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Question 47

An experimental magnetic levitation sled is released from rest at the start of a test track and accelerates.

The initial velocity of the sled is 0 m/s0\text{ m/s}0 m/s. The acceleration of the sled is 4.2 m/s24.2\text{ m/s}^24.2 m/s2.

Calculate the final velocity of the sled when it has travelled a distance of 11 m11\text{ m}11 m down the track. Give your answer to 2 significant figures.

Use the equation:

v2−u2=2as v^2 - u^2 = 2as v2−u2=2as

where:

  • vvv is the final velocity
  • uuu is the initial velocity
  • aaa is the acceleration
  • sss is the distance
[4]
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5 Forces Questions

  1. GCSE
  2. /Physics
  3. /5 Forces

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