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3.2 Dissipation and efficiency

3.2 Dissipation and efficiency

3.2.1 Dissipation of energy

Dissipation: energy spreads into less useful stores

Definition

Dissipation

Dissipation is the spreading of transferred energy into the thermal energy stores of the surroundings, which makes the energy less useful for further transfers.

  1. Energy is conserved: the total amount of energy in a closed system does not decrease.
  2. During every real transfer, some energy enters the intended useful store and some is transferred to other stores.
  3. Energy that is dissipated is still present, but it is spread among many particles in the surroundings and is difficult to transfer usefully again.

Mechanical processes warm objects and surroundings

  1. When surfaces move against each other, friction acts opposite to the motion.
  2. Work is done against friction, transferring energy from kinetic or other mechanical stores to the thermal energy stores of the surfaces and their surroundings.
  3. The temperature rises because the average kinetic energy of particles in the warmed materials increases.
  4. Air resistance produces the same overall effect because moving objects do work against drag and transfer energy to the thermal energy stores of the air and the object.
Key Idea

A mechanical process becomes wasteful when heating caused by friction or drag transfers energy away from the intended useful store.

Energy becomes less useful, not destroyed

  1. A moving bicycle eventually stops because energy from its kinetic store is transferred by friction in the brakes, tyres and bearings, and by air resistance, to thermal stores.
  2. A filament lamp transfers electrical energy usefully by radiation as visible light, while much more is transferred by infrared radiation and heating to the surroundings.
  3. In an electric motor, electrical energy is transferred usefully to a kinetic store, while resistance in the wires and friction in moving parts increase thermal stores.
  4. In each example, the surroundings cool only by spreading that thermal energy through an even larger region, so the energy becomes still less concentrated.
Example
  • A motor receives 500 J500\ \text{J}500 J of electrical energy and transfers 350 J350\ \text{J}350 J to the kinetic energy store of a load.
  • The dissipated energy is the remainder:
  • Edissipated=500 J−350 J=150 JE_{\text{dissipated}}=500\ \text{J}-350\ \text{J}=150\ \text{J}Edissipated​=500 J−350 J=150 J
  • The 150 J150\ \text{J}150 J is mainly transferred to thermal stores by electrical resistance, friction and sound.

Descriptions must name the transfer and destination

  1. A complete explanation identifies the initial energy store or input, the intended useful transfer, the unwanted transfer mechanism and the thermal store that gains energy.
  2. Write that energy is transferred or dissipated, not that it is used up, lost or destroyed.
Exam technique
  • For a braking question, link the chain directly: friction does work, the brakes and surroundings warm, and energy from the kinetic store is dissipated into thermal stores.
  • When asked why dissipated energy is less useful, state that it is spread through the surroundings and is difficult to transfer back into a useful store.

Common errors change the physics

  1. Do not say friction creates energy; friction transfers energy between stores.
  2. Do not call all thermal energy wasted because heating can be the intended useful transfer in a kettle or heater.
Common Mistake
  • Do not write that energy disappears when an object stops; its kinetic store decreases while thermal stores increase.
  • Do not confuse energy dissipation with a failure of conservation of energy.

Check your explanation against conservation

  1. The sum of all useful and unwanted energy transfers equals the total energy supplied.
  2. Any energy-accounting diagram must therefore have equal total input and total output energies, even when much of the output is dissipated.
Self review
  • What is energy dissipation?
  • Why does friction raise the temperature of surfaces?
  • Why is energy in the thermal stores of the surroundings less useful?
  • Describe the energy transfers when a moving bicycle brakes.

3.2.2 Reducing unwanted energy transfers

Reducing unwanted transfers keeps energy useful

Definition

Lubrication

Lubrication is the use of a substance, such as oil or grease, between moving surfaces to reduce friction and the unwanted transfer of energy by heating.

Definition

Thermal insulation

Thermal insulation is the use of materials or structures that reduce the rate of energy transfer by heating.

  1. Reducing unwanted transfers increases the fraction of the input transferred usefully without creating energy.
  2. The correct method depends on whether the unwanted pathway is friction, conduction, convection or infrared radiation.

Lubrication reduces heating by friction

  1. Oil or grease separates moving surfaces so their microscopic irregularities make less direct contact.
  2. The frictional force falls, so less work is done against friction and less energy enters thermal stores.
  3. Bearings, gears and engine parts therefore run cooler and more input energy remains available for useful motion.
Key Idea

Lubrication reduces dissipation by reducing friction between moving surfaces.

Building insulation slows cooling

  1. Loft insulation traps air and reduces conduction through the roof.
  2. Cavity-wall insulation traps air in small pockets, reducing conduction and preventing large convection currents.
  3. Double glazing uses a trapped gas layer to reduce conduction and convection through windows.
  4. Draught proofing reduces convection by stopping warm air escaping through gaps.
  5. Reflective foil reduces net infrared transfer into an outside wall because its shiny surface has low emissivity.

