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bg-background","children":["$","$L3a",null,{"backHref":"/gcse/physics/edexcel/questions","basePath":"/gcse/physics/edexcel/forces-and-springs/questions","formulaUrl":"https://qualifications.pearson.com/content/dam/pdf/GCSE/Science/2016/teaching-and-learning-materials/gcse-physics-exam-aid-1ph0-1sc0-june-2025.pdf","initialIndex":2,"initialQuestionWindow":[{"id":"0391727c-76a8-4a41-9a78-e5d9b231fc03","revisionId":"f2a2ba12-4765-45ee-b7f9-53c91401d4f2","questionNumber":null,"questionType":"LA","specification":"","difficulty":2,"difficultyBand":"easy","tier":null,"totalMarks":2,"sourceTitle":null,"calculatorUse":null,"isCalculation":true,"parts":[{"id":"e6953693-1b46-4099-8c07-9363da738268","label":null,"content":"A student investigates the stretching of a spring in a physics laboratory.\n\nThe spring constant ($k$) of the spring is $25\\text{ N/m}$.\n\nThe spring is stretched so that its extension is $0.080\\text{ m}$.\n\nCalculate the force applied to stretch the spring.\n\nUse the equation:\n$$\\text{force} = \\text{spring constant} \\times \\text{extension}$$","markscheme":"- Substitutes the given values into the formula: $25 \\times 0.080$ M1\n- Evaluates to get $2.0\\text{ N}$ (or $2\\text{ N}$) A1","marks":2,"order":0,"markingRubric":null,"tableImages":[],"explanation":{"methods":[{"id":"hookes_law_substitution","label":"Substitute into the formula","steps":[{"type":"hyper_latex","block":{"nodes":[{"latex":"F=\\htmlData{anchor=substitution}{25\\times0.080}"},{"latex":"F=\\htmlData{anchor=force}{2.0\\text{ N}}"}],"highlights":[{"color":"amber","style":"box","anchor":"substitution"},{"color":"green","style":"box","anchor":"force"}],"connections":[{"to":"force","from":"substitution","color":"sky","label":"calculate"}]},"order":1,"title":"Calculate the force","description":"Substituting 25 × 0.080 earns M1. Evaluating this as 2.0 N earns A1."}]}],"generatedAt":"2026-07-22T09:05:43.610Z","modelVersion":"gpt-5.6-terra+diagrams-1","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":{"methods":[{"id":"e6953693-1b46-4099-8c07-9363da738268:hookes_law_substitution","label":"Substitute into the formula","steps":[{"type":"hyper_latex","block":{"nodes":[{"latex":"F=\\htmlData{anchor=substitution}{25\\times0.080}"},{"latex":"F=\\htmlData{anchor=force}{2.0\\text{ N}}"}],"highlights":[{"color":"amber","style":"box","anchor":"substitution"},{"color":"green","style":"box","anchor":"force"}],"connections":[{"to":"force","from":"substitution","color":"sky","label":"calculate"}]},"order":1,"title":"Calculate the force","description":"Substituting 25 × 0.080 earns M1. Evaluating this as 2.0 N earns A1."}]}],"generatedAt":"2026-08-24T02:41:16.557Z","modelVersion":"gemini-3.5-flash","explanationVersion":"v2"},"firstAttemptFullMarks":null,"walkthroughVideo":null},{"id":"13f00793-1552-4810-91f2-9dd581373b63","revisionId":"f345e940-9e7c-416f-a7d4-207700024b0b","questionNumber":null,"questionType":"LA","specification":"","difficulty":3,"difficultyBand":"easy","tier":null,"totalMarks":2,"sourceTitle":null,"calculatorUse":null,"isCalculation":true,"parts":[{"id":"bcbdb495-0be8-467f-b8ad-47da7fe6de44","label":null,"content":"State the two measurements that must be made to determine the extension of a steel spring when a $6.0\\text{ N}$ weight is suspended from it.","markscheme":"- Measure the original (unstretched) length of the spring before any weight is added B1\n- Measure the extended (stretched) length of the spring with the $6.0\\text{ N}$ weight suspended from it B1","marks":2,"order":0,"markingRubric":null,"tableImages":[],"explanation":{"methods":[{"id":"measure_extension","label":"Measure the two lengths","steps":[{"type":"text","order":0,"title":"Recall what extension means","content":"The **extension** is how much longer the spring becomes when the weight is added:\n\n$$\\text{extension}=\\text{stretched length}-\\text{original length}$$\n\nSo you need a length measurement from **before** loading and a length measurement from **after** loading."},{"type":"text","order":1,"title":"Measure original length","content":"Before adding the weight, use a ruler to measure the spring’s original, unstretched length. This earns the first mark.","highlights":[{"text":"extension of a steel spring","location":"specification"}]},{"type":"text","order":2,"title":"Measure the stretched length","content":"Suspend the $6.0\\text{ N}$ weight and measure the spring’s length again while the weight is hanging still. This is the **extended (stretched) length**, and stating this measurement earns the second B1 mark.","highlights":[{"text":"$$6.0\\text{ N}$ weight is suspended from it","location":"specification"}]}]}],"generatedAt":"2026-07-22T09:06:22.400Z","modelVersion":"gpt-5.6-terra+diagrams-1","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":{"methods":[{"id":"bcbdb495-0be8-467f-b8ad-47da7fe6de44:measure_extension","label":"Measure the two lengths","steps":[{"type":"text","order":0,"title":"Recall what extension means","content":"The **extension** is how much longer the spring becomes when the weight is added:\n\n$$\\text{extension}=\\text{stretched length}-\\text{original length}$$\n\nSo you need a length measurement from **before** loading and a length measurement from **after** loading."},{"type":"text","order":1,"title":"Measure original length","content":"Before adding the weight, use a ruler to measure the spring’s original, unstretched length. This earns the first mark.","highlights":[{"text":"extension of a steel spring","location":"specification"}]},{"type":"text","order":2,"title":"Measure the stretched length","content":"Suspend the $6.0\\text{ N}$ weight and measure the spring’s length again while the weight is hanging still. This is the **extended (stretched) length**, and stating this measurement earns the second B1 mark.","highlights":[{"text":"$$6.0\\text{ N}$ weight is suspended from it","location":"specification"}]}]}],"generatedAt":"2026-08-24T02:42:45.974Z","modelVersion":"gemini-3.5-flash","explanationVersion":"v2"},"firstAttemptFullMarks":null,"walkthroughVideo":null},{"id":"1b727972-1d58-4359-9606-59ba97ef03bb","revisionId":"07b55157-e195-41bf-a4a5-a7c19f897dfd","questionNumber":null,"questionType":"LA","specification":"A spring inside a mountain bike suspension fork has a spring constant of $320 \\text{ N/m}$.","difficulty":3,"difficultyBand":"easy","tier":null,"totalMarks":3,"sourceTitle":null,"calculatorUse":null,"isCalculation":true,"parts":[{"id":"37675b95-38b3-4409-a98b-a8b7be8eff45","label":null,"content":"Calculate the work done in stretching this spring by $0.15 \\text{ m}$.\n\nState the unit.\n\nUse the equation:\n$$E_e = \\frac{1}{2} k x^2$$","markscheme":"- Substitutes values into the equation: $E_e = 0.5 \\times 320 \\times 0.15^2$ M1\n- Calculates the value of $3.6$ A1\n- States the unit of work done / energy is $\\text{J}$ (or Joules) B1","marks":3,"order":0,"markingRubric":null,"tableImages":[],"explanation":{"methods":[{"id":"substitution","label":"Substitute into the equation","steps":[{"type":"text","order":0,"title":"Identify the equation","content":"The equation is given in the question, so use it directly. The spring constant is $k=320\\ \\text{N/m}$ and the extension is $x=0.15\\ \\text{m}$.