3.2.1 Series and parallel circuits
Series circuits
Series circuit
A circuit in which the components are connected one after another in a single loop, so there is only one path for the charge to flow through.
- In a series circuit, the components are joined end to end so that they form a single loop with the power supply.
- There is only one path around the circuit, so all of the charge that leaves the supply passes through every component in turn.
- The current is the same at every point in a series circuit, because charge is not used up by the components and cannot leave the loop anywhere.
- An ammeter placed before the first lamp, between two lamps or after the last lamp gives the same reading.
- The potential difference of the supply is shared between the components, so the potential differences across the components add up to the potential difference across the supply.
- For two components in series, this is written as Vsupply=V1+V2V_{\text{supply}} = V_1 + V_2Vsupply=V1+V2.
- The component with the larger resistance takes the larger share of the potential difference.
- In terms of energy, each coulomb of charge is given energy by the supply and then transfers part of that energy in each component it passes through.
- The energy transferred by each coulomb in all of the components adds up to the energy it was given by the supply.
- If one component is removed, breaks or is switched off, the single loop is broken and every component stops working.
- Old-style strings of festive lights were wired in series, so one failed bulb made the whole string go dark.
- One switch placed anywhere in a series circuit turns all of the components on or off together.
Parallel circuits
Parallel circuit
A circuit in which the components are connected in separate branches between the same two points, so there is more than one path for the charge to flow through.
Junction
A point in a circuit where a conducting path splits into two or more branches, or where branches join back together.
- In a parallel circuit, each component is placed on its own branch, and every branch is connected between the same two points of the circuit.
- The current from the supply splits at a junction, part of it flows along each branch, and the branch currents recombine at a second junction.
- The total current from the supply is equal to the sum of the branch currents, written Itotal=I1+I2I_{\text{total}} = I_1 + I_2Itotal=I1+I2 for two branches.
- A branch with a smaller resistance carries a larger current than a branch with a larger resistance.
- Each branch is connected directly across the supply, so the potential difference across every branch is the same and equal to the supply potential difference.
- In terms of energy, each coulomb of charge passes through only one branch, so it transfers all of the energy it was given by the supply in that branch.
- Each branch can be switched on and off independently, and a break in one branch does not stop charge flowing through the others.
- The lights and sockets in a house are wired in parallel, so every appliance receives the full mains potential difference and switching off the kettle does not switch off the fridge.
- Adding another identical lamp in series shares the supply potential difference between more lamps, so each lamp gets a smaller share and glows more dimly.
- Adding another identical lamp in parallel gives it the full supply potential difference, so it glows as brightly as the lamps already there, while the total current from the supply increases.

Comparing the two circuits
- Paths: a series circuit has one path for the charge, whereas a parallel circuit has a separate path through each branch.
- Current: the current is the same everywhere in a series circuit, whereas in a parallel circuit the branch currents add up to the total current.
- Potential difference: the supply potential difference is shared between series components, whereas each parallel branch has the full supply potential difference across it.
- Energy: each coulomb transfers some of its energy in every series component, whereas it transfers all of its energy in the one parallel branch it passes through.
- Faults and switching: one break stops a whole series circuit, whereas a break in one parallel branch leaves the other branches working.
Positioning measuring instruments
Ammeter
A meter connected in series with a component to measure the current through it.
Voltmeter
A meter connected in parallel across a component to measure the potential difference across it.
- An ammeter measures the current through a component in amperes, A\text{A}A.
- To fit an ammeter, the circuit is broken at the point of interest and the ammeter is connected in series so that the same charge flows through it.
- An ammeter has a very low resistance, so it does not noticeably reduce the current it is measuring.
- In a series circuit, an ammeter can go anywhere in the loop because the current is the same at every point.
- In a parallel circuit, an ammeter in the main part of the circuit measures the total current, while an ammeter in a branch measures only the current in that branch.
- A voltmeter measures the potential difference across a component in volts, V\text{V}V.
- A voltmeter is connected in parallel with the component, with one lead on each side of it, and the circuit does not need to be broken.
- A voltmeter has a very high resistance, so almost no current flows through it and it does not change the circuit it is measuring.
- A voltmeter across the supply measures the supply potential difference, which equals the sum of the series voltmeter readings or the reading across any one parallel branch.
- The positive terminal of each meter should be connected to the side of the circuit nearest the positive terminal of the supply, or a digital meter shows a negative reading and an analogue needle moves the wrong way.
Using the rules to predict meter readings
- A 12 V12\ \text{V}12 V battery is connected in series with lamp X and lamp Y.
- A voltmeter across lamp X reads 5.0 V5.0\ \text{V}5.0 V, and the potential differences across the two lamps must add up to the battery potential difference.
- An ammeter next to lamp X reads 0.40 A0.40\ \text{A}0.40 A, so an ammeter next to lamp Y also reads 0.40 A0.40\ \text{A}0.40 A because the current is the same everywhere in the loop.
- The two lamps are now reconnected in parallel with the same battery, and the branch currents are 0.50 A0.50\ \text{A}0.50 A through X and 0.70 A0.70\ \text{A}0.70 A through Y.
- A voltmeter across either lamp now reads 12 V12\ \text{V}12 V, because each branch is connected directly across the battery.
Measuring current and potential difference in series and parallel circuits
- Aim: to build series and parallel circuits from circuit diagrams and measure how the current and potential difference behave in each.
- Apparatus: a low-voltage d.c. power supply set to 6 V6\ \text{V}6 V (or a battery of four 1.5 V1.5\ \text{V}1.5 V cells), a switch, two identical filament lamps in holders, a digital ammeter, a digital voltmeter and connecting leads with crocodile clips.
- Method, the series circuit:
- With the supply switched off, connect the supply, switch, lamp A and lamp B in one loop, following the circuit diagram.
- Insert the ammeter between the supply and lamp A, close the switch, and record the current once the reading is steady.
- Open the switch, move the ammeter to the gap between the two lamps and then to the gap after lamp B, recording the current each time.
- Connect the voltmeter across lamp A, then across lamp B, then across the supply, and record each potential difference.
- Method, the parallel circuit:
- Rebuild the circuit so that lamp A and lamp B are on separate branches, each joined to the supply at the same two junctions.
- Record the current with the ammeter in the main lead from the supply, then with it in the branch containing lamp A, then in the branch containing lamp B.
- Connect the voltmeter across lamp A, across lamp B and across the supply, and record each potential difference.
- Repeat every reading twice more after switching off and on again, and calculate a mean for each position.
- Results: in the series circuit, the ammeter gives about the same reading, such as 0.21 A0.21\ \text{A}0.21 A, at every position, and the two lamp readings, such as 3.0 V3.0\ \text{V}3.0 V each, add up to the supply reading of 6.0 V6.0\ \text{V}6.0 V.
- In the parallel circuit, each branch carries about 0.30 A0.30\ \text{A}0.30 A, the main lead carries about 0.60 A0.60\ \text{A}0.60 A, and the voltmeter reads about 6.0 V6.0\ \text{V}6.0 V across each lamp and across the supply.
- Conclusion: current is the same everywhere in a series circuit and potential difference is shared, whereas in a parallel circuit potential difference is the same across each branch and the branch currents add up to the total current.
- Watch out: check the zero reading of each meter before connecting it, check every meter terminal is the right way round, and keep the same lamps and supply setting for both circuits so the results can be compared.
- Safety: open the switch before changing any connection, never connect a lead straight across the supply terminals, and do not touch the lamps after use because the glass becomes hot.
- Do not say that current is used up by the components, because the current leaving a series component is the same as the current entering it.
- Do not write that potential difference flows through a component, because current flows through a component while potential difference is measured across it.
- Do not connect an ammeter in parallel or a voltmeter in series, because the ammeter would carry a very large current and the voltmeter would stop the current in the circuit.
Describing series and parallel circuits
- When a question asks you to describe the differences between series and parallel circuits, make each point a direct comparison that mentions both circuits, joined by whereas.
- Name the quantity in each comparison, so say current, potential difference or number of paths instead of writing that series circuits are weaker.
- When you add meters to a circuit diagram, draw the ammeter in the line of the circuit and the voltmeter on a separate loop around the component, because examiners check the position of each meter.
- When a question gives some meter readings, use the series and parallel rules to work out the missing readings before attempting anything else.
- State how the current at different points in a series circuit compares.
- Describe how the supply potential difference is shared in a series circuit.
- State the potential difference across each branch of a parallel circuit connected to a 9 V9\ \text{V}9 V battery.
- Explain why switching off one appliance at home does not switch off the others.
- Describe how an ammeter and a voltmeter are connected to measure the current through and the potential difference across a lamp.
3.2.2 Circuit symbols and circuit diagrams
Direct current circuits
Direct current
A current in which charge flows around a circuit in one direction only.
Conventional current
The direction of current shown on circuit diagrams, from the positive terminal of the supply, around the circuit, to the negative terminal.
- A d.c. circuit is a circuit in which the current always flows in the same direction, supplied by a cell, a battery or a d.c. power supply.
- Every d.c. supply has two terminals, a positive terminal (+++) and a negative terminal (−-−).
- In a metal wire, the moving charges are electrons, which are negatively charged, so they leave the negative terminal, travel around the circuit and return to the positive terminal.
- The direction of current was chosen before electrons were discovered, and scientists agreed to show current flowing from positive to negative.
- This agreed direction, called conventional current, is still used on every circuit diagram.
- Conventional current flows out of the positive terminal, around the circuit and back into the negative terminal, which is the opposite direction to the flow of electrons.
- The positive and negative terminals matter whenever a component only works one way round, such as a diode, or whenever a meter has its own positive and negative terminals.
Circuit diagrams
Circuit diagram
A drawing that uses standard symbols to show how the components of a circuit are connected together.
- A circuit diagram uses standard symbols instead of pictures, so that anyone can read it in the same way whatever the real components look like.
- Connecting wires are drawn as straight lines, usually horizontal or vertical, so that most circuit diagrams look like a set of rectangles.
- A junction, where wires are joined, is shown by a solid dot, while two lines that cross without a dot are not connected.
- A circuit diagram shows how the components are connected, not where they sit on the bench or how long the wires are.
- Connecting wires are treated as having no resistance, so a long wire on a diagram behaves exactly like a short one.
- A complete circuit is a closed loop of conductors running from one terminal of the supply, through the components, back to the other terminal.
- Any gap in the loop, apart from a switch that is meant to be open, means that no current can flow.
Supplies and switches
Cell
A device that transfers energy from its chemical store to provide a potential difference between its positive and negative terminals.
Battery
Two or more cells connected together in series to provide a larger potential difference than one cell alone.
- A cell is drawn as two parallel lines of different lengths, where the long thin line is the positive terminal and the short thick line is the negative terminal.
