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13.2 Transformers and the National Grid

13.2 Transformers and the National Grid

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Question 5

An alternating potential difference of 240 V is applied across the primary coil of a step-down transformer. This produces a potential difference of 12 V across the secondary coil. The primary coil has 3000 turns.

Calculate the number of turns in the secondary coil. Use the equation:

potential difference across primary coilpotential difference across secondary coil=number of turns on primary coilnumber of turns on secondary coil \frac{\text{potential difference across primary coil}}{\text{potential difference across secondary coil}} = \frac{\text{number of turns on primary coil}}{\text{number of turns on secondary coil}} potential difference across secondary coilpotential difference across primary coil​=number of turns on secondary coilnumber of turns on primary coil​
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Markscheme

13.2 Transformers and the National Grid Questions

  1. GCSE
  2. /Physics
  3. /13.2 Transformers and the National Grid

28 exam-style questions on Edexcel GCSE Physics 13.2 Transformers and the National Grid. Each one has a worked solution and a mark scheme showing where the marks go.

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