The table shows measurements from a heating experiment.
| Measurement | Value |
|---|---|
| Mass of empty beaker | 0.15 kg |
| Mass of beaker and liquid | 0.55 kg |
| Temperature rise of liquid | 15 ∘C15\ ^\circ\mathrm{C}15 ∘C |
| Energy transferred to liquid | 12000 J |
What is the specific heat capacity of the liquid? Use ΔQ=mcΔθ\Delta Q=mc\Delta\thetaΔQ=mcΔθ.
1450 J kg−1 ∘C−11450\ \mathrm{J\,kg^{-1}\,{}^\circ C^{-1}}1450 Jkg−1∘C−1
1140 J kg−1 ∘C−11140\ \mathrm{J\,kg^{-1}\,{}^\circ C^{-1}}1140 Jkg−1∘C−1
2000 J kg−1 ∘C−12000\ \mathrm{J\,kg^{-1}\,{}^\circ C^{-1}}2000 Jkg−1∘C−1
5330 J kg−1 ∘C−15330\ \mathrm{J\,kg^{-1}\,{}^\circ C^{-1}}5330 Jkg−1∘C−1
110 exam-style questions on Edexcel GCSE Physics 14.2 Specific heat capacity and latent heat, covering 14.2.1 Heating, temperature and changes of state, 14.2.2 Specific heat capacity and specific latent heat, 14.2.3 Specific heat capacity calculation, 14.2.4 Specific latent heat calculation, and 14.2.5 Reducing energy transfer through thermal insulation. Each one has a worked solution and a mark scheme showing where the marks go.