- A battery is drawn as two or more cell symbols joined together, sometimes with a dashed line between the first and last cell.
- When the cells all face the same way, the potential difference of the battery is the sum of the potential differences of the cells, so two 1.5 V1.5\ \text{V}1.5 V cells give 3.0 V3.0\ \text{V}3.0 V.
- A d.c. power supply is usually drawn as two small open circles marked +++ and −-−, sometimes labelled with the potential difference it is set to.
- On a laboratory power supply, the positive terminal is normally red and the negative terminal is normally black.
- An open switch is drawn as a short line hinged at one end and lifted away from the contact, showing a gap that breaks the circuit.
- A closed switch is drawn with the line lying flat against the contact, showing that the circuit is complete.
Component symbols
Variable resistor
A resistor whose resistance can be adjusted to change the current in a circuit.
- A fixed resistor is drawn as a rectangle, and it has a set resistance that limits the current in a circuit.
- A variable resistor is drawn as a rectangle with a diagonal arrow through it, and moving its slider changes its resistance and so changes the current.
- A filament lamp is drawn as a circle with a cross inside it.
- A diode is drawn as a triangle pointing at a short bar, with the wire passing straight through both.
- The triangle points in the direction in which conventional current is allowed to flow through the diode.
- A light-dependent resistor (LDR) is drawn as a resistor rectangle, usually inside a circle, with two arrows pointing towards it to show light falling on it.
- An NTC thermistor is drawn as a resistor rectangle with a diagonal line through it that ends in a short horizontal tail.
- An ammeter is drawn as a circle containing the letter A, and a voltmeter is drawn as a circle containing the letter V.
- An ammeter is drawn in the line of the circuit, while a voltmeter is drawn on its own short loop that joins the circuit on either side of the component it measures.

Drawing and reading diagrams
- Draw circuit diagrams with a ruler and a sharp pencil, using only the standard symbols.
- Draw the wires so that each loop is closed, with no gaps except at an open switch.
- Mark every junction with a dot, and draw the cell or battery so that its long and short lines are clear.
- To read a diagram, start at the positive terminal and trace the path of conventional current around the circuit back to the negative terminal.
- Components that the current passes through one after another, with no junction between them, are in series.
- Components on separate branches between the same two junctions are in parallel.
- Check which way round any diode is drawn, because a diode pointing against the conventional current from the supply blocks the current in that part of the circuit.
Reading a circuit diagram
- A circuit diagram shows two 1.5 V1.5\ \text{V}1.5 V cells facing the same way, a closed switch, a fixed resistor and a diode, all in one loop.
- The two cells form a battery with a potential difference of 1.5 V+1.5 V=3.0 V1.5\ \text{V} + 1.5\ \text{V} = 3.0\ \text{V}1.5 V+1.5 V=3.0 V.
- Conventional current leaves the long line of the battery and travels round the loop towards the short line.
- The triangle of the diode points in the same direction as this conventional current, so the diode lets the current pass and the circuit carries a current.
- If the battery is turned round, the conventional current tries to flow against the triangle of the diode, so there is no current in the loop.
Building a circuit from a circuit diagram
- Aim: to build a working circuit from a circuit diagram and check that every connection matches the diagram.
- Apparatus: a circuit diagram showing a d.c. power supply, a switch, a fixed resistor, a filament lamp, an ammeter and a voltmeter, the matching real components, a low-voltage d.c. power supply set to 6 V6\ \text{V}6 V and connecting leads with crocodile clips.
- Method, identifying the parts:
- Match each real component to its symbol on the diagram, and find the positive and negative terminals of the supply and of each meter.
- Lay the components out on the bench in roughly the same shape as the diagram, which makes the connections easier to follow.
- Method, wiring the circuit:
- With the supply switched off and the switch open, start at the positive terminal of the supply and connect the components of the main loop one after another, following the diagram.
- Fit the ammeter in the line of the loop, with its positive terminal on the side nearer the positive terminal of the supply.
- Add the voltmeter last, clipping its leads to either side of the component it is drawn across.
- Trace each lead with your finger and tick off the matching line on the diagram, so that every connection is checked once.
- Method, testing the circuit:
- Switch on the supply, close the switch briefly and check that the lamp lights and that both meters give a sensible positive reading.
- If nothing happens, open the switch and check each connection against the diagram again, looking for a loose clip or a gap in the loop.
- Results: a correctly built circuit lights the lamp, the ammeter shows a current and the voltmeter shows a potential difference smaller than the supply setting.
- Conclusion: following the diagram connection by connection produces a circuit that behaves as the diagram predicts.
- Watch out: a negative meter reading means the meter has been connected the wrong way round, and a voltmeter reading of zero with the lamp off usually means the loop is broken somewhere.
- Safety: keep the supply switched off while connecting leads, keep the potential difference low, and never join a lead straight across the two terminals of the supply.
- Do not mix up the lines of the cell symbol, because the long line is positive and the short line is negative.
- Do not draw a lamp as an empty circle, because the cross inside the circle is what identifies a filament lamp.
- Do not forget the junction dots, because two lines crossing without a dot are not joined.
- Do not confuse conventional current with electron flow, because electrons move from negative to positive, in the opposite direction to the current shown on diagrams.
Drawing circuit diagrams
- When you draw a circuit, use a ruler, close every loop and check that each symbol matches the component named in the question.
- Draw the voltmeter on a separate loop across the component, because a voltmeter drawn in the line of the circuit is marked as wrong.
- When a question shows a diagram containing a diode, check which way the triangle points before deciding whether there is a current.
- When you are asked to identify a component, describe its symbol precisely, such as a rectangle with a diagonal arrow through it for a variable resistor.
- State which line of a cell symbol is the positive terminal.
- Describe the direction of conventional current around a circuit.
- Describe the circuit symbol for an NTC thermistor.
- State what a solid dot shows on a circuit diagram.
- Explain why a diode pointing against the conventional current stops the current in its part of the circuit.
3.2.3 Current, potential difference and resistance
Current
Electric current
The rate of flow of electric charge.
- Current, symbol III, is the rate of flow of charge around a circuit.
- Current is measured in amperes, unit A\text{A}A, often shortened to amps, using an ammeter connected in series.
- Small currents are often given in milliamperes, where 1 mA=0.001 A1\ \text{mA} = 0.001\ \text{A}1 mA=0.001 A.
- A current can only flow when there is a closed circuit and a source of potential difference, such as a cell, to push the charge around it.
Potential difference
Potential difference
The energy transferred per unit charge as the charge passes between two points in a circuit.
Volt
The unit of potential difference, equal to one joule of energy transferred for each coulomb of charge.
- Potential difference, symbol VVV, is the energy transferred per unit charge as the charge moves between two points in a circuit.
- Potential difference is measured in volts, unit V\text{V}V, using a voltmeter connected in parallel across the component.
- The definition can be written as an equation, V=EQV = \dfrac{E}{Q}V=QE, where EEE is the energy transferred in joules, J\text{J}J, and QQQ is the charge in coulombs, C\text{C}C.
- This means that 1 V=1 J/C1\ \text{V} = 1\ \text{J/C}1 V=1 J/C, so a potential difference of 1 V1\ \text{V}1 V transfers 1 J1\ \text{J}1 J of energy for every coulomb of charge.
- The potential difference across a cell tells you how much energy the cell gives to each coulomb of charge that passes through it.
- A 9 V9\ \text{V}9 V battery gives each coulomb of charge 9 J9\ \text{J}9 J of energy.
- The potential difference across a component tells you how much energy each coulomb transfers in that component, for example to the thermal store of a resistor or away from a lamp by light.
- The potential difference of the supply is what drives charge around a circuit, so a larger supply potential difference pushes more charge through a component every second.
Resistance
Resistance
A measure of how much a component opposes the flow of charge through it.
Ohm
The unit of resistance, equal to the resistance of a component that carries a current of one ampere when the potential difference across it is one volt.
- Resistance, symbol RRR, is a measure of how strongly a component opposes the flow of charge through it.
- Resistance is measured in ohms, unit Ω\OmegaΩ, and large resistances are often given in kilohms, where 1 kΩ=1000 Ω1\ \text{k}\Omega = 1000\ \Omega1 kΩ=1000 Ω.
- In a metal, the current is a flow of free electrons, which keep colliding with the ions that make up the metal.
- Each collision slows the electrons down and transfers energy to the ions, so the more often the electrons collide, the greater the resistance.
- Connecting wires are made of copper and have a very small resistance, while resistors are made to have a particular, much larger resistance.
How the three quantities are linked
- The current through a component depends on both the potential difference across it and its resistance.
- For a component with a fixed resistance, a larger potential difference produces a larger current, because each coulomb is pushed through with more energy.
- For a fixed potential difference, a larger resistance produces a smaller current, because the component opposes the flow of charge more strongly.
- The resistance of a component is found by dividing the potential difference across it by the current through it, R=VIR = \dfrac{V}{I}R=IV.
- To find a resistance, the potential difference and the current must be measured at the same time on the same component.
- Current: symbol III, measured in amperes, A\text{A}A, with an ammeter in series.
- Potential difference: symbol VVV, measured in volts, V\text{V}V, with a voltmeter in parallel.
- Resistance: symbol RRR, measured in ohms, Ω\OmegaΩ, and calculated from readings of VVV and III.
Finding a resistance from meter readings
- A voltmeter across a resistor reads 6.0 V6.0\ \text{V}6.0 V, and the ammeter in series with it reads 0.30 A0.30\ \text{A}0.30 A.
- The supply is then turned down until the resistor has 3.0 V3.0\ \text{V}3.0 V across it, and the current falls to 0.15 A0.15\ \text{A}0.15 A.
- Halving the potential difference halved the current, and the resistance of this resistor stayed the same.
Working with units
- A component has 5.0 V5.0\ \text{V}5.0 V across it and carries a current of 2.0 mA2.0\ \text{mA}2.0 mA.
- The current is converted to amperes before it is used.
- A 12 V12\ \text{V}12 V supply then drives 36 C36\ \text{C}36 C of charge through a heater, and rearranging the definition of potential difference gives the energy transferred.
Measuring the resistance of components
- Aim: to measure the potential difference across and the current through several components and calculate the resistance of each one.
- Apparatus: a low-voltage d.c. power supply, a switch, an ammeter, a voltmeter, connecting leads, and the components to test, such as two fixed resistors of unknown value, a filament lamp and a 50 cm50\ \text{cm}50 cm length of resistance wire held between two crocodile clips.
- Method, setting up:
- Connect the power supply, the switch, the ammeter and the first component in series.
- Connect the voltmeter in parallel across the component only, not across the ammeter as well.
- Set the power supply to a low potential difference, such as 2 V2\ \text{V}2 V.
- Method, taking readings:
- Close the switch, wait for the readings to settle, and record the current and the potential difference together.