Thickness and conductivity control the rate

Definition

Thermal conductivity

Thermal conductivity is a measure of how readily a material transfers energy by conduction.

  1. Lower thermal conductivity means less energy is transferred each second for the same area, thickness and temperature difference.
  2. Greater wall thickness increases the conduction distance, so the rate of energy transfer and rate of cooling decrease.
  3. A thick layer of low-conductivity material therefore slows cooling more than a thin layer of a good conductor.
Example
  • Two identical houses have the same wall area and temperature difference.
  • The house with a thicker layer of low-conductivity foam cools more slowly because the conduction path is longer and the foam transfers energy less readily.

Insulation choices have costs and limits

  1. Payback time compares installation cost with the annual saving:
  2. payback time=installation costsaving per year\text{payback time}=\frac{\text{installation cost}}{\text{saving per year}}payback time=saving per yearinstallation cost​
  3. Thicker insulation usually gives progressively smaller extra savings, so cost and available space affect the choice.
Exam technique
  • For a wall question, link greater thickness to a longer conduction path and lower thermal conductivity to less energy transferred each second.
  • Use rate of energy transfer or rate of cooling, not only that insulation keeps heat in.

Keep the mechanisms distinct

Common Mistake
  • Insulation reduces energy transfer; it does not stop it completely.
  • Trapped air insulates only when it cannot circulate freely and form convection currents.
  • Thermal conductivity is a material property, not a temperature.
  1. Lubrication applies to moving surfaces, while insulation applies where there is a temperature difference.
  2. A valid improvement must act on the named unwanted transfer pathway.
Self review
  • How does lubrication reduce unwanted transfers?
  • What does thermal conductivity measure?
  • How does increasing wall thickness affect cooling rate?
  • Give two insulation methods and the transfer each reduces.

3.2.3 Efficiency

Efficiency compares useful output with total input

Definition

Efficiency

Efficiency is the ratio of useful energy transferred by a device to the total energy supplied to it.

  1. Efficiency has no unit because it is a ratio of energies measured in the same unit.
  2. It lies between 000 and 111, or between 0%0\%0% and 100%100\%100%.

Calculate efficiency from energy

  1. Use:
  2. η=EusefulEtotal\eta=\frac{E_{\text{useful}}}{E_{\text{total}}}η=Etotal​Euseful​​
  3. EusefulE_{\text{useful}}Euseful​ and EtotalE_{\text{total}}Etotal​ are both measured in joules (J)(\text{J})(J).
  4. For a percentage, multiply the ratio by 100%100\%100%.
Example
  • A motor receives 800 J800\ \text{J}800 J and transfers 600 J600\ \text{J}600 J usefully.
  • η=600800=0.75=75%\eta=\frac{600}{800}=0.75=75\%η=800600​=0.75=75%
  • The remaining 200 J200\ \text{J}200 J is dissipated.

Rearrange for missing energies

  1. Euseful=ηEtotalE_{\text{useful}}=\eta E_{\text{total}}Euseful​=ηEtotal​
  2. Etotal=EusefulηE_{\text{total}}=\frac{E_{\text{useful}}}{\eta}Etotal​=ηEuseful​​
Example
  • A lamp is 0.180.180.18 efficient and receives 250 J250\ \text{J}250 J.
  • Euseful=0.18×250 J=45 JE_{\text{useful}}=0.18\times250\ \text{J}=45\ \text{J}Euseful​=0.18×250 J=45 J

Power gives the same ratio

  1. When input and output are measured over the same time:
  2. η=PusefulPtotal\eta=\frac{P_{\text{useful}}}{P_{\text{total}}}η=Ptotal​Puseful​​
  3. Use two energies or two powers; never divide energy by power.
Example
  • A heater takes 2.0 kW2.0\ \text{kW}2.0 kW and transfers 1.7 kW1.7\ \text{kW}1.7 kW usefully.
  • η=1.72.0=0.85=85%\eta=\frac{1.7}{2.0}=0.85=85\%η=2.01.7​=0.85=85%

Useful output depends on purpose

  1. Light is useful for a lamp, kinetic energy is useful for a motor and heating water is useful for a kettle.
  2. Other outputs are unwanted for that purpose, even if the same transfer is useful in another device.
Exam technique
  • Identify the useful output first, then divide useful by total in that order.
  • Convert 72%72\%72% to 0.720.720.72 before using it in a rearranged equation.
  • Show the ratio and final decimal or percentage.