\n\nThe highlighted wording tells you the quantity to calculate: the elastic energy stored, which is the work done in stretching the spring.","highlights":[{"text":"Calculate the work done in stretching this spring by $0.15 \\text{ m}$.","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"E_e = \\frac{1}{2}\\,\\htmlData{anchor=k-symbol}{k}\\,\\htmlData{anchor=x-symbol}{x^2}"},{"latex":"E_e = 0.5 \\times \\htmlData{anchor=k-value}{320} \\times \\htmlData{anchor=x-value}{0.15}^2"}],"highlights":[{"color":"sky","style":"box","anchor":"k-value"},{"color":"amber","style":"box","anchor":"x-value"}],"connections":[{"to":"k-value","from":"k-symbol","color":"sky","label":"substitute k"},{"to":"x-value","from":"x-symbol","color":"amber","label":"substitute x"}]},"order":1,"title":"Substitute the values","description":"Replace k with 320 N/m and x with 0.15 m. Writing this substitution earns the M1 mark, even if the arithmetic later slips."},{"type":"hyper_latex","block":{"nodes":[{"latex":"E_e = \\htmlData{anchor=expression}{0.5 \\times 320 \\times 0.15^2}"},{"latex":"E_e = \\htmlData{anchor=answer}{3.6}"},{"text":"Therefore, the work done is 3.6 J. The calculated value earns the A1 mark, and the joule unit earns the B1 mark."}],"highlights":[{"color":"green","style":"box","anchor":"answer"}],"connections":[{"to":"answer","from":"expression","color":"green","label":"calculate"}]},"order":2,"title":"Calculate the energy","description":"Now evaluate the expression to find the work done."}]}],"generatedAt":"2026-07-22T11:09:23.129Z","modelVersion":"gpt-5.6-terra+diagrams-1","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":{"methods":[{"id":"37675b95-38b3-4409-a98b-a8b7be8eff45:substitution","label":"Substitute into the equation","steps":[{"type":"text","order":0,"title":"Identify the equation","content":"The equation is given in the question, so use it directly. The spring constant is $k=320\\ \\text{N/m}$ and the extension is $x=0.15\\ \\text{m}$.\n\nThe highlighted wording tells you the quantity to calculate: the elastic energy stored, which is the work done in stretching the spring.","highlights":[{"text":"Calculate the work done in stretching this spring by $0.15 \\text{ m}$.","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"E_e = \\frac{1}{2}\\,\\htmlData{anchor=k-symbol}{k}\\,\\htmlData{anchor=x-symbol}{x^2}"},{"latex":"E_e = 0.5 \\times \\htmlData{anchor=k-value}{320} \\times \\htmlData{anchor=x-value}{0.15}^2"}],"highlights":[{"color":"sky","style":"box","anchor":"k-value"},{"color":"amber","style":"box","anchor":"x-value"}],"connections":[{"to":"k-value","from":"k-symbol","color":"sky","label":"substitute k"},{"to":"x-value","from":"x-symbol","color":"amber","label":"substitute x"}]},"order":1,"title":"Substitute the values","description":"Replace k with 320 N/m and x with 0.15 m. Writing this substitution earns the M1 mark, even if the arithmetic later slips."},{"type":"hyper_latex","block":{"nodes":[{"latex":"E_e = \\htmlData{anchor=expression}{0.5 \\times 320 \\times 0.15^2}"},{"latex":"E_e = \\htmlData{anchor=answer}{3.6}"},{"text":"Therefore, the work done is 3.6 J. The calculated value earns the A1 mark, and the joule unit earns the B1 mark."