- Open the switch straight away, so the component does not warm up between readings.
- Repeat the measurement twice more and calculate a mean current and a mean potential difference.
- Replace the component with the next one and repeat, keeping the supply setting the same.
- Results: record the mean potential difference, mean current and calculated resistance for each component, for example 2.0 V2.0\ \text{V}2.0 V and 0.10 A0.10\ \text{A}0.10 A for a resistor, giving 20 Ω20\ \Omega20 Ω.
- Conclusion: at the same potential difference, the component with the larger resistance carries the smaller current.
- Watch out: check both meters read zero before the switch is closed, and record each reading to the full resolution of the meter.
- Safety: use a low potential difference, open the switch between readings, and let the lamp and the wire cool before touching them.
- Do not use the word voltage when you mean potential difference, and do not use amps as the name of the quantity, because the quantity is current.
- Do not say that current is used up in a component, because the energy carried by the charge is transferred while the current stays the same.
- Do not divide the readings the wrong way up, because resistance is potential difference divided by current.
Quantities and units
- Learn each quantity with its symbol, unit and the meter that measures it, because one-mark questions often ask for exactly these.
- Convert mA\text{mA}mA to A\text{A}A and kΩ\text{k}\OmegakΩ to Ω\OmegaΩ before you substitute into any equation.
- When you describe how the current changes, say what is being kept constant, such as the current increases when the potential difference increases for the same resistance.
- Write the unit with every final answer, using Ω\OmegaΩ for resistance, because a correct number without a unit can lose the mark.
- State the unit of potential difference and the meter used to measure it.
- Define potential difference.
- Describe what happens to the current through a fixed resistor when the potential difference across it increases.
- Explain, in terms of electrons, why a metal has resistance.
- Calculate the resistance of a component with 4.5 V4.5\ \text{V}4.5 V across it and a current of 0.15 A0.15\ \text{A}0.15 A through it.
3.2.4 Ohm's law
The resistance equation
- Potential difference, current and resistance are linked by the equation V=IRV = IRV=IR, which you must be able to recall and apply.
- VVV is the potential difference in volts, V\text{V}V.
- III is the current in amperes, A\text{A}A.
- RRR is the resistance in ohms, Ω\OmegaΩ.
- The equation can be rearranged to find whichever quantity is unknown.
- To find the current, divide the potential difference by the resistance, I=VRI = \dfrac{V}{R}I=RV.
- To find the resistance, divide the potential difference by the current, R=VIR = \dfrac{V}{I}R=IV.
- Values given in milliamperes or kilohms must be changed to amperes and ohms before they are substituted.
- For a component whose resistance does not change, the equation shows that doubling the potential difference doubles the current.
- For a fixed potential difference, doubling the resistance halves the current.
Constant resistance
Ohm's law
The current through a conductor at constant temperature is directly proportional to the potential difference across it.
- For some resistors, the resistance stays the same as the current through them changes.
- A fixed resistor, or a metal wire kept at a constant temperature, behaves in this way.
- For these components, every pair of readings gives the same value of VI\dfrac{V}{I}IV, so the current is directly proportional to the potential difference.
- This behaviour is described by Ohm's law, and a component that obeys it is called an ohmic conductor.
- The condition at constant temperature is part of the law, because heating a metal changes its resistance.
Changing resistance
- For other components, the resistance changes as the current changes.
- The resistance of a filament lamp increases as the current through it increases.
- The resistance of an NTC thermistor decreases as it gets warmer, and the resistance of an LDR decreases as more light falls on it.
- For these components, the value of VI\dfrac{V}{I}IV is different for different pairs of readings, so the current is not directly proportional to the potential difference.
- To decide whether a component has a constant resistance, calculate R=VIR = \dfrac{V}{I}R=IV for several pairs of readings and compare the answers.
- If the values agree, allowing for small measurement errors, the resistance is constant.
- If the values rise or fall steadily as the current increases, the resistance is changing.
Resistance of a wire
- The resistance of a metal wire depends on its length, its thickness, the material it is made from and its temperature.
- A longer wire has a larger resistance, because each electron makes more collisions with ions as it travels along it.
- For a wire of one material and thickness at constant temperature, the resistance is directly proportional to the length.
- Doubling the length of the wire doubles its resistance.
- A thinner wire has a larger resistance than a thicker wire of the same length and material.
Finding a current
- A resistor of 12 Ω12\ \Omega12 Ω is connected to a 3.0 V3.0\ \text{V}3.0 V cell.
- The same resistor is then connected to a 6.0 V6.0\ \text{V}6.0 V battery.
- Doubling the potential difference has doubled the current, because the resistance of the resistor is constant.
Finding a potential difference
- A current of 2.5 mA2.5\ \text{mA}2.5 mA flows through a 4.8 kΩ4.8\ \text{k}\Omega4.8 kΩ resistor.
- Both values are first changed to base units.
Resistance and the length of a wire
- Aim: to investigate how the resistance of a wire depends on its length.
- Apparatus: a 1.00 m1.00\ \text{m}1.00 m length of thin constantan wire taped flat along a metre rule, two crocodile clips, a single 1.5 V1.5\ \text{V}1.5 V cell or a power supply set to 2 V2\ \text{V}2 V, a switch, a digital ammeter, a digital voltmeter and connecting leads.
- Method, setting up:
- Clip one crocodile clip to the wire exactly at the 0 cm0\ \text{cm}0 cm mark of the ruler, and connect the cell, switch, ammeter and wire in series.
- Fix the second crocodile clip at 20.0 cm20.0\ \text{cm}20.0 cm from the first, so that a 20.0 cm20.0\ \text{cm}20.0 cm length of wire is in the circuit.
- Connect the voltmeter across the length of wire between the two clips.
- Method, taking readings:
- Close the switch, record the current and the potential difference, and open the switch again straight away.
- Move the second clip to 40.0 cm40.0\ \text{cm}40.0 cm, 60.0 cm60.0\ \text{cm}60.0 cm, 80.0 cm80.0\ \text{cm}80.0 cm and 100.0 cm100.0\ \text{cm}100.0 cm, taking a pair of readings at each length.
- Repeat the whole set of lengths twice more and calculate the mean resistance at each length using R=VIR = \dfrac{V}{I}R=IV.
- Plot a graph of resistance on the vertical axis against length on the horizontal axis and draw a line of best fit.
- Variables: the independent variable is the length of wire, the dependent variable is its resistance, and the control variables are the material and thickness of the wire and its temperature.
- Results: the graph is a straight line through the origin, with the resistance rising by roughly the same amount for every extra 20.0 cm20.0\ \text{cm}20.0 cm of wire.
- Conclusion: the resistance of the wire is directly proportional to its length.
- Watch out: if the first clip is not exactly at the zero mark, every length is wrong by the same amount and the line misses the origin, and short lengths draw a large current that warms the wire and raises its resistance.
- Safety: the wire can become hot enough to burn, so keep the current small, open the switch between readings and do not touch the wire while the switch is closed.
- Do not forget to convert mA\text{mA}mA and kΩ\text{k}\OmegakΩ before substituting, because an unconverted value gives an answer that is wrong by a factor of 100010001000.
- Do not assume every component obeys Ohm's law, because the resistance of a filament lamp, a thermistor and an LDR all change.
- Do not describe Ohm's law without the condition of constant temperature.
Resistance calculations
- Write the equation first, then show the substitution with units, then give the final answer with its unit, because each stage can earn a mark.
- When you rearrange, rearrange the symbols before you put in any numbers, which makes slips easier to spot.
- When a question gives a table of readings and asks whether the resistance is constant, calculate VI\dfrac{V}{I}IV for at least two rows and quote the values in your answer.
- Give your answer to the same number of significant figures as the least precise value in the question, which is usually two or three.
- Write down the equation linking potential difference, current and resistance.
- Calculate the resistance of a lamp that carries 0.40 A0.40\ \text{A}0.40 A when it has 6.0 V6.0\ \text{V}6.0 V across it.
- State Ohm's law.
- Describe how to use a table of readings to show whether a component has a constant resistance.
- Explain why a longer wire has a larger resistance.
3.2.5 Ohmic and non-ohmic resistors
Where resistance comes from
- A metal is made of a regular arrangement of positive ions, with free electrons able to move between them.
- When a potential difference is applied, the free electrons drift through the metal, forming the current.
- As they drift, the electrons collide with the ions, which slows them down and transfers energy to the ions.
- The energy transferred to the ions increases the thermal store of the metal, which is why a current heats a resistor.
- The more often the electrons collide with the ions, the greater the resistance of the metal.
- The ions are always vibrating, and the hotter the metal, the more strongly they vibrate, so the electrons collide with them more often.
Resistors with constant resistance
Ohmic conductor
A conductor whose resistance stays constant as the current through it changes, provided its temperature stays constant.
- If the temperature of a metal conductor stays the same, its ions keep vibrating by the same amount as the current changes.
- The rate of collisions for each electron therefore does not change, so the resistance stays constant.
- With a constant resistance, doubling the potential difference doubles the current, so the value of VI\dfrac{V}{I}IV is the same for every pair of readings.
- A conductor that behaves in this way is an ohmic conductor.
- Fixed resistors are made so that they stay close to room temperature for the currents they are designed to carry, so their resistance stays almost constant.
- A metal wire behaves as an ohmic conductor only while its temperature is kept constant, for example by keeping the current small.
- If a large current heats an ordinary resistor or wire, its resistance rises, so it stops behaving as an ohmic conductor.
Resistors with changing resistance
Non-ohmic component
A component whose resistance changes as the current through it changes.
Filament lamp
A lamp that gives out light because a thin metal filament inside it is heated to a very high temperature by the current.
- In some components, the resistance changes as the current changes, so they are non-ohmic.
- A filament lamp is the most important example.
- As the current through the filament increases, more energy is transferred to it every second, so its temperature rises, reaching over 2000 ∘C2000\ ^{\circ}\text{C}2000 ∘C when the lamp glows brightly.
- The hotter filament has ions that vibrate more, so the electrons collide with them more often.
- More frequent collisions mean the resistance of the filament increases as the current increases.
- Because its resistance rises, doubling the potential difference across a filament lamp less than doubles the current through it.
- An NTC thermistor also changes its resistance as the current changes, but in the opposite way.
- A large current warms the thermistor, and its resistance falls as its temperature rises, so the current rises faster than the potential difference.
- A diode has a very high resistance until the potential difference across it in the forward direction reaches about 0.6 V0.6\ \text{V}0.6 V, after which its resistance becomes very small.
- Non-ohmic does not mean that a component has no resistance, or that its resistance is large, but only that its resistance is not constant.
Testing whether resistance is constant
- To test a component, measure the current through it at several different potential differences.
- Calculate R=VIR = \dfrac{V}{I}R=IV for each pair of readings.
