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3.2.7 Linear and non-linear circuit components

Current-potential difference graphs

Definition

Current-potential difference graph

A graph of the current through a component plotted against the potential difference across it.

  1. A current-potential difference graph shows how the current through a component changes as the potential difference across it changes.
  2. The potential difference is the independent variable, so it is plotted on the horizontal axis, in volts, V\text{V}V.
  3. The current is the dependent variable, so it is plotted on the vertical axis, in amperes, A\text{A}A.
  4. Positive values show the current in one direction, and negative values show the current flowing the opposite way after the supply connections are reversed.
  5. The resistance at any point on the graph is found by reading off VVV and III at that point and calculating R=VIR = \dfrac{V}{I}R=IV​.
    1. A steeper line means more current for each volt, so it shows a smaller resistance.
    2. A shallower line means less current for each volt, so it shows a larger resistance.

Linear components

Definition

Linear component

A component whose current-potential difference graph is a straight line through the origin, so the current is directly proportional to the potential difference.

  1. The graph of a linear component is a straight line through the origin.
  2. Equal increases in potential difference produce equal increases in current, so the current is directly proportional to the potential difference.
  3. Because VI\dfrac{V}{I}IV​ is the same at every point on the line, a linear component has a constant resistance.
  4. A fixed resistor and a metal wire at constant temperature are linear components.
  5. The line has the same shape for negative values, because these components behave in the same way whichever direction the current flows.
  6. Two linear components can be compared by the steepness of their lines, with the steeper line belonging to the component with the smaller resistance.

Non-linear components

Definition

Non-linear component

A component whose current-potential difference graph is curved, so the current is not directly proportional to the potential difference.

  1. The graph of a non-linear component is curved.
  2. Equal increases in potential difference produce unequal changes in current, so the current is not directly proportional to the potential difference.
  3. Because VI\dfrac{V}{I}IV​ is different at different points on the curve, a non-linear component has a resistance that changes.
  4. The direction in which the curve bends shows how the resistance changes.
    1. A curve that becomes less steep as the potential difference increases shows a resistance that is increasing.
    2. A curve that becomes steeper as the potential difference increases shows a resistance that is decreasing.
  5. A filament lamp, a diode and a thermistor that warms up as the current increases are all non-linear components.

Deciding from data

  1. To decide from a table of results, calculate IV\dfrac{I}{V}VI​ or VI\dfrac{V}{I}IV​ for each row.
    1. If the ratio is the same for every row, the component is linear.
    2. If the ratio changes steadily from row to row, the component is non-linear.
  2. To decide from a graph, lay a ruler along the plotted points and check whether they lie on a straight line that passes through the origin.
  3. A single point that lies well away from an otherwise smooth pattern is an anomaly and should be checked or repeated, not used to change the line.
Example

Linear or non-linear

  • Component X gives 0.20 A0.20\ \text{A}0.20 A at 1.0 V1.0\ \text{V}1.0 V, 0.40 A0.40\ \text{A}0.40 A at 2.0 V2.0\ \text{V}2.0 V and 0.80 A0.80\ \text{A}0.80 A at 4.0 V4.0\ \text{V}4.0 V.
VI=1.00.20=2.00.40=4.00.80=5.0 Ω \dfrac{V}{I} = \dfrac{1.0}{0.20} = \dfrac{2.0}{0.40} = \dfrac{4.0}{0.80} = 5.0\ \Omega IV​=0.201.0​=0.402.0​=0.804.0​=5.0 Ω
  • The ratio is the same for every reading, so component X is linear with a constant resistance of 5.0 Ω5.0\ \Omega5.0 Ω.
  • Component Y gives 0.20 A0.20\ \text{A}0.20 A at 1.0 V1.0\ \text{V}1.0 V, 0.32 A0.32\ \text{A}0.32 A at 2.0 V2.0\ \text{V}2.0 V and 0.45 A0.45\ \text{A}0.45 A at 4.0 V4.0\ \text{V}4.0 V.
1.00.20=5.0 Ω,2.00.32=6.3 Ω,4.00.45=8.9 Ω \dfrac{1.0}{0.20} = 5.0\ \Omega, \quad \dfrac{2.0}{0.32} = 6.3\ \Omega, \quad \dfrac{4.0}{0.45} = 8.9\ \Omega 0.201.0​=5.0 Ω,0.322.0​=6.3 Ω,0.454.0​=8.9 Ω
  • The ratio rises as the potential difference increases, so component Y is non-linear and its resistance is increasing.
Practical

Current-potential difference characteristic of a resistor

  • Aim: to obtain the current-potential difference characteristic of a fixed resistor and use it to decide whether the resistor is linear.
  • Apparatus: a 10 Ω10\ \Omega10 Ω fixed resistor, a d.c. power supply set to 6 V6\ \text{V}6 V, a variable resistor, a switch, a digital ammeter, a digital voltmeter and connecting leads.
  • Method, positive readings:
    • Connect the supply, switch, variable resistor, ammeter and fixed resistor in series, with the voltmeter across the fixed resistor only.
    • Set the variable resistor to its largest resistance so that the first current is small.
    • Close the switch and record the potential difference and the current, then open the switch.
    • Reduce the setting of the variable resistor in steps to give about six readings, roughly 0.5 V0.5\ \text{V}0.5 V apart, up to about 3.0 V3.0\ \text{V}3.0 V.
  • Method, negative readings:
    • Swap the two leads at the supply terminals so the current flows the other way through the resistor.
    • Take a second set of six readings and record them as negative values of current and potential difference.
  • Method, processing:
    • Repeat every reading twice more and calculate means.
    • Plot current on the vertical axis against potential difference on the horizontal axis, with both axes running through negative values, and draw a line of best fit.
  • Results: the points lie on a straight line through the origin that continues into the negative quarter of the graph.
  • Conclusion: the fixed resistor is a linear component, because the current is directly proportional to the potential difference in both directions.
  • Watch out: label both axes with the quantity and the unit, use a scale that fills most of the grid, and draw a single ruled line of best fit, not a line joining the points.
  • Safety: keep the current small and open the switch between readings, because a resistor carrying a large current can become hot.
Common Mistake
  • Do not use the gradient of the line as the resistance, because resistance is VI\dfrac{V}{I}IV​ read at a point and the gradient of this graph is IV\dfrac{I}{V}VI​.
  • Do not describe every straight line as proportional, because the line must also pass through the origin.
  • Do not join the points dot to dot, because a line or curve of best fit shows the true pattern.
Exam technique

Describing graphs

  • When you describe a linear component, use the phrase straight line through the origin and say that the current is directly proportional to the potential difference.
  • When you describe a non-linear component, say that the graph is curved and state whether it becomes steeper or less steep.
  • Support your decision with numbers, by calculating VI\dfrac{V}{I}IV​ at two points and showing that the values are the same or different.
Self review
  • State which quantity is plotted on each axis of a current-potential difference graph.
  • Describe the graph of a linear component.
  • Explain how a curved current-potential difference graph shows that resistance is changing.
  • State what a negative value of current on the graph represents.
  • Describe how to use a table of readings to decide whether a component is linear.
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3.2.7 Linear and non-linear circuit components Revision Guide

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Revision notes for OCR GCSE Physics 3.2.7 Linear and non-linear circuit components: explanations and worked examples.

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