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6.1.6 Representing radioactive decay

Symbols for nuclear particles

  1. Particles emitted in radioactive decay are written in the same way as nuclei, with a top number and a bottom number.
  2. The top number shows the mass number, which is the relative mass in nucleons.
  3. The bottom number shows the relative charge, which for a nucleus is its atomic number.
  4. An alpha particle is written 24He{}^{4}_{2}\text{He}24​He or 24α{}^{4}_{2}\alpha24​α, because it has a mass of 444 and a charge of +2+2+2.
  5. A beta particle is written −10e{}^{0}_{-1}\text{e}−10​e or −10β{}^{0}_{-1}\beta−10​β, because its mass is almost zero and its charge is −1-1−1.
  6. A gamma ray is written 00γ{}^{0}_{0}\gamma00​γ, because it has no mass and no charge.
  7. A neutron is written 01n{}^{1}_{0}\text{n}01​n, because it has a mass of 111 and no charge.
  8. A proton is written 11p{}^{1}_{1}\text{p}11​p, or 11H{}^{1}_{1}\text{H}11​H because it is the nucleus of hydrogen-1.

Writing a decay equation

Definition

Decay equation

An equation that shows an unstable parent nucleus changing into a daughter nucleus and the radiation it emits.

  1. A decay equation shows the parent nucleus on the left of an arrow and the daughter nucleus and the emitted radiation on the right.
  2. Every nucleus and particle in the equation is written with its symbol, mass number and charge.
  3. A decay equation is written in four steps.
    1. Write the symbol for the parent nucleus, followed by an arrow.
    2. Write the symbol for the emitted particle on the right of the arrow.
    3. Work out the mass number and atomic number of the daughter nucleus from the change caused by the particle.
    4. Use the atomic number to find the chemical symbol of the daughter nucleus from the periodic table, or from the data in the question.
  4. The two sides of the equation must match in total mass number and in total charge, because nucleons and charge are neither created nor destroyed.

Common decay equations

  1. Uranium-238 emits an alpha particle and becomes thorium-234, so 92238U→90234Th+24He{}^{238}_{92}\text{U} \rightarrow {}^{234}_{90}\text{Th} + {}^{4}_{2}\text{He}92238​U→90234​Th+24​He.
  2. Radium-226 emits an alpha particle and becomes radon-222, so 88226Ra→86222Rn+24He{}^{226}_{88}\text{Ra} \rightarrow {}^{222}_{86}\text{Rn} + {}^{4}_{2}\text{He}88226​Ra→86222​Rn+24​He.
  3. Americium-241 emits an alpha particle and becomes neptunium-237, so 95241Am→93237Np+24He{}^{241}_{95}\text{Am} \rightarrow {}^{237}_{93}\text{Np} + {}^{4}_{2}\text{He}95241​Am→93237​Np+24​He.
  4. Carbon-14 emits a beta particle and becomes nitrogen-14, so 614C→714N+−10e{}^{14}_{6}\text{C} \rightarrow {}^{14}_{7}\text{N} + {}^{0}_{-1}\text{e}614​C→714​N+−10​e.
  5. Iodine-131 emits a beta particle and becomes xenon-131, so 53131I→54131Xe+−10e{}^{131}_{53}\text{I} \rightarrow {}^{131}_{54}\text{Xe} + {}^{0}_{-1}\text{e}53131​I→54131​Xe+−10​e.
  6. Cobalt-60 emits a beta particle and a gamma ray and becomes nickel-60, so 2760Co→2860Ni+−10e+00γ{}^{60}_{27}\text{Co} \rightarrow {}^{60}_{28}\text{Ni} + {}^{0}_{-1}\text{e} + {}^{0}_{0}\gamma2760​Co→2860​Ni+−10​e+00​γ.
Example

Writing an alpha decay equation

  • Polonium-210, 84210Po{}^{210}_{84}\text{Po}84210​Po, decays by emitting an alpha particle, and the element with atomic number 828282 is lead.
  • The parent nucleus and the alpha particle are written first.
84210Po→daughter+24He {}^{210}_{84}\text{Po} \rightarrow \text{daughter} + {}^{4}_{2}\text{He} 84210​Po→daughter+24​He
  • The daughter nucleus has a mass number of 210−4=206210 - 4 = 206210−4=206 and an atomic number of 84−2=8284 - 2 = 8284−2=82.
  • An atomic number of 828282 means the daughter nucleus is lead.
84210Po→82206Pb+24He {}^{210}_{84}\text{Po} \rightarrow {}^{206}_{82}\text{Pb} + {}^{4}_{2}\text{He} 84210​Po→82206​Pb+24​He
Example

Writing a beta decay equation

  • Strontium-90, 3890Sr{}^{90}_{38}\text{Sr}3890​Sr, decays by emitting a beta particle, and the element with atomic number 393939 is yttrium.
  • The parent nucleus and the beta particle are written first.
3890Sr→daughter+−10e {}^{90}_{38}\text{Sr} \rightarrow \text{daughter} + {}^{0}_{-1}\text{e} 3890​Sr→daughter+−10​e
  • The daughter nucleus keeps a mass number of 909090, and its atomic number rises to 38+1=3938 + 1 = 3938+1=39.
  • An atomic number of 393939 means the daughter nucleus is yttrium.
3890Sr→3990Y+−10e {}^{90}_{38}\text{Sr} \rightarrow {}^{90}_{39}\text{Y} + {}^{0}_{-1}\text{e} 3890​Sr→3990​Y+−10​e
Common Mistake
  • Do not write the beta particle as +10e{}^{0}_{+1}\text{e}+10​e or −11e{}^{1}_{-1}\text{e}−11​e, because its charge is −1-1−1 and its mass number is 000.
  • Do not keep the parent symbol for the daughter nucleus after alpha or beta decay, because the change in atomic number makes it a new element.
  • Do not put the emitted particle on the left of the arrow, because it is a product of the decay.
Exam technique

Completing decay equations

  • Write all four numbers for every particle, because a symbol such as α\alphaα with no numbers often loses the mark.
  • Take the daughter element from the atomic number, using the periodic table or the list of elements given in the question.
  • Either 24He{}^{4}_{2}\text{He}24​He or 24α{}^{4}_{2}\alpha24​α is allowed for an alpha particle, and either −10e{}^{0}_{-1}\text{e}−10​e or −10β{}^{0}_{-1}\beta−10​β is allowed for a beta particle.
Self review
  • What does the bottom number of a particle in a decay equation represent?
  • How is a beta particle written in a decay equation?
  • What symbol is used for a gamma ray?
  • Write the symbol for a neutron.
  • What is the daughter nucleus when radium-226 emits an alpha particle?
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