- If the values are the same, the component has a constant resistance over that range.
- If the values increase as the current increases, as for a filament lamp, the resistance is rising.
- If the values decrease as the current increases, as for a self-heating thermistor, the resistance is falling.
Resistance of a filament lamp
- A filament lamp gives these pairs of readings: 1.0 V1.0\ \text{V}1.0 V and 0.10 A0.10\ \text{A}0.10 A, 3.0 V3.0\ \text{V}3.0 V and 0.20 A0.20\ \text{A}0.20 A, and 6.0 V6.0\ \text{V}6.0 V and 0.25 A0.25\ \text{A}0.25 A.
- The resistance rises from 10 Ω10\ \Omega10 Ω to 24 Ω24\ \Omega24 Ω as the current increases, so the lamp is non-ohmic.
- The rise happens because the larger current makes the filament hotter, so its ions vibrate more and the electrons collide with them more often.
Resistance of a fixed resistor
- A fixed resistor gives 2.0 V2.0\ \text{V}2.0 V with 0.20 A0.20\ \text{A}0.20 A, and 4.0 V4.0\ \text{V}4.0 V with 0.40 A0.40\ \text{A}0.40 A.
- The resistance is the same at both currents, so the resistor behaves as an ohmic conductor over this range.
- Do not say the resistance of a lamp increases because the current is used up, because the cause is the rising temperature of the filament.
- Do not say that the electrons vibrate more when a metal is heated, because it is the ions that vibrate more.
- Do not describe a non-ohmic component as having no resistance, because non-ohmic only means that its resistance changes.
Explaining changing resistance
- For an explanation of why the resistance of a filament lamp increases, write the full chain of cause and effect, with one link per step.
- The current increases, so the temperature of the filament increases.
- The ions vibrate more, so the electrons collide with them more often.
- The more frequent collisions mean the resistance increases.
- Missing out the ions or the collisions is the most common way to drop a mark on this explanation.
- When you are given data, support your answer with at least two calculated resistance values.
- Explain, in terms of ions and electrons, what causes resistance in a metal.
- State the condition needed for a metal wire to have a constant resistance.
- Explain why the resistance of a filament lamp increases as the current through it increases.
- Describe how the resistance of an NTC thermistor changes as it warms up.
- State what non-ohmic means.
3.2.6 Designing circuits to investigate resistance
The test circuit
Variable resistor
A resistor whose resistance can be adjusted to change the current in a circuit.
- To explore how the resistance of a component behaves, the circuit must let you change the current through the component and measure both the current and the potential difference at each setting.
- Each part of the standard test circuit has its own job.
- d.c. power supply or battery: provides the potential difference that drives the current.
- Component under test: the wire, lamp, diode, thermistor or LDR being investigated.
- Ammeter in series with the component: measures the current through it.
- Voltmeter in parallel across the component only: measures the potential difference across it, without including the ammeter or any other part.
- Variable resistor in series: changes the current, and so changes the potential difference across the component.
- Switch: lets the current be turned off between readings so that the component does not heat up.
- Turning the variable resistor to a larger resistance gives a smaller current and a smaller potential difference across the component, while a smaller setting gives a larger current.
- A variable power supply can be used instead of a variable resistor, by changing its output in steps.
- To take readings for current in the opposite direction, the connections to the supply are reversed, and the readings are recorded as negative values.
Planning the investigation
Independent variable
The variable that is deliberately changed in an investigation.
Dependent variable
The variable that is measured to find out how it is affected by the independent variable.
Control variable
A variable that is kept the same throughout an investigation so that it cannot affect the results.
- The independent variable is usually the potential difference across the component, which you change in steps.
- The dependent variable is the current through the component, which you measure at each step.
- The control variables must be kept the same so that only the potential difference affects the current.
- For a metal wire, the control variables are its length, thickness, material and temperature.
- For an NTC thermistor, the temperature must be held constant at each setting, and for an LDR the light intensity must be held constant.
- Take at least five or six readings spread evenly across the range, plus the same number in the reverse direction when the component might behave differently each way.
- Repeat each reading and calculate a mean, ignoring any result that is clearly anomalous.
Adapting the circuit for each component
- Wire of varying resistance: a length of resistance wire is fixed along a metre rule, and a sliding crocodile clip selects how much of it is in the circuit.
- The voltmeter is connected across the selected length only, and the current is kept small so the wire does not warm up.
- Filament lamp: the potential difference is increased in steps up to the rated value printed on the lamp, and each reading is taken once the brightness has settled.
- Diode: a protective resistor is placed in series with the diode, because a diode in the forward direction has a very small resistance and could otherwise carry a damaging current.
- The readings are taken in small steps around 0.6 V0.6\ \text{V}0.6 V, where the current starts to rise sharply, and the supply is then reversed to test the other direction.
- NTC thermistor: the thermistor is placed in a beaker of water with a thermometer, so its temperature can be changed and measured while the same measuring circuit records the current and potential difference.
- LDR: the LDR is placed at a measured distance from a lamp in a darkened room, so the light intensity on it can be changed by moving the lamp while the circuit records the current and potential difference.
Using the readings
- For each pair of readings, calculate the resistance using R=VIR = \dfrac{V}{I}R=IV.
- Comparing the resistance values shows whether the resistance is constant or changes as the current changes.
- Plotting the current against the potential difference shows the same pattern as a graph, which is the clearest way to compare components.
Choosing a protective resistor
- A diode must not carry more than 0.10 A0.10\ \text{A}0.10 A, and it is connected in series with a protective resistor to a 6.0 V6.0\ \text{V}6.0 V supply.
- When the diode conducts, it has about 0.7 V0.7\ \text{V}0.7 V across it, so the rest of the supply potential difference is across the resistor.
- The smallest resistance that keeps the current at or below 0.10 A0.10\ \text{A}0.10 A is found from R=VIR = \dfrac{V}{I}R=IV.
- A protective resistor of 100 Ω100\ \Omega100 Ω would therefore be a safe choice, because it gives a current of about 0.05 A0.05\ \text{A}0.05 A.
Wire thickness and resistance
- Aim: to investigate how the thickness of a metal wire affects its resistance.
- Apparatus: five constantan wires of the same length, 50.0 cm50.0\ \text{cm}50.0 cm, with different diameters, a micrometer, a power supply set to 2 V2\ \text{V}2 V, a variable resistor, a switch, a digital ammeter, a digital voltmeter and crocodile-clip leads.
- Method, preparing the wires:
- Measure the diameter of each wire with the micrometer at three places along its length and calculate a mean.
- Mark a 50.0 cm50.0\ \text{cm}50.0 cm length on each wire with tape so the same length is tested every time.
- Method, taking readings:
- Connect the supply, switch, variable resistor, ammeter and the first wire in series, with the voltmeter across the marked length only.
- Adjust the variable resistor so the current is about 0.2 A0.2\ \text{A}0.2 A, close the switch, record the current and potential difference, and open the switch.
- Repeat with each wire in turn, then repeat the full set twice more and calculate a mean resistance for each wire using R=VIR = \dfrac{V}{I}R=IV.
- Variables: the independent variable is the diameter of the wire, the dependent variable is its resistance, and the control variables are the length, the material and the temperature of the wire.
- Results: the thinnest wire has the largest resistance, and the resistance falls as the diameter increases.
- Conclusion: a thicker wire of the same length and material has a smaller resistance, because the electrons have more room to pass between the ions.
- Watch out: keep the current small and the switch closed only briefly, because a warm wire has a higher resistance and would distort the comparison.
- Safety: thin wires heat up quickly, so let each wire cool before handling it and keep the supply potential difference low.
- Do not connect the voltmeter across both the component and the ammeter, because it would then measure the wrong potential difference.
- Do not leave out the protective resistor when testing a diode, because the current could become large enough to damage the diode or the meters.
- Do not change two things at once, such as the potential difference and the temperature of a thermistor, because you cannot then tell which one caused the change in current.
Explaining circuit designs
- When you are asked to explain the design of a circuit, name each component and give its purpose, such as the variable resistor changes the current through the component.
- State where each meter goes and why, so write that the ammeter is in series to measure the current through the component and the voltmeter is in parallel to measure the potential difference across it.
- Finish by saying how the readings are used, which is to calculate R=VIR = \dfrac{V}{I}R=IV for each pair or to plot current against potential difference.
- State the purpose of the variable resistor in a circuit used to test a component.
- Explain why a protective resistor is used when testing a diode.
- Describe how the circuit is changed to obtain negative readings of current and potential difference.
- Name two control variables when investigating the resistance of a metal wire.
- Describe how the light intensity on an LDR can be changed in an investigation.
3.2.7 Linear and non-linear circuit components
Current-potential difference graphs
Current-potential difference graph
A graph of the current through a component plotted against the potential difference across it.
- A current-potential difference graph shows how the current through a component changes as the potential difference across it changes.
- The potential difference is the independent variable, so it is plotted on the horizontal axis, in volts, V\text{V}V.
- The current is the dependent variable, so it is plotted on the vertical axis, in amperes, A\text{A}A.
- Positive values show the current in one direction, and negative values show the current flowing the opposite way after the supply connections are reversed.
- The resistance at any point on the graph is found by reading off VVV and III at that point and calculating R=VIR = \dfrac{V}{I}R=IV.
- A steeper line means more current for each volt, so it shows a smaller resistance.
- A shallower line means less current for each volt, so it shows a larger resistance.
Linear components
Linear component
A component whose current-potential difference graph is a straight line through the origin, so the current is directly proportional to the potential difference.
- The graph of a linear component is a straight line through the origin.
- Equal increases in potential difference produce equal increases in current, so the current is directly proportional to the potential difference.
- Because VI\dfrac{V}{I}IV is the same at every point on the line, a linear component has a constant resistance.
- A fixed resistor and a metal wire at constant temperature are linear components.
- The line has the same shape for negative values, because these components behave in the same way whichever direction the current flows.
- Two linear components can be compared by the steepness of their lines, with the steeper line belonging to the component with the smaller resistance.
Non-linear components
Non-linear component
A component whose current-potential difference graph is curved, so the current is not directly proportional to the potential difference.
- The graph of a non-linear component is curved.
- Equal increases in potential difference produce unequal changes in current, so the current is not directly proportional to the potential difference.
- Because VI\dfrac{V}{I}IV is different at different points on the curve, a non-linear component has a resistance that changes.
- The direction in which the curve bends shows how the resistance changes.
- A curve that becomes less steep as the potential difference increases shows a resistance that is increasing.
- A curve that becomes steeper as the potential difference increases shows a resistance that is decreasing.
- A filament lamp, a diode and a thermistor that warms up as the current increases are all non-linear components.
Deciding from data
- To decide from a table of results, calculate IV\dfrac{I}{V}VI or VI\dfrac{V}{I}IV for each row.
