An electric winch with an efficiency of 70% is used to raise a crate of mass 150 kg vertically at a constant speed of 0.8 m s-1.
Calculate the electrical power input to the winch.
(Take g=9.8 m s−2g = 9.8\text{ m s}^{-2}g=9.8 m s−2)
0.823 kW0.823\text{ kW}0.823 kW
1.176 kW1.176\text{ kW}1.176 kW
1.680 kW1.680\text{ kW}1.680 kW
2.625 kW2.625\text{ kW}2.625 kW