An LED driver in a smart lighting system transfers 780 J of electrical energy when operating at a potential difference of 24 V.
Calculate the total charge that flows through the LED driver.
Use the equation:
energy transferred (E)=charge flow (Q)×potential difference (V) \text{energy transferred } (E) = \text{charge flow } (Q) \times \text{potential difference } (V) energy transferred (E)=charge flow (Q)×potential difference (V)Show your working.
32 exam-style questions on Edexcel GCSE Physics 10.1 Circuits, charge and current, covering 10.1.1 Structure of the atom, 10.1.2 Circuit diagrams and symbols, 10.1.3 Series and parallel circuits, 10.1.4 Potential difference and voltmeters, 10.1.5 Energy transferred, charge and potential difference, and 10.1.6 Current, ammeters and charge flow. Each one has a worked solution and a mark scheme showing where the marks go.