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6.3 Nuclear equations and decay

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Question 63
F

The equation represents alpha decay.

84210Po→ZAPb+24He {}^{210}_{84}\mathrm{Po}\rightarrow{}^{A}_{Z}\mathrm{Pb}+{}^{4}_{2}\mathrm{He} 84210​Po→ZA​Pb+24​He

Which values complete the equation?

[1]
A

A=208A=208A=208 and Z=82Z=82Z=82

B

A=206A=206A=206 and Z=82Z=82Z=82

C

A=210A=210A=210 and Z=82Z=82Z=82

D

A=206A=206A=206 and Z=84Z=84Z=84

Markscheme

6.3 Nuclear equations and decay Questions

  1. GCSE
  2. /Physics
  3. /6.3 Nuclear equations and decay

120 exam-style questions on Edexcel GCSE Physics 6.3 Nuclear equations and decay, covering 6.3.1 Beta-minus and beta-plus decay, 6.3.2 Effects of decay on the nucleus, and 6.3.3 Balancing nuclear equations. Each one has a worked solution and a mark scheme showing where the marks go.

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