Figure 1 shows a uniform steel balance beam pivoted at its centre.
A calibration weight is suspended from the left side of the beam, exerting a downward vertical force of 8.4 N at a distance of 0.35 m from the central pivot.
Calculate the moment of this weight about the pivot in N m\text{N m}N m. Use the equation:
moment of a force=force×distance \text{moment of a force} = \text{force} \times \text{distance} moment of a force=force×distance