

  • Write each conversion as a separate line before you substitute into an equation, so that the conversion can earn credit even if a later step goes wrong.
  • Keep the units next to the numbers in your working, because a unit that does not work out properly warns you that a conversion is missing.
  • After converting, check the size of the answer against a typical speed, so 707070 mph should come out close to 30 m/s30\ \text{m/s}30 m/s.
Self review
  • State the SI units of distance, time and mass.
  • Convert 72 km/h72\ \text{km/h}72 km/h into m/s\text{m/s}m/s.
  • Convert 303030 mph into m/s\text{m/s}m/s, using 1 mile≈1600 m1\ \text{mile} \approx 1600\ \text{m}1 mile≈1600 m.
  • Explain what is meant by two quantities being directly proportional.
  • Calculate, in m/s\text{m/s}m/s, the average speed of a car that travels 45 km45\ \text{km}45 km in 303030 minutes.
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8.1.3 Ratios, units and rates on the road Revision Guide

  1. GCSE
  2. /Physics
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Revision notes for OCR GCSE Physics 8.1.3 Ratios, units and rates on the road: explanations and worked examples.

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