A 0.40 kg sample absorbs 24000 J and warms from 10 ∘C10\ ^\circ\mathrm{C}10 ∘C to its melting point of 50 ∘C50\ ^\circ\mathrm{C}50 ∘C. It then absorbs a further 60000 J while melting completely. What are its specific heat capacity and specific latent heat of fusion?
1200 J kg−1 ∘C−11200\ \mathrm{J\,kg^{-1}\,{}^\circ C^{-1}}1200 Jkg−1∘C−1 and 210000 J/kg210000\ \mathrm{J/kg}210000 J/kg
1500 J kg−1 ∘C−11500\ \mathrm{J\,kg^{-1}\,{}^\circ C^{-1}}1500 Jkg−1∘C−1 and 150000 J/kg150000\ \mathrm{J/kg}150000 J/kg
1500 J kg−1 ∘C−11500\ \mathrm{J\,kg^{-1}\,{}^\circ C^{-1}}1500 Jkg−1∘C−1 and 210000 J/kg210000\ \mathrm{J/kg}210000 J/kg
1200 J kg−1 ∘C−11200\ \mathrm{J\,kg^{-1}\,{}^\circ C^{-1}}1200 Jkg−1∘C−1 and 150000 J/kg150000\ \mathrm{J/kg}150000 J/kg
110 exam-style questions on Edexcel GCSE Physics 14.2 Specific heat capacity and latent heat, covering 14.2.1 Heating, temperature and changes of state, 14.2.2 Specific heat capacity and specific latent heat, 14.2.3 Specific heat capacity calculation, 14.2.4 Specific latent heat calculation, and 14.2.5 Reducing energy transfer through thermal insulation. Each one has a worked solution and a mark scheme showing where the marks go.