Current-potential difference graphs
Definition
Current-potential difference graph
A graph of the current through a component plotted against the potential difference across it.
- A current-potential difference graph shows how the current through a component changes as the potential difference across it changes.
- The potential difference is the independent variable, so it is plotted on the horizontal axis, in volts, V\text{V}V.
- The current is the dependent variable, so it is plotted on the vertical axis, in amperes, A\text{A}A.
- Positive values show the current in one direction, and negative values show the current flowing the opposite way after the supply connections are reversed.
- The resistance at any point on the graph is found by reading off VVV and III at that point and calculating R=VIR = \dfrac{V}{I}R=IV.
- A steeper line means more current for each volt, so it shows a smaller resistance.
- A shallower line means less current for each volt, so it shows a larger resistance.
Linear components
Definition
Linear component
A component whose current-potential difference graph is a straight line through the origin, so the current is directly proportional to the potential difference.
- The graph of a linear component is a straight line through the origin.
- Equal increases in potential difference produce equal increases in current, so the current is directly proportional to the potential difference.
- Because VI\dfrac{V}{I}IV is the same at every point on the line, a linear component has a constant resistance.
- A fixed resistor and a metal wire at constant temperature are linear components.
- The line has the same shape for negative values, because these components behave in the same way whichever direction the current flows.
- Two linear components can be compared by the steepness of their lines, with the steeper line belonging to the component with the smaller resistance.
Non-linear components
Definition
Non-linear component
A component whose current-potential difference graph is curved, so the current is not directly proportional to the potential difference.
- The graph of a non-linear component is curved.
- Equal increases in potential difference produce unequal changes in current, so the current is not directly proportional to the potential difference.
- Because VI\dfrac{V}{I}IV is different at different points on the curve, a non-linear component has a resistance that changes.
- The direction in which the curve bends shows how the resistance changes.
- A curve that becomes less steep as the potential difference increases shows a resistance that is increasing.
- A curve that becomes steeper as the potential difference increases shows a resistance that is decreasing.
- A filament lamp, a diode and a thermistor that warms up as the current increases are all non-linear components.
Deciding from data
- To decide from a table of results, calculate IV\dfrac{I}{V}VI or VI\dfrac{V}{I}IV for each row.
- If the ratio is the same for every row, the component is linear.
- If the ratio changes steadily from row to row, the component is non-linear.
- To decide from a graph, lay a ruler along the plotted points and check whether they lie on a straight line that passes through the origin.
- A single point that lies well away from an otherwise smooth pattern is an anomaly and should be checked or repeated, not used to change the line.
Example
Linear or non-linear
- Component X gives 0.20 A0.20\ \text{A}0.20 A at 1.0 V1.0\ \text{V}1.0 V, 0.40 A0.40\ \text{A}0.40 A at 2.0 V2.0\ \text{V}2.0 V and 0.80 A0.80\ \text{A}0.80 A at 4.0 V4.0\ \text{V}4.0 V.
- The ratio is the same for every reading, so component X is linear with a constant resistance of 5.0 Ω5.0\ \Omega5.0 Ω.
- Component Y gives 0.20 A0.20\ \text{A}0.20 A at 1.0 V1.0\ \text{V}1.0 V, 0.32 A0.32\ \text{A}0.32 A at 2.0 V2.0\ \text{V}2.0 V and 0.45 A0.45\ \text{A}0.45 A at 4.0 V4.0\ \text{V}4.0 V.
- The ratio rises as the potential difference increases, so component Y is non-linear and its resistance is increasing.
Practical
Current-potential difference characteristic of a resistor
- Aim: to obtain the current-potential difference characteristic of a fixed resistor and use it to decide whether the resistor is linear.
- Apparatus: a 10 Ω10\ \Omega10 Ω fixed resistor, a d.c. power supply set to 6 V6\ \text{V}6 V, a variable resistor, a switch, a digital ammeter, a digital voltmeter and connecting leads.
- Method, positive readings:
- Connect the supply, switch, variable resistor, ammeter and fixed resistor in series, with the voltmeter across the fixed resistor only.
- Set the variable resistor to its largest resistance so that the first current is small.
- Close the switch and record the potential difference and the current, then open the switch.
- Reduce the setting of the variable resistor in steps to give about six readings, roughly 0.5 V0.5\ \text{V}0.5 V apart, up to about 3.0 V3.0\ \text{V}3.0 V.
- Method, negative readings:
- Swap the two leads at the supply terminals so the current flows the other way through the resistor.
- Take a second set of six readings and record them as negative values of current and potential difference.
- Method, processing:
- Repeat every reading twice more and calculate means.
- Plot current on the vertical axis against potential difference on the horizontal axis, with both axes running through negative values, and draw a line of best fit.
- Results: the points lie on a straight line through the origin that continues into the negative quarter of the graph.
- Conclusion: the fixed resistor is a linear component, because the current is directly proportional to the potential difference in both directions.
- Watch out: label both axes with the quantity and the unit, use a scale that fills most of the grid, and draw a single ruled line of best fit, not a line joining the points.
- Safety: keep the current small and open the switch between readings, because a resistor carrying a large current can become hot.
Common Mistake
- Do not use the gradient of the line as the resistance, because resistance is VI\dfrac{V}{I}IV read at a point and the gradient of this graph is IV\dfrac{I}{V}VI.
- Do not describe every straight line as proportional, because the line must also pass through the origin.
- Do not join the points dot to dot, because a line or curve of best fit shows the true pattern.
Exam technique
Describing graphs
- When you describe a linear component, use the phrase straight line through the origin and say that the current is directly proportional to the potential difference.
- When you describe a non-linear component, say that the graph is curved and state whether it becomes steeper or less steep.
- Support your decision with numbers, by calculating VI\dfrac{V}{I}IV at two points and showing that the values are the same or different.
Self review
- State which quantity is plotted on each axis of a current-potential difference graph.
- Describe the graph of a linear component.
- Explain how a curved current-potential difference graph shows that resistance is changing.
- State what a negative value of current on the graph represents.
- Describe how to use a table of readings to decide whether a component is linear.