A diagram shows a triangle OABOABOAB.
OA⃗=5a \vec{OA} = 5\mathbf{a} OA=5a OB⃗=2b \vec{OB} = 2\mathbf{b} OB=2bP P\,P is the point on AB AB\,AB such that AP:PB=3:1AP:PB = 3:1AP:PB=3:1
OP⃗=k(5a+6b) \vec{OP} = k(5\mathbf{a} + 6\mathbf{b}) OP=k(5a+6b)Find the value of kkk.