}],"highlights":[{"color":"green","style":"box","anchor":"answer"}],"connections":[{"to":"answer","from":"expression","color":"green","label":"calculate"}]},"order":2,"title":"Calculate the energy","description":"Now evaluate the expression to find the work done."}]}],"generatedAt":"2026-08-24T02:43:25.936Z","modelVersion":"gemini-3.5-flash","explanationVersion":"v2"},"firstAttemptFullMarks":null,"walkthroughVideo":null}],"subjectCode":"gcse_physics","summaries":[{"id":"0391727c-76a8-4a41-9a78-e5d9b231fc03","difficultyBand":"easy","calculatorUse":null,"totalMarks":2,"questionType":"LA","isCalculation":true},{"id":"0fb554ff-61ca-4a7b-9c35-eed8dac390ae","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"13f00793-1552-4810-91f2-9dd581373b63","difficultyBand":"easy","calculatorUse":null,"totalMarks":2,"questionType":"LA","isCalculation":true},{"id":"1b727972-1d58-4359-9606-59ba97ef03bb","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"307f1555-c01f-4964-8e9a-42948b8eb100","difficultyBand":"easy","calculatorUse":null,"totalMarks":2,"questionType":"LA","isCalculation":true},{"id":"432bcc6b-d77c-4f26-bd5b-a3bf55a1ea00","difficultyBand":"medium","calculatorUse":null,"totalMarks":2,"questionType":"LA","isCalculation":false},{"id":"4b31b83a-493e-482f-a02f-41eb0e99092e","difficultyBand":"medium","calculatorUse":null,"totalMarks":2,"questionType":"LA","isCalculation":true},{"id":"4bb6aa50-c866-4747-b701-6efe573ade59","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":false},{"id":"5171cc8b-4599-4893-af04-25e64e2d10ab","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"5c6ad43c-8410-4f06-8889-dd352de2678b","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"6c78998b-4959-4fee-8a77-f3998d3f757d","difficultyBand":"easy","calculatorUse":null,"totalMarks":2,"questionType":"LA","isCalculation":true},{"id":"6ef9146f-61cb-4d8a-abc9-a36c2e399e6f","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"74d243aa-dbb1-4ca4-955b-ef718d957f66","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"78544f05-b3b4-40a2-8480-a07082283bdf","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":false},{"id":"953ef71f-90e5-4ad0-9ee1-abba2d6f45ec","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"993e0f14-807b-40d8-91ed-f05ef4f2c1ff","difficultyBand":"easy","calculatorUse":null,"totalMarks":2,"questionType":"LA","isCalculation":true},{"id":"ac07fee8-4602-491a-9439-090058519493","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"ae8d43c3-fded-43ec-9890-ff9de533c4b0","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"aeff4fdf-23a7-4c35-a205-bfc7524e5eba","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":false},{"id":"bc946096-eb77-41e7-a242-81b20b5acbe3","difficultyBand":"easy","calculatorUse":null,"totalMarks":1,"questionType":"LA","isCalculation":false},{"id":"dbe41b68-c5cf-42fe-92c6-d3b5bdc6adf4","difficultyBand":"easy","calculatorUse":null,"totalMarks":1,"questionType":"LA","isCalculation":false},{"id":"f581db9d-c0bd-4c46-88d9-b8c54519709d","difficultyBand":"easy","calculatorUse":null,"totalMarks":2,"questionType":"LA","isCalculation":true},{"id":"f6483f2c-8736-4a80-b892-c92b9cb11bb4","difficultyBand":"easy","calculatorUse":null,"totalMarks":2,"questionType":"LA","isCalculation":false}],"title":"15.1 Forces and springs","topicId":"a2ee170e-f470-5860-be3b-342656a4393c","topicSidebar":"$L3b","topicSlug":"forces-and-springs","topicTitle":"15.1 Forces and springs"}]}],"$L3c","$L3d"]}]

15.1 Forces and springs

Question 2

15.1 Forces and springs Questions

15.1 Forces and springs

Question 2

15.1 Forces and springs Questions