Which of these is the correct equation to calculate the moment of a force?
moment of a force=force×perpendicular distance from the pivot\text{moment of a force} = \text{force} \times \text{perpendicular distance from the pivot}moment of a force=force×perpendicular distance from the pivot
moment of a force=force÷perpendicular distance from the pivot\text{moment of a force} = \text{force} \div \text{perpendicular distance from the pivot}moment of a force=force÷perpendicular distance from the pivot
moment of a force=force×distance moved in the direction of the force\text{moment of a force} = \text{force} \times \text{distance moved in the direction of the force}moment of a force=force×distance moved in the direction of the force
moment of a force=force÷distance moved in the direction of the force\text{moment of a force} = \text{force} \div \text{distance moved in the direction of the force}moment of a force=force÷distance moved in the direction of the force
9 exam-style questions on Edexcel GCSE Physics 9.2 Moments (physics only). Each one has a worked solution and a mark scheme showing where the marks go.