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6 Radioactivity

6 Radioactivity

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Question 78

Fluorine-18 is a widely used radiopharmaceutical tracer in positron emission tomography (PET) imaging. It decays via positron (β+\beta^+β+) emission, during which a proton inside the nucleus decays according to the equation:

11p⟶01n++10e+νe {}^1_1\text{p} \longrightarrow {}^1_0\text{n} + {}^0_{+1}\text{e} + \nu_{\text{e}} 11​p⟶01​n++10​e+νe​

Deduce which nucleus is formed when a fluorine-18 nucleus undergoes this decay.

Use the list of proton (atomic) numbers to help you:

  • Nitrogen (N): proton number = 7
  • Oxygen (O): proton number = 8
  • Fluorine (F): proton number = 9
  • Neon (Ne): proton number = 10
A

neon-18

B

oxygen-18

C

oxygen-17

D

fluorine-17

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6 Radioactivity Questions

  1. GCSE
  2. /Physics
  3. /6 Radioactivity

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