A force is applied to the end of a 0.40 m handle. The line of action is 0.24 m from the pivot, measured perpendicularly. A moment of 18 N m is required. What force is needed?
45 N45\ \mathrm{N}45 N
43.2 N43.2\ \mathrm{N}43.2 N
75 N75\ \mathrm{N}75 N
112.5 N112.5\ \mathrm{N}112.5 N
102 exam-style questions on Edexcel GCSE Physics 9.2 Moments, covering 9.2.1 Rotational effects of forces and moments, 9.2.2 The principle of moments, and 9.2.3 Levers and gears. Each one has a worked solution and a mark scheme showing where the marks go.