Check units and limits

Common Mistake
  • Do not divide total by useful, because that gives a value above 111 for a real device.
  • Do not attach joules or watts to efficiency.
  • Do not add a percentage sign to a decimal unless you multiply by 100100100.
  1. Check that useful energy is no greater than total energy.
  2. Use Edissipated=Etotal−EusefulE_{\text{dissipated}}=E_{\text{total}}-E_{\text{useful}}Edissipated​=Etotal​−Euseful​ when the unwanted transfer is required.
Self review
  • Define efficiency.
  • State the efficiency equation.
  • How is a decimal efficiency converted to a percentage?
  • Calculate the efficiency when 350 J350\ \text{J}350 J of 500 J500\ \text{J}500 J is useful.

3.2.4 Increasing efficiency

Increasing efficiency reduces unwanted transfers

Definition

Efficiency

Efficiency is the ratio of useful energy transferred by a device to the total energy supplied to it.

  1. Efficiency rises when a larger fraction of the same input reaches the intended useful store.
  2. For a fixed input, Etotal=Euseful+EdissipatedE_{\text{total}}=E_{\text{useful}}+E_{\text{dissipated}}Etotal​=Euseful​+Edissipated​, so reducing dissipation increases useful output.

Reduce friction and resistance

  1. Lubricating bearings and gears reduces friction, so less energy enters thermal stores and more reaches the kinetic output.
  2. Ball bearings, smooth surfaces and aligned parts can reduce rubbing and deformation.
  3. Lower-resistance conductors and secure electrical connections reduce unwanted heating by current.

Reduce drag and unwanted vibration

  1. Streamlining reduces air resistance, so less energy is transferred to the thermal stores of the air and vehicle.
  2. Reducing unnecessary vibration limits transfers as sound and heating.
  3. A method improves efficiency only when it reduces an output that is unwanted for the device's intended purpose.
Example
  • A motor receives 1000 J1000\ \text{J}1000 J and initially transfers 650 J650\ \text{J}650 J usefully.
  • ηbefore=6501000=65%\eta_{\text{before}}=\frac{650}{1000}=65\%ηbefore​=1000650​=65%
  • After lubrication, only 200 J200\ \text{J}200 J is dissipated, so 800 J800\ \text{J}800 J is useful.
  • ηafter=8001000=80%\eta_{\text{after}}=\frac{800}{1000}=80\%ηafter​=1000800​=80%

Insulation improves heating systems

  1. Insulation around a hot-water tank reduces transfer to the surroundings, leaving more energy in the water's thermal store.
  2. A lid reduces convection and evaporation, so less energy is required to heat the contents.
  3. Loft insulation, cavity-wall insulation, double glazing and draught proofing reduce transfers from buildings.
  4. Insulation is not always helpful because refrigerators and computers need controlled heat removal.
Key Idea

Match the improvement to the unwanted pathway: friction, resistance, drag, sound or thermal transfer.

Improvements have limits

  1. No real process reaches 100%100\%100% efficiency because some unwanted transfers are unavoidable.
  2. An improvement may add mass, cost, maintenance or manufacturing impacts.
  3. Extra insulation gives progressively smaller savings once transfer through that part is already low.
Exam technique
  • Name the change, identify the unwanted transfer it reduces, then state that a greater fraction of the input is useful.
  • Do not write only that less energy is wasted; identify the destination or mechanism.

Judge changes from evidence

  1. Compare devices under the same operating conditions and for the same useful task.
  2. A measured efficiency increase should match a reduction in unwanted output or an increase in useful output.
Common Mistake
  • Do not claim total energy use falls unless the useful task and operating conditions are fixed.
  • Useful energy depends on purpose.
  • Do not remove friction where grip or braking is useful.
Self review
  • How does lubrication increase motor efficiency?
  • Why can streamlining increase efficiency?
  • How does insulation improve a hot-water system?
  • Why can no real device exceed 100%100\%100% efficiency?

Recap questions

1 of 5

A hair dryer is supplied with electrical energy and its useful output is moving warm air. Some energy is also transferred as sound, so which part is wasted?

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Sankey diagram of an electric motor with 100 J electrical input, 70 J useful kinetic output and 30 J wasted as thermal energy and sound In any device, energy is transferred from one store to another. The useful transfer is the part that does the job we want, while wasted energy is usually dissipated to the surroundings as heating or sound.

A Sankey diagram shows these transfers with arrows whose widths represent the amount of energy. The main forward arrow is usually the useful output, and side branches show wasted outputs.

Energy is conserved, so total input energy equals total useful output plus total wasted output. In the diagram, 100 J100\text{ J}100 J in becomes 70 J70\text{ J}70 J useful plus 30 J30\text{ J}30 J wasted.

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An electric winch motor is used to pull a boat up a slipway. Explain why the efficiency of this motor is less than 100%.

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Why is dissipated energy difficult to use again?

3.2 Dissipation and efficiency Revision Guide

  1. GCSE
  2. /Physics
  3. /3.2 Dissipation and efficiency

Revision notes for Edexcel GCSE Physics 3.2 Dissipation and efficiency: explanations and worked examples.

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