The diagram shows a hydraulic press being used to multiply force.
An input force F1=80 NF_1 = 80\text{ N}F1=80 N is applied to the input piston, which has a cross-sectional area of 2.4 cm2.
What is the upward force F2 F_2\,F2 produced at the output piston of cross-sectional area 18.0 cm2?
Use the equation:
pressure=forcearea \text{pressure} = \frac{\text{force}}{\text{area}} pressure=areaforce10.7 N10.7\text{ N}10.7 N
33.3 N33.3\text{ N}33.3 N
600 N600\text{ N}600 N
4500 N4500\text{ N}4500 N