Charge, current and potential difference

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Question 34
Easy

An electrochemical sensor in an experimental glucose monitor is activated.

A charge of 0.084 C passes through the sensor in a time of 24 s.

Calculate the current in the sensor.

Use the equation:

current=chargetime \text{current} = \frac{\text{charge}}{\text{time}} current=timecharge​
[2]

Charge, current and potential difference Questions

  1. GCSE
  2. /Physics
  3. /Charge, current and potential difference