- If the ratio is the same for every row, the component is linear.
- If the ratio changes steadily from row to row, the component is non-linear.
- To decide from a graph, lay a ruler along the plotted points and check whether they lie on a straight line that passes through the origin.
- A single point that lies well away from an otherwise smooth pattern is an anomaly and should be checked or repeated, not used to change the line.
Linear or non-linear
- Component X gives 0.20 A0.20\ \text{A}0.20 A at 1.0 V1.0\ \text{V}1.0 V, 0.40 A0.40\ \text{A}0.40 A at 2.0 V2.0\ \text{V}2.0 V and 0.80 A0.80\ \text{A}0.80 A at 4.0 V4.0\ \text{V}4.0 V.
- The ratio is the same for every reading, so component X is linear with a constant resistance of 5.0 Ω5.0\ \Omega5.0 Ω.
- Component Y gives 0.20 A0.20\ \text{A}0.20 A at 1.0 V1.0\ \text{V}1.0 V, 0.32 A0.32\ \text{A}0.32 A at 2.0 V2.0\ \text{V}2.0 V and 0.45 A0.45\ \text{A}0.45 A at 4.0 V4.0\ \text{V}4.0 V.
- The ratio rises as the potential difference increases, so component Y is non-linear and its resistance is increasing.
Current-potential difference characteristic of a resistor
- Aim: to obtain the current-potential difference characteristic of a fixed resistor and use it to decide whether the resistor is linear.
- Apparatus: a 10 Ω10\ \Omega10 Ω fixed resistor, a d.c. power supply set to 6 V6\ \text{V}6 V, a variable resistor, a switch, a digital ammeter, a digital voltmeter and connecting leads.
- Method, positive readings:
- Connect the supply, switch, variable resistor, ammeter and fixed resistor in series, with the voltmeter across the fixed resistor only.
- Set the variable resistor to its largest resistance so that the first current is small.
- Close the switch and record the potential difference and the current, then open the switch.
- Reduce the setting of the variable resistor in steps to give about six readings, roughly 0.5 V0.5\ \text{V}0.5 V apart, up to about 3.0 V3.0\ \text{V}3.0 V.
- Method, negative readings:
- Swap the two leads at the supply terminals so the current flows the other way through the resistor.
- Take a second set of six readings and record them as negative values of current and potential difference.
- Method, processing:
- Repeat every reading twice more and calculate means.
- Plot current on the vertical axis against potential difference on the horizontal axis, with both axes running through negative values, and draw a line of best fit.
- Results: the points lie on a straight line through the origin that continues into the negative quarter of the graph.
- Conclusion: the fixed resistor is a linear component, because the current is directly proportional to the potential difference in both directions.
- Watch out: label both axes with the quantity and the unit, use a scale that fills most of the grid, and draw a single ruled line of best fit, not a line joining the points.
- Safety: keep the current small and open the switch between readings, because a resistor carrying a large current can become hot.
- Do not use the gradient of the line as the resistance, because resistance is VI\dfrac{V}{I}IV read at a point and the gradient of this graph is IV\dfrac{I}{V}VI.
- Do not describe every straight line as proportional, because the line must also pass through the origin.
- Do not join the points dot to dot, because a line or curve of best fit shows the true pattern.
Describing graphs
- When you describe a linear component, use the phrase straight line through the origin and say that the current is directly proportional to the potential difference.
- When you describe a non-linear component, say that the graph is curved and state whether it becomes steeper or less steep.
- Support your decision with numbers, by calculating VI\dfrac{V}{I}IV at two points and showing that the values are the same or different.
- State which quantity is plotted on each axis of a current-potential difference graph.
- Describe the graph of a linear component.
- Explain how a curved current-potential difference graph shows that resistance is changing.
- State what a negative value of current on the graph represents.
- Describe how to use a table of readings to decide whether a component is linear.
3.2.8 Current-potential difference graphs for components
Fixed resistor and metal wire
- The graph for a fixed resistor, or for a metal wire at constant temperature, is a straight line through the origin.
- The line continues through the origin into the negative values, and the graph is symmetrical, because the resistor opposes the current equally in both directions.
- The straight line shows a constant resistance, which is what a resistor is designed for, since it sets a fixed current for a given potential difference.
- A resistor with a larger resistance gives a less steep line, because a smaller current flows for each volt.
- If a wire carries a large current and becomes warm, the ends of its line start to bend towards the potential difference axis, because its resistance rises as it heats up.
Filament lamp
Filament lamp
A lamp that gives out light because a thin metal filament inside it is heated to a very high temperature by the current.
- The graph for a filament lamp is a curve through the origin that becomes less steep as the potential difference increases in either direction, giving a shallow S-shape.
- The graph is symmetrical, because the filament heats up in the same way whichever direction the current flows.
- At small potential differences, the filament is cool and the graph is almost straight.
- As the current increases, the filament gets hotter, its ions vibrate more, the electrons collide with them more often, and its resistance increases.
- This property is tied to the job of the lamp, because the filament must become very hot to give out light, so its resistance unavoidably rises when it is working.
Diode
Diode
A component that lets current flow through it in one direction only, because its resistance is very high in the opposite direction.
- A diode only allows current to flow through it in one direction, called the forward direction.
- In the reverse direction, the diode has a very high resistance, so the current is almost zero and the graph lies along the negative potential difference axis.
- In the forward direction, the current stays almost zero until the potential difference reaches about 0.6 V0.6\ \text{V}0.6 V, and then rises very steeply.
- Above this potential difference, the diode has a very small resistance.
- The graph is therefore not symmetrical, which is the clearest sign of a component that treats the two directions differently.
- Diodes are used to make sure current can only flow one way, for example to protect a device from damage if its battery is put in the wrong way round.
NTC thermistor
NTC thermistor
A resistor whose resistance decreases as its temperature increases.
- The resistance of an NTC thermistor decreases as its temperature increases.
- A graph of resistance against temperature is a curve that falls steeply at low temperatures and then levels off at higher temperatures.
- On a current-potential difference graph, a thermistor held at one temperature gives a straight line, and a thermistor at a higher temperature gives a steeper line because its resistance is smaller.
- If the current is large enough to warm the thermistor, its line curves upwards and becomes steeper, because its resistance falls as it heats itself.
- Because its resistance responds to temperature, a thermistor is used as a temperature sensor in thermostats, oven controls, fire alarms and digital thermometers.
Light-dependent resistor
Light-dependent resistor (LDR)
A resistor whose resistance decreases as the intensity of the light falling on it increases.
- The resistance of an LDR decreases as the light intensity falling on it increases.
- In darkness, an LDR can have a resistance of around a million ohms, while in bright light its resistance can fall to a few hundred ohms.
- A graph of resistance against light intensity is a curve that falls steeply at low light intensity and then levels off.
- On a current-potential difference graph, an LDR in brighter light gives a steeper straight line, because its resistance is smaller.
- Because its resistance responds to light, an LDR is used as a light sensor, for example in street lights that switch on at dusk and in automatic night lights.
Reading resistance from a lamp graph
- A current-potential difference graph for a filament lamp passes through the points 2.0 V2.0\ \text{V}2.0 V, 0.25 A0.25\ \text{A}0.25 A and 6.0 V6.0\ \text{V}6.0 V, 0.40 A0.40\ \text{A}0.40 A.
- The resistance has nearly doubled between the two points, which matches the curve becoming less steep as the filament heats up.
- At −6.0 V-6.0\ \text{V}−6.0 V, the graph reads −0.40 A-0.40\ \text{A}−0.40 A, so the resistance is again 15 Ω15\ \Omega15 Ω and the lamp behaves the same in both directions.
Characteristics of a filament lamp and a diode
- Aim: to obtain the current-potential difference characteristics of a filament lamp and a diode and relate their shapes to how each component works.
- Apparatus: a 6 V6\ \text{V}6 V filament lamp in a holder, a diode, a 100 Ω100\ \Omega100 Ω protective resistor, a d.c. power supply set to 6 V6\ \text{V}6 V, a variable resistor, a switch, a digital ammeter, a digital voltmeter and connecting leads.
- Method, the filament lamp:
- Connect the supply, switch, variable resistor, ammeter and lamp in series, with the voltmeter across the lamp only.
- Start with the variable resistor at its largest value, and record the potential difference and current at about eight settings up to 6.0 V6.0\ \text{V}6.0 V, waiting for the lamp to settle each time.
- Reverse the supply connections and repeat to obtain the negative readings.
- Method, the diode:
- Replace the lamp with the diode and the protective resistor in series, keeping the voltmeter across the diode only.
- Record readings in steps of about 0.1 V0.1\ \text{V}0.1 V from 0 V0\ \text{V}0 V to about 0.8 V0.8\ \text{V}0.8 V, because the current changes rapidly in this region.
- Reverse the supply connections and record readings up to −3.0 V-3.0\ \text{V}−3.0 V across the diode.
- Method, processing:
- Repeat each set of readings and calculate means.
- Plot a separate graph for each component with current on the vertical axis and potential difference on the horizontal axis, and draw a smooth curve of best fit through each set of points.
- Results: the lamp gives a symmetrical curve that flattens at higher potential differences, while the diode gives almost no current in reverse and a sharp rise above about 0.6 V0.6\ \text{V}0.6 V in the forward direction.
- Conclusion: the resistance of the lamp increases as it heats up, while the diode has a very high resistance in one direction and a very low resistance in the other once it starts to conduct.
- Watch out: take more readings where the graph changes shape quickly, and draw curves freehand in one smooth stroke rather than as straight segments.
- Safety: the lamp glass becomes hot, so do not touch it during or just after the experiment, and never test the diode without the protective resistor.
- Do not draw the diode graph as a straight line in the forward direction, because the current stays near zero until about 0.6 V0.6\ \text{V}0.6 V and then rises steeply.
- Do not say that the resistance of an NTC thermistor increases with temperature, because it decreases.
- Do not say that an LDR has a low resistance in the dark, because its resistance is highest in the dark.
Relating graphs to components
- When you are asked to relate a graph to a component, give three linked points, which are the shape, what it shows about the resistance, and the reason or use.
- For a filament lamp, the curve gets less steep, so the resistance increases, because the filament heats up.
- For a diode, there is no current in reverse, so the resistance is very high in one direction, which lets current flow one way only.
- When you sketch a graph, include both positive and negative values unless the question tells you otherwise, because symmetry is often what is being tested.
- Sketch and describe the current-potential difference graph for a filament lamp.
- Explain why the graph for a diode is not symmetrical.
- State how the resistance of an NTC thermistor changes as its temperature increases.
- Describe one use of an LDR and explain why it suits that use.
- State what happens to the line for a thermistor on a current-potential difference graph when it is warmer.
