A step-down transformer at a local substation supplies a street of houses.
The potential difference across the primary coil is 11 000 V11\,000\ \text{V}11000 V. The potential difference across the secondary coil is 230 V.
The current in the secondary coil is 550 A.
The transformer is 100% efficient.
Calculate the current in the primary coil.
Use the equation
VP×IP=VS×ISV_P \times I_P = V_S \times I_SVP×IP=VS×IS
The primary coil has 4400 turns.
Calculate the number of turns on the secondary coil.
Use the equation
VPVS=NPNS\displaystyle \frac{V_P}{V_S} = \frac{N_P}{N_S}VSVP=NSNP
Explain why step-down transformers are placed close to the homes they supply.
108 exam-style questions on Edexcel GCSE Physics 13.2 Transformers and the National Grid, covering 13.2.1 Transformers and induction, 13.2.2 The transformer turns-ratio equation, 13.2.3 The National Grid, 13.2.4 The transformer power equation, and 13.2.5 Advantages of high-voltage transmission. Each one has a worked solution and a mark scheme showing where the marks go.