A sealed actuator contains a fixed mass of gas. The gas is compressed at constant temperature, and no gas escapes.
The gas initially occupies 0.40 litres0.40\ \text{litres}0.40 litres at a pressure of 120 kPa. Its volume is reduced to 0.25 litres0.25\ \text{litres}0.25 litres.
Calculate the new pressure of the gas.
Use the equation
P1×V1=P2×V2P_1 \times V_1 = P_2 \times V_2P1×V1=P2×V2
108 exam-style questions on Edexcel GCSE Physics 14.3 Gas pressure and temperature, covering 14.3.1 Gas pressure and particle motion, 14.3.2 Temperature and pressure at constant volume, 14.3.3 Absolute zero and the kelvin scale, 14.3.4 Compressing and expanding gases, 14.3.5 Volume and pressure at constant temperature, and 14.3.6 Doing work on a gas. Each one has a worked solution and a mark scheme showing where the marks go.