A cyclist accelerates uniformly from 4.0 m/s to 10 m/s. The acceleration is 1.4 m/s2.
Use the equation: (final velocity)2−(initial velocity)2=2×acceleration×distance(\text{final velocity})^2 - (\text{initial velocity})^2 = 2 \times \text{acceleration} \times \text{distance}(final velocity)2−(initial velocity)2=2×acceleration×distance
How far does the cyclist travel while accelerating?
30 m30\ \text{m}30 m
35.7 m35.7\ \text{m}35.7 m
60 m60\ \text{m}60 m
117.6 m117.6\ \text{m}117.6 m
43 exam-style questions on OCR GCSE Physics 2.1 Motion, covering 2.1.1 Measuring distance and time, 2.1.2 Measuring speed, 2.1.3 Ratios, units and rates in motion, 2.1.4 Scalars and vectors in motion, 2.1.5 Distance-time and velocity-time graphs, 2.1.6 Area under a velocity-time graph, 2.1.7 Average speed for non-uniform motion, and 2.1.8 Uniform motion and uniform acceleration. Each one has a worked solution and a mark scheme showing where the marks go.