3.2.9 Resistance in series and parallel
Net resistance
Net resistance
The overall resistance of a combination of components, which decides the current drawn from the supply.
- When several resistors are connected together, their combined effect on the circuit is described by their net resistance.
- For a supply with a fixed potential difference, a larger net resistance means a smaller current is drawn from the supply.
- Adding a resistor can either increase or decrease the net resistance, depending on whether it is added in series or in parallel.
Resistors in series
- When a second resistor is added in series, there is still only one path, so all of the charge must pass through both resistors one after the other.
- Each resistor opposes the flow of charge, so the charge meets more opposition in total than it did with one resistor.
- The net resistance increases, and it is larger than the resistance of either resistor on its own.
- With the same supply potential difference, the larger net resistance means the current in the circuit falls.
- The supply potential difference is now shared between the two resistors, so the potential difference across the first resistor is smaller than before.
- Adding a third resistor in series increases the net resistance again, so every extra resistor in series makes the current smaller.
Resistors in parallel
- When a second resistor is added in parallel, it provides an extra path through which charge can flow.
- Each branch is connected directly across the supply, so each resistor has the full supply potential difference across it and carries its own current.
- The current through the first resistor does not change, but the second branch adds its own current, so the total current from the supply increases.
- A larger total current flowing for the same potential difference means that the net resistance has decreased.
- The net resistance of resistors in parallel is smaller than the resistance of the smallest resistor on its own.
- Every extra resistor added in parallel adds another path, so the net resistance keeps falling and the total current keeps rising.

Lamps in series and in parallel
- Identical lamps connected in series to a supply glow more dimly than one lamp on its own.
- The net resistance is larger, so the current is smaller, and the supply potential difference is shared, so each lamp transfers energy more slowly.
- Identical lamps connected in parallel to the same supply each glow as brightly as one lamp on its own.
- Each lamp has the full supply potential difference across it and carries the same current as a single lamp would.
- The lamps in parallel draw a larger total current, so a battery powering them goes flat more quickly than the same battery powering lamps in series.
Adding a resistor to a circuit
- A 6.0 V6.0\ \text{V}6.0 V supply is connected to a single 10 Ω10\ \Omega10 Ω resistor, and an ammeter in the main lead records the current.
- A second resistor is added in series, so the net resistance becomes larger than 10 Ω10\ \Omega10 Ω and the ammeter reading falls.
- The second resistor is instead added in parallel, so it forms a new branch with the full 6.0 V6.0\ \text{V}6.0 V across it.
- The current through the original 10 Ω10\ \Omega10 Ω branch stays the same, but the new branch adds extra current, so the ammeter reading in the main lead rises.
- A larger current for the same 6.0 V6.0\ \text{V}6.0 V shows that the net resistance of the parallel pair is smaller than 10 Ω10\ \Omega10 Ω.
Brightness of lamps in series and in parallel
- Aim: to compare the brightness of identical filament lamps connected in series and in parallel to the same supply.
- Apparatus: two identical 3.5 V3.5\ \text{V}3.5 V filament lamps in holders, a battery of two 1.5 V1.5\ \text{V}1.5 V cells, a switch, a digital ammeter, a digital voltmeter, a light sensor and data logger or a light meter, a cardboard tube to fit over each lamp, and connecting leads.
- Method, a single lamp:
- Connect one lamp, the switch and the ammeter in series with the battery, with the voltmeter across the lamp.
- Fix the light sensor at the open end of the cardboard tube, 5.0 cm5.0\ \text{cm}5.0 cm from the lamp, so that background light is kept out.
- Close the switch and record the light reading, the current and the potential difference across the lamp.
- Method, two lamps in series:
- Add the second lamp in series with the first, keeping the same battery and the same sensor position on the first lamp.
- Record the light reading from the first lamp, the current and the potential difference across each lamp.
- Method, two lamps in parallel:
- Rebuild the circuit so that each lamp is on its own branch between the same two junctions.
- Record the light reading from the first lamp, the current in the main lead and the potential difference across each lamp.
- Repeat each arrangement three times and calculate mean values.
- Variables: the independent variable is the way the lamps are connected, the dependent variable is the brightness of the lamp, and the control variables are the battery, the type of lamp and the distance between the lamp and the sensor.
- Results: the lamps in series are much dimmer than the single lamp and each has about half of the battery potential difference across it, while each lamp in parallel is about as bright as the single lamp and has the full battery potential difference across it.
- Conclusion: lamps in series share the potential difference and have a larger net resistance, so they are dimmer, whereas lamps in parallel each receive the full potential difference and are brighter.
- Watch out: if you judge brightness by eye, results are only qualitative, so a light sensor in a tube at a fixed distance gives fairer, numerical readings.
- Safety: open the switch between readings to save the battery, and let the lamps cool before handling them.
- Do not say that adding more resistors always increases the resistance, because adding resistors in parallel decreases the net resistance.
- Do not say that lamps in parallel are dimmer because the current is split between them, because each branch has the full supply potential difference and carries its own full current.
- Do not say that the current in a series circuit is shared between the components, because the current is the same through each of them.
Explaining net resistance
- Explain series and parallel resistance with a cause and a consequence, such as charge has to pass through both resistors, so the net resistance increases.
- For parallel resistors, mention the extra path, the larger total current and the same potential difference, because the last two together show that the net resistance has fallen.
- Explanations of net resistance only need words, so focus on the reasoning rather than on numbers.
- State what happens to the net resistance when a resistor is added in series.
- Explain why adding a resistor in parallel decreases the net resistance.
- Compare the net resistance of two resistors in parallel with the resistance of the smaller resistor.
- Explain why identical lamps in series are dimmer than the same lamps in parallel.
- Name two control variables in an investigation into the brightness of lamps.
3.2.10 Series and parallel circuit problems
Calculating in series circuits
- In a series circuit, the current is the same through every component, so one current value is used for every component.
- The total resistance of components in series is the sum of their resistances, Rtotal=R1+R2R_{\text{total}} = R_1 + R_2Rtotal=R1+R2.
- The supply potential difference is shared, so the potential differences across the components add up to it, Vsupply=V1+V2V_{\text{supply}} = V_1 + V_2Vsupply=V1+V2.
- The equation V=IRV = IRV=IR can be applied to the whole circuit or to one component, as long as all three values belong to the same part.
- For the whole circuit, use the supply potential difference, the circuit current and the total resistance.
- For one component, use the potential difference across that component, the current through it and its own resistance.
- The component with the larger resistance has the larger potential difference across it, because the same current flows through both and V=IRV = IRV=IR.
Calculating in parallel circuits
- In a parallel circuit, the potential difference across each branch is the same as the supply potential difference.
- The current in each branch is found separately, using I=VRI = \dfrac{V}{R}I=RV with the supply potential difference and the resistance of that branch.
- The total current from the supply is the sum of the branch currents, Itotal=I1+I2I_{\text{total}} = I_1 + I_2Itotal=I1+I2.
- The total resistance of a parallel circuit is found by dividing the supply potential difference by the total current, Rtotal=VsupplyItotalR_{\text{total}} = \dfrac{V_{\text{supply}}}{I_{\text{total}}}Rtotal=ItotalVsupply.
- This total resistance is always smaller than the resistance of any single branch.
- The branch with the smaller resistance carries the larger current, because each branch has the same potential difference across it.

Solving circuit problems
- Decide first whether the components are in series, in parallel, or a mixture of both.
- Write down the values you know and label each one with the component it belongs to.
- Use the series and parallel rules to find any potential difference or current that is shared or added.
- Use V=IRV = IRV=IR for a single component or for the whole circuit to find the remaining unknown.
- Check the answer, for example by confirming that the series potential differences add up to the supply or that the branch currents add up to the total current.
Circuits with sensors
Photocell
A device that produces a potential difference, and so can drive a current, when light falls on it.
- The same rules apply when a circuit contains an NTC thermistor or an LDR, except that the resistance of the sensor depends on its surroundings.
- The resistance of a thermistor at a given temperature, or of an LDR at a given light intensity, is usually read from a graph and then used in the calculation.
- When a thermistor is in series with a fixed resistor, a rise in temperature lowers the thermistor resistance, so the circuit current increases and the potential difference across the thermistor falls.
- A photocell acts as a supply rather than a resistor, and the power it delivers is found by multiplying the potential difference across it by the current it drives, P=VIP = VIP=VI.
Current and potential difference in a series circuit
- A 12 V12\ \text{V}12 V battery is connected in series with a 3.0 Ω3.0\ \Omega3.0 Ω resistor and a 5.0 Ω5.0\ \Omega5.0 Ω resistor.
- The two potential differences add up to 4.5 V+7.5 V=12 V4.5\ \text{V} + 7.5\ \text{V} = 12\ \text{V}4.5 V+7.5 V=12 V, which matches the battery.
Currents in a parallel circuit
- A 6.0 V6.0\ \text{V}6.0 V supply is connected across a 12 Ω12\ \Omega12 Ω resistor and a 4.0 Ω4.0\ \Omega4.0 Ω resistor in parallel.
- Each branch has the full 6.0 V6.0\ \text{V}6.0 V across it.
- The total resistance of 3.0 Ω3.0\ \Omega3.0 Ω is smaller than the smaller branch resistance of 4.0 Ω4.0\ \Omega4.0 Ω, as expected for a parallel circuit.
A thermistor in a series circuit
- An NTC thermistor is connected in series with a 1.0 kΩ1.0\ \text{k}\Omega1.0 kΩ resistor and a 6.0 V6.0\ \text{V}6.0 V supply, and at 20 ∘C20\ ^{\circ}\text{C}20 ∘C the thermistor has a resistance of 2.0 kΩ2.0\ \text{k}\Omega2.0 kΩ.
- At 60 ∘C60\ ^{\circ}\text{C}60 ∘C, the thermistor resistance falls to 500 Ω500\ \Omega500 Ω.
- Warming the thermistor has doubled the current and halved the potential difference across the thermistor.
Thermistor resistance and temperature
- Aim: to investigate how the resistance of an NTC thermistor changes as the temperature of the water around it is raised.
- Apparatus: an NTC thermistor sealed in a waterproof sleeve, a 250 cm3250\ \text{cm}^3250 cm3 beaker, a thermometer, a kettle, ice, a stirring rod, a 2 V2\ \text{V}2 V d.c. supply, a switch, a digital ammeter, a digital voltmeter and connecting leads.
- Method, setting up:
- Connect the supply, switch, ammeter and thermistor in series, with the voltmeter across the thermistor only.
- Half fill the beaker with a mixture of ice and cold water, and clamp the thermistor and the thermometer side by side in the water without touching the glass.
- Method, taking readings:
- Stir the water, wait until the thermometer reading is steady, then close the switch and record the temperature, current and potential difference.
- Open the switch, add a little hot water from the kettle to raise the temperature by about 10 ∘C10\ ^{\circ}\text{C}10 ∘C, stir, and wait for the readings to settle again.
- Continue in steps of about 10 ∘C10\ ^{\circ}\text{C}10 ∘C up to about 80 ∘C80\ ^{\circ}\text{C}80 ∘C, then repeat the whole run and calculate the mean resistance at each temperature using R=VIR = \dfrac{V}{I}R=IV.
- Plot resistance on the vertical axis against temperature on the horizontal axis and draw a smooth curve of best fit.
- Results: the resistance falls steeply at first and then more gradually, for example from several thousand ohms near 0 ∘C0\ ^{\circ}\text{C}0 ∘C to a few hundred ohms near 80 ∘C80\ ^{\circ}\text{C}80 ∘C.
- Conclusion: the resistance of an NTC thermistor decreases as its temperature increases, and the change is largest at low temperatures.
- Watch out: the thermistor takes time to reach the temperature of the water, and a large current would warm it above the water temperature, so keep the supply potential difference low and close the switch only for each reading.
- Safety: take care when pouring water from the kettle, keep the electrical connections dry and above the water, and use only a low-voltage supply.
LDR resistance and light intensity
- Aim: to investigate how the resistance of an LDR changes with the intensity of the light falling on it.
- Apparatus: an LDR, a bench lamp, a metre rule, a light meter if available, a 2 V2\ \text{V}2 V d.c. supply, a switch, a digital ammeter, a digital voltmeter and connecting leads, used in a darkened room.
- Method:
- Connect the supply, switch, ammeter and LDR in series, with the voltmeter across the LDR only.
- Clamp the LDR facing the lamp at the zero end of the metre rule, so the lamp shines straight onto it.
- Place the lamp 10 cm10\ \text{cm}10 cm from the LDR, record the current and potential difference, and calculate the resistance using R=VIR = \dfrac{V}{I}R=IV.
- Move the lamp back in steps of 10 cm10\ \text{cm}10 cm up to 60 cm60\ \text{cm}60 cm, taking readings at each distance, or record the light intensity with the light meter placed where the LDR sits.
- Repeat the whole set and calculate the mean resistance at each distance.
- Variables: the independent variable is the distance of the lamp, which sets the light intensity, the dependent variable is the resistance of the LDR, and the control variables are the lamp, the angle of the LDR and the background light.
- Results: the resistance of the LDR increases as the lamp is moved further away.
- Conclusion: the resistance of an LDR decreases as the light intensity falling on it increases.
- Watch out: stray light from windows or other groups changes the readings, so work in a darkened room and keep the LDR pointing straight at the lamp.
- Safety: the bench lamp becomes hot, so move it by its base and keep leads away from the bulb.
Photocell power, area and distance
- Aim: to investigate how the power output of a photocell depends on its illuminated area and on its distance from a light source.
- Apparatus: a small photocell (solar cell), a bench lamp, a metre rule, opaque card, a 100 Ω100\ \Omega100 Ω resistor, a digital ammeter, a digital voltmeter and connecting leads, used in a darkened room.
- Method, changing the area:
- Connect the photocell, ammeter and resistor in series, with the voltmeter across the photocell.
- Place the lamp 20 cm20\ \text{cm}20 cm from the photocell and record the current and potential difference with the whole cell uncovered.
- Cover one quarter, then one half, then three quarters of the cell with opaque card, recording the readings each time.
- Method, changing the distance:
- Uncover the whole cell and move the lamp to 10 cm10\ \text{cm}10 cm, 20 cm20\ \text{cm}20 cm, 30 cm30\ \text{cm}30 cm, 40 cm40\ \text{cm}40 cm and 50 cm50\ \text{cm}50 cm, recording the readings at each distance.
- For every reading, calculate the power output using P=VIP = VIP=VI, and repeat each run to find a mean.
- Results: the power output rises as more of the cell is uncovered, and it falls as the lamp is moved further away.
- Conclusion: a photocell delivers more power when a larger area is illuminated and when it is closer to the light source, because more light energy reaches it every second.
- Watch out: keep the distance fixed while changing the area and keep the area fixed while changing the distance, and keep the cell facing the lamp at the same angle throughout.
- Safety: the lamp becomes hot, so do not touch the bulb, and switch it off between runs.
- Do not mix values from different parts of a circuit in V=IRV = IRV=IR, such as the supply potential difference with the resistance of only one component.
- Do not add the resistances of parallel branches together, because that gives the total resistance of a series circuit.
- Do not forget that every branch of a parallel circuit has the full supply potential difference across it.
Circuit calculations
- Write each step on its own line with the equation, the substitution and the answer with its unit, so that the method marks can be awarded even if a later value is wrong.
- Label each value with its component, such as V1V_1V1 or ItotalI_{\text{total}}Itotal, so that the examiner can follow which part of the circuit you are working on.
- Finish by checking that the potential differences or currents add up correctly, because this catches most mistakes.
- State the rule for the potential differences across components in series.
- Calculate the total resistance of a 6.0 Ω6.0\ \Omega6.0 Ω resistor and a 9.0 Ω9.0\ \Omega9.0 Ω resistor in series.
- Calculate the current in a 3.0 Ω3.0\ \Omega3.0 Ω branch connected in parallel across a 6.0 V6.0\ \text{V}6.0 V supply.
- Explain why the total resistance of a parallel circuit is smaller than the resistance of any branch.
- Describe how the potential difference across a thermistor in a series circuit changes as it warms up.
3.2.11 Circuits for measurement and testing
Meters for measuring circuits
Multimeter
A single meter that can be switched to measure current, potential difference or resistance.
- Measuring circuits are built so that the meters record the current and potential difference without changing what they measure.
- An ammeter is placed in series and has a very low resistance, so adding it to a circuit barely changes the current.
- A voltmeter is placed in parallel and has a very high resistance, so it draws almost no current from the component it measures.
- A multimeter combines several meters in one, and a dial selects whether it measures current, potential difference or resistance.
- The black lead goes into the socket marked COM, while the red lead goes into the socket for volts and ohms or the socket for amperes, depending on the measurement.
- On the resistance setting, the multimeter passes a small current from its own battery, so the component must be disconnected from the circuit first.
- Each setting has a range, such as 20 V20\ \text{V}20 V or 200 mA200\ \text{mA}200 mA, and the best range is the smallest one that is still larger than the value being measured.
Accurate readings
Resolution
The smallest change in a quantity that a measuring instrument can show.
Zero error
A reading shown by a measuring instrument when the true value of the quantity is zero.
- The resolution of a digital meter is set by its last digit, so a meter reading 1.23 V1.23\ \text{V}1.23 V has a resolution of 0.01 V0.01\ \text{V}0.01 V.
- Choosing a smaller range usually gives more digits after the decimal point, and so a better resolution.
- Before a meter is used, check for a zero error by reading it with no current or no potential difference applied.
- A zero error must be subtracted from every reading, because it shifts all the readings by the same amount.
- On an analogue meter, read the needle with your eye directly in line with it, so that parallax does not make the reading too high or too low.
- Readings change if the component warms up, so close the switch only while taking each reading.
- Take each reading more than once and calculate a mean, ignoring any value that is clearly anomalous.
Testing for faults
Open circuit
A circuit with a break in it, so there is no complete path and no current flows.
Short circuit
A path of very low resistance that lets the current bypass part of a circuit.
- An open circuit has a break in it, such as a broken wire, a loose connection or a blown filament, so there is no current anywhere in that loop.
- A short circuit is a low-resistance path that lets the current bypass a component, so that component stops working and the current in the rest of the circuit rises.
- A continuity tester, made from a cell and a buzzer or lamp, or a multimeter on its resistance setting, shows whether a wire, fuse or switch provides a complete path.
- A reading of nearly 0 Ω0\ \Omega0 Ω, or a sounding buzzer, shows a complete path, while a very large reading shows a break.
- A voltmeter can find the faulty part of a series circuit without disconnecting anything.
- Across a working component in a circuit with a break, the voltmeter reads zero, because no current flows through it.
- Across the broken component, the voltmeter reads the full supply potential difference, because the voltmeter completes the circuit around the gap.
- A component that has been short-circuited has a potential difference of zero across it, even though the supply is working.
Circuits that measure
- A sensor in series with a fixed resistor turns a change in the surroundings into a change in potential difference, which a voltmeter can read.
- In a temperature-sensing circuit, an NTC thermistor is connected in series with a fixed resistor and a d.c. supply, with a voltmeter across the fixed resistor.
- As the temperature rises, the resistance of the thermistor falls, so the current increases.
- The fixed resistor now takes a larger share of the supply potential difference, so the voltmeter reading rises.
- A light-sensing circuit works in the same way, with an LDR in place of the thermistor, so the voltmeter reading rises as the light gets brighter.
- The circuit is calibrated by recording the voltmeter reading at several known temperatures or light intensities, so that any later reading can be converted back into a temperature or light intensity.
Finding a fault with a voltmeter
- Three identical lamps, A, B and C, are connected in series with a 6.0 V6.0\ \text{V}6.0 V battery, and none of them lights.
- A voltmeter across lamp A reads 0 V0\ \text{V}0 V, so no current is flowing through lamp A.
- A voltmeter across lamp B reads 6.0 V6.0\ \text{V}6.0 V, which is the full battery potential difference.
- A voltmeter across lamp C reads 0 V0\ \text{V}0 V.
- The full potential difference appears across lamp B, so the break in the circuit is in lamp B, most likely a broken filament.
- Replacing lamp B completes the circuit, and each lamp then has about 2.0 V2.0\ \text{V}2.0 V across it.
Correcting a zero error
- A digital ammeter reads 0.02 A0.02\ \text{A}0.02 A before it is connected to anything, which is a zero error.
- In the circuit, the same ammeter reads 0.47 A0.47\ \text{A}0.47 A.
- The corrected current of 0.45 A0.45\ \text{A}0.45 A is the value that should be used in any later calculation.
- Do not measure the resistance of a component with a multimeter while it is still connected to a working circuit, because the reading will be wrong and the meter can be damaged.
- Do not put a multimeter on the current setting across a component, because its low resistance creates a short circuit.
- Do not assume that a voltmeter reading of zero across a component means that component is broken, because in a series circuit with a break, every working component reads zero.
Measurement and testing questions
- When you explain how a circuit is used for measuring, say where each meter goes, what it measures, and why its resistance does not upset the circuit.
- For a fault-finding question, use the readings to identify where the full supply potential difference appears, because that locates the break.
- For a sensor circuit, describe the chain in order: the condition changes, the sensor resistance changes, the current changes, and the voltmeter reading changes.
- Explain why an ammeter needs a very low resistance.
- Define the resolution of a measuring instrument.
- Describe how to check a meter for a zero error.
- Explain how a voltmeter can locate a broken lamp in a series circuit.
- Describe how the voltmeter reading changes in a thermistor and fixed resistor circuit as the temperature rises.
3.2.12 Power transfer in circuit devices
Energy transfer in a circuit
- A circuit is a way of transferring energy from the supply to the components, with the current acting as the pathway.
- The supply transfers energy to the charge, and each component transfers that energy electrically to another store or away from the circuit.
- In a resistor or a heater, the energy is transferred to the thermal store of the component and then by heating to the surroundings.
- In a filament lamp, the energy is transferred to the thermal store of the filament and away by light and by heating.
- In a motor, most of the energy is transferred to the kinetic store of the spinning parts.
- The energy transferred when charge QQQ passes through a potential difference VVV is given by E=QVE = QVE=QV.
- EEE is the energy transferred in joules, J\text{J}J, QQQ is the charge in coulombs, C\text{C}C, and VVV is the potential difference in volts, V\text{V}V.
- The current is not used up in a component, because it is the energy carried by the charge that is transferred.
Power
Power
The rate at which energy is transferred.
Watt
The unit of power, equal to an energy transfer of one joule every second.
- Power tells you how quickly a device transfers energy, not how much energy it transfers in total.
- Power is the energy transferred divided by the time taken, P=EtP = \dfrac{E}{t}P=tE, which you can rearrange to E=PtE = PtE=Pt.
- PPP is the power in watts, W\text{W}W, EEE is the energy in joules, J\text{J}J, and ttt is the time in seconds, s\text{s}s.
- One watt is one joule per second, so 1 W=1 J/s1\ \text{W} = 1\ \text{J/s}1 W=1 J/s, and a 60 W60\ \text{W}60 W lamp transfers 60 J60\ \text{J}60 J of energy every second.
- Large powers are given in kilowatts, where 1 kW=1000 W1\ \text{kW} = 1000\ \text{W}1 kW=1000 W, so a 2 kW2\ \text{kW}2 kW kettle transfers 2000 J2000\ \text{J}2000 J every second.
Power, potential difference and current
- The power of any circuit device depends on the potential difference across it and the current through it.
- The potential difference is the energy transferred by each coulomb of charge.
- The current is the number of coulombs passing each second.
- Multiplying energy per coulomb by coulombs per second gives energy per second, which is the power.
- This gives the equation P=VIP = VIP=VI, where PPP is in watts, VVV is in volts and III is in amperes.
- Doubling either the potential difference or the current, with the other kept the same, doubles the rate at which the device transfers energy.
- Substituting V=IRV = IRV=IR into P=VIP = VIP=VI gives a second equation, P=I2RP = I^2RP=I2R, which is useful when the current and the resistance are known.
- Because the current is squared, doubling the current through a fixed resistor makes it transfer energy four times as quickly, which is why large currents heat wires so strongly.
Energy over time
Kilowatt-hour
The energy transferred by a device with a power of one kilowatt when it runs for one hour.
- The total energy transferred by a device depends on its power and on how long it is used, E=PtE = PtE=Pt.
- With power in watts and time in seconds, the energy comes out in joules.
- With power in kilowatts and time in hours, the energy comes out in kilowatt-hours, kW h\text{kW h}kW h, which is the unit used on electricity bills.
- One kilowatt-hour is equal to 1000 W×3600 s=3 600 000 J1000\ \text{W} \times 3600\ \text{s} = 3\,600\,000\ \text{J}1000 W×3600 s=3600000 J.
- A device with a higher power transfers energy faster, but a lower-power device left on for longer can still transfer more energy in total.
- The power rating on an appliance, such as 230 V230\ \text{V}230 V, 2.3 kW2.3\ \text{kW}2.3 kW, gives the power it transfers when connected to the stated potential difference.
Power and energy for a heater
- A heater has a potential difference of 12 V12\ \text{V}12 V across it and a current of 3.0 A3.0\ \text{A}3.0 A through it, and it is switched on for 5.05.05.0 minutes.
- The heater transfers 36 J36\ \text{J}36 J every second, and 10 800 J10\,800\ \text{J}10800 J in the five minutes.
Heating effect in a resistor
- A current of 0.50 A0.50\ \text{A}0.50 A flows through a 20 Ω20\ \Omega20 Ω resistor.
- The current is then doubled to 1.0 A1.0\ \text{A}1.0 A.
- Doubling the current has made the power four times larger.
Energy used by a kettle
- A kettle is rated at 230 V230\ \text{V}230 V, 2.3 kW2.3\ \text{kW}2.3 kW, and it is used for 3.03.03.0 minutes.
- The same energy in joules is 2300 W×180 s=414 000 J2300\ \text{W} \times 180\ \text{s} = 414\,000\ \text{J}2300 W×180 s=414000 J.
- Do not confuse power and energy, because power in watts is the rate of transfer, while energy in joules or kilowatt-hours is the amount transferred.
- Do not write that the kilowatt-hour is a unit of power, because it is a unit of energy.
- Do not write about an electrical energy store, because no such store exists and electricity is a way of transferring energy between stores.
- Do not leave time in minutes when the power is in watts, because E=PtE = PtE=Pt needs seconds to give joules.
Power calculations
- Choose the power equation that matches the values given, using P=VIP = VIP=VI for potential difference and current, P=I2RP = I^2RP=I2R for current and resistance, and P=EtP = \dfrac{E}{t}P=tE for energy and time.
- In a two-step question, such as finding energy from potential difference, current and time, find the power first and then use E=PtE = PtE=Pt.
- When you explain why power depends on potential difference and current, link energy per coulomb with coulombs per second.
- Define power and state its unit.
- Write down the equation linking power, potential difference and current.
- Explain why the power of a device equals the potential difference multiplied by the current.
- Calculate the energy transferred by a 1.5 kW1.5\ \text{kW}1.5 kW heater in 2.0 h2.0\ \text{h}2.0 h, in kilowatt-hours.
- Describe what happens to the power transferred in a resistor when the current through it is doubled.
3.2.13 Energy and power in resistor circuits
Equivalent resistance
Equivalent resistance
The resistance of a single resistor that could replace a combination of resistors and draw the same current from the same supply.
- Several resistors in series can be replaced, in a calculation, by one resistor with the same overall effect on the circuit.
- For resistors in series, the equivalent resistance is the sum of the individual resistances, Req=R1+R2+R3R_{\text{eq}} = R_1 + R_2 + R_3Req=R1+R2+R3.
- This works because the same current flows through every resistor, and the potential differences across them add up to the supply potential difference.
- The current drawn from the supply is found by dividing the supply potential difference by the equivalent resistance, I=VsupplyReqI = \dfrac{V_{\text{supply}}}{R_{\text{eq}}}I=ReqVsupply.
- Adding another resistor in series increases the equivalent resistance, so for the same supply the current falls.
The equations you need
- All of these equations must be recalled, so learn each one with its units.
- Charge: Q=ItQ = ItQ=It, with charge in coulombs, C\text{C}C, current in amperes, A\text{A}A, and time in seconds, s\text{s}s.
- Potential difference: V=IRV = IRV=IR, with potential difference in volts, V\text{V}V, and resistance in ohms, Ω\OmegaΩ.
- Energy from charge: E=QVE = QVE=QV, with energy in joules, J\text{J}J.
- Power from potential difference: P=VIP = VIP=VI, with power in watts, W\text{W}W.
- Power from resistance: P=I2RP = I^2RP=I2R.
- Energy from power: E=PtE = PtE=Pt, with energy in joules and time in seconds, or energy in kW h\text{kW h}kW h with power in kW\text{kW}kW and time in hours.
Solving series circuit problems
- Add the resistances to find the equivalent resistance of the circuit.
- Use I=VReqI = \dfrac{V}{R_{\text{eq}}}I=ReqV with the supply potential difference to find the current, which is the same through every resistor.
- Use V=IRV = IRV=IR with each resistor's own resistance to find the potential difference across it.
- Use P=VIP = VIP=VI or P=I2RP = I^2RP=I2R to find the power of each resistor or of the whole circuit.
- Use E=PtE = PtE=Pt or E=QVE = QVE=QV to find the energy transferred in a given time, and Q=ItQ = ItQ=It to find the charge that flows.
- Check the answers using conservation of energy.
- The potential differences across the resistors add up to the supply potential difference.
- The powers of the resistors add up to the power supplied by the source.
Comparing resistors in series
- Every resistor in a series circuit carries the same current, so by P=I2RP = I^2RP=I2R the resistor with the larger resistance transfers energy at the greater rate.
- The larger resistor also has the larger potential difference across it, so each coulomb transfers more energy in that resistor.
- When an extra resistor is added in series, the current falls, so the power of each of the original resistors decreases.
Energy and power in two series resistors
- A 6.0 V6.0\ \text{V}6.0 V supply is connected in series with a 2.0 Ω2.0\ \Omega2.0 Ω resistor and a 4.0 Ω4.0\ \Omega4.0 Ω resistor for 5.05.05.0 minutes.
- The energy can be checked with E=QV=300 C×6.0 V=1800 JE = QV = 300\ \text{C} \times 6.0\ \text{V} = 1800\ \text{J}E=QV=300 C×6.0 V=1800 J, which agrees.
Finding an unknown resistance
- A lamp is connected in series with an 8.0 Ω8.0\ \Omega8.0 Ω resistor and a 12 V12\ \text{V}12 V battery, and the potential difference across the lamp is 4.0 V4.0\ \text{V}4.0 V.
- In 2.02.02.0 minutes, the charge through the lamp and the energy it transfers are found next.
- Do not use the supply potential difference with the resistance of one resistor, because each value in V=IRV = IRV=IR must belong to the same part of the circuit.
- Do not confuse E=PtE = PtE=Pt with P=EtP = \dfrac{E}{t}P=tE when rearranging, and always convert minutes or hours into seconds when working in joules.
- Do not round values part way through a calculation, because rounding early can change the final answer.
Multi-step circuit problems
- Before you start a long calculation, list the values you know and the quantity you need, then pick the equation that links them.
- Show every step with its substitution, because method marks are given even if an earlier slip carries an error forward.
- Use a second equation to check your final energy or power where you can, such as E=PtE = PtE=Pt checked against E=QVE = QVE=QV.
- State how to find the equivalent resistance of resistors in series.
- Write down the equation linking energy, charge and potential difference.
- Calculate the current from a 9.0 V9.0\ \text{V}9.0 V battery connected to 1.0 Ω1.0\ \Omega1.0 Ω and 2.0 Ω2.0\ \Omega2.0 Ω resistors in series.
- Explain which of two resistors in series transfers energy at the greater rate.
- Calculate the charge that flows when a current of 0.50 A0.50\ \text{A}0.50 A passes for 4.04.04.0 minutes.