Write x2−8x+3x^2 - 8x + 3x2−8x+3 in the form (x+a)2+b(x + a)^2 + b(x+a)2+b where a a\,a and b b\,b are integers.
Hence, or otherwise, write down the coordinates of the turning point of the graph of y=x2−8x+3y = x^2 - 8x + 3y=x